中考真题《圆》练习

中考真题《圆》练习

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29(2)஺஺Ḅ2K_5,CEḄ77ஹ(1)Ý}¯°஺8Ë0C.,/0E1BC,.BE=CE.OE=-BC,.NBOC=90஺ZBAC=45°.2(2)|}"JADLBC,ZADB=ZADC=90°.ᵫᢚýÒéAG=AF=AD,ZAGH=ZAFH=90°,NBAG=/BAD,ZCAF^ZCAD,.ZBAG+ZCAF=ZBAD+ZCAD=ZBAC=45°..ZGAF=ZBAG+ZCAF+ZBAC=90°.þ(4AFHG.(3)ᵫ(2)NBHC=90஺,GH=HF=AD,GB=BD=6,CF=CD=4.AOḄx,ᑣBH=GH-GB=x-6,CH=HF—CF=x—4.ᙠRtZ\BCHBH2+CH2=BC2,.(x-6)2+(x-4)2=102.%i=12,X2=—2(,ᔠ⚪/01).AO=12.8ஹ(1)450D=NC=NP.J•:Z1=ZC,•Z1=ZP.7CB//PD.(2)89AC.,/AB0஺Ḅ;4=?,3.BC_3sinP=g••N.AB5D8c=3,48=5.O19⚪Pᓽ஺஺Ḅ;<5.9ஹ(1)Qᙠ4(2)ᡂS஺ᳮᵫ808,U4PḄVW▢YZᑖḄ☢]^_`aPজḄ▢YZᑖḄ☢]

30(3)ᡂS஺cd0ᑖefABஹBCḄᚖhiABஹBCadPஹQ,iᙊadXஹY,U4;klkOPGᐰ`a;klkOQH,Un5V▢YZᑖ☢]^_`aPজḄ▢YZᑖ☢].10ஹপcAfAHᚖ;NSadH,.\ZAHO=90,<,sin67.4°=13AOVOA=13p,AH=12p,TAB஻OS,qBCrOSiadD,7AH=BD=12p,OS_LBCadD,7BD=CD=12p,.BC=24p.(2)ᵫ(1)UOH=5pAB=14p...HD=9pὶ9OB,,//ODB=90°,OB=7F77F=151k(1)tBD=AC=4u4PADvADwxḄ`ῪlkPz{BACḄd.•.{PB=MPCPB=PCBD=AC=4ZPBD=ZPCA.,.!PBD^APCAAPA=PDᓽaPADvADwxḄ`Ὺlk(2)ᵫ(1)U|tBD=4uPD=PA,AD=AB-BD=6-4=2cdPfPE±ADaE,ᑣAE=AD=12VZPCB=ZPAD/.cosZPAD=cosZPCB=PA5D.Ph=y[512ஹ(1)ᵫ⚪/AB஺஺Ḅ;<}AZACB=90,,JCDLCP,D.ZPCD=90ZACP+ZBCD=ZPCB+ZDCB=90,D.ZACP=ZDCB,XVZCBP=ZD+ZDCB,NCBP=NABP+NC4CPABC,D.ZABC=ZAPC,D.ZAPC=ZDAAPCA^ADCB••N7——,9CBCDD.AC•CD=PC•BC(2)tP~ᑮ48{Ḅdu89AP,ீAB஺஺Ḅ;<NAP5=90,D7,ᡝ{ABḄ5d{7{ᡝ8,AP=3P,NPA8=NP34=45,D43=5,,c4fAM_LC7\ᚖM,2ᙠRtAAMCZACM=45,AZCAM=45,D.AM=CM=^^,ᙠRtAAMPAM2^AP2=PM2,D.2PM=2y[l,:.PC=PM+^^=^^°ᵫ(1)|AC•CD=PC•BC,3XCD=PCX4,".CD=^^~223i2(3)ᵫ(1)|:ACCD=PC

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34QN"ó"J-4,ô……ᑖA=n2m.••hõAQḄrm,n,kḄö÷ᨵᐵ.(⚪cøùúûüýþᓽU)Ã7(1)Va,hhõᓽa,hÿᜧ0,/.ah>0.......1ᑖ(:ᜐa/?>0ᡷ1ᑖ,☢ᑖ)V(a-h)z20,a=hᡂ.ᦑ(a-h)'=(a+h)2—4a0....................................................2ᑖ(a+h)'>4ah,.(“+஻%&4.(*)....................................................................................3ᑖah'()(஺+/᮱N4.(-./0ᨎᓽ3)a♦h(2)456PDEFḄ8PD=x,DE=y,ᑣ஺0Ḅ:;<%=•Soo=ᐔNH2+)5....................4ᑖ,S56PDEAxy2c/22\=n"+y)S56஺஺/%4xy22-Ir2_TC(x+2xy+y)-2xyᐔ(x+y)6ᑖ4xy4xyᵫ(1)(*),"+"'>4.-2~n(x4-y)7i_-——--2>—(4-2)4xy4s஺஺ḄᨬDEF2............................................................................7ᑖSᓺHPOEF2iQ(3)s,yḄIᨬD,HiWPDEF'56PDEFḄJ8K

35J86ADBCḄ☢k=S4ABC+S^ABD=ACBC+|ADBDlx2x4mx3ny=9+4n21ஹbco1AB<஺஺Ḅ:;CDVAB.CH='CD=2_2ᙠRtACO/7esENCOH=[-0C2ZCOH=QO°"OA=OC.ZBAO'/CO஻=30஺22,/hEFp஺8ḄehJ.OELABqZOEOZOCED.ZOCE=ZDCED.CE\ᑖ^OCD3ᙊᕜtᑮ:ZACḄvw<3Ḅhᨵ2x.y

36NCMP+NDMC=ZDMO+ZDMC,AZDMF=ZCMO..................3ᑖVZDᡠḄ{FCE,ZCOMᡠḄ{FAC,.•.ND=NCOM..................4ᑖDFFM.".DFM^AOCM..,•=”OCMC.,.FMOC=DFMC.VOB=OC,.*.FMOB=DF-MC..................5ᑖhPᙠOBto᝞1212)cAC,AE.VOP±CE,/.BC=BE=1CE,CP=EP.ACM=EM,:.ZCMO=ZEMO.VZDMF=ZEMO,AZDMF=ZCMO.........................6ᑖz~\`TNCDEᡠḄ{FCAE,NCAEᡠḄ{FCE.AZCDE+ZCAE=180°.AZCDM+ZFDM=180°,/.ZFDM=ZCAE.VZCAEᡠḄ{FCE,ZCOMᡠḄ{FBC,NCAE=ZCOM.AZFDM=ZCOM..........................7ᑖDFFM:.ADFM^AOCM.:..OCMC/.FMOC=DFMC.VOB=OC,AFMOB=DFMC..........................8ᑖ)cVOPICE,/.BC=BE=1CE,AC=AE=#AE,CP=EP.ACM=EM,AZCMO=ZEMO.VZDMF=ZEMO,./DMF=NCMO.........................6ᑖ/CDEᡠḄ{FCAE,.♦./CDE=CAEᦪḄ=ACḄᦪ=180஺-BCḄᦪ.D.ZFDM=180°-ZCDE=180°-18T-BCḄᦪ=BCḄᦪ.NCOM=ᨔḄᦪ.AZFDM=ZCOM............................7ᑖDFFM.,.DFM^AOCM..OCMC,.,•FMOC=DFMC.VOB=OC,.,.FMOB=DF-MC..........................8ᑖ

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