2023年山东省东营市中考数学考前信心卷及答案解析

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24VZPAC=22°,pc2X/.tanZB4C=-77,ᓽ=-p--------------p.,AC5V3X+40-16V3|x=16,BPPC=16,BP=2PC=32,16vi6aᨵᓻ◅.᝞@2,oqḼBOuᔣwxQRPSPOL8஺ᚖGO,ᙠRtAPBD...PD167242
sinN/DÃRn-pg=-=-2"J:.NPBD=45°,:.NQBD=NQBP-NDBP=T2°-45°=27°,ᓽo£8ᜐ¤¥qᓭst27°Ḅuᔣwx©ª«ᐰQ.22.8ᑖÄ᪥GÆÆᐰ᪥ÇȺÉÇÊËÌÍÎ⌱ÐÑ᪥ÒᑖÇÈÓÔÇÈÕÖÇÊ×ØᜩÇÊ×ÚᒹܺÉÝÞßàᡂSâ×Ú.᝞@_᪷²ÓÔäåᑴḄç@⊤.é᪷²@⊤Ḅêëàᡂìᑡî⚪⚣ᦪᑖð⊤ÇÊ×Úᑖñ⚣ᦪ⚣᳛*25⚓ᐳ31⚓

25Añ0«1
9tn8ñlWx<2
180.3Cñ2Wx<3
180.3஺ñ(3Wx<4)n0.2Eñ4Wx<5
30.05(1)⚣ᦪᑖð⊤஻=0.15,n=12,óô⚣ᦪᑖðõu@⊡ᐙà᦮)(2)ùÑ᪥ᨵÇÈ1000úû⌕ýØᜩÇÊ×ÚþO2~×ḄÇÈÿ
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⏨Ḅᨵ(3)ḄEᨵ2ᵱ1᝕ὁ!"⌱$2%&'()*+,-..0ᵨ᪛34ᡈᑡ⊤8ᡠ⌱2ា;&ᵱ&᝕Ḅᭆ᳛.m=\-0.3-0.3-0.2-0.05=0.15,V184-0.3=60,(2)᪷⚪?@AB26⚓ᐳ31⚓

261000X(0.15+0.3)=450(),QAᐰ᪥◤⌕
⏨Ḅᨵ450RS3TU2ᵱᵨA,8⊤YI᝕ᵨC⊤\■,᪷⚪?^_᪛34᝞aA^BCACAB᪷᪛34@Ab@cḄᐳᨵ6efᔠᩩiḄᨵ4e42ᡠjᡠ⌱2ា;&ᵱ&᝕Ḅᭆ᳛;A-16323.S8ᑖTmnopqrᜓt%ᵬஹwxe■z{ᣎ}&~ᢙᕒ()t%5iᵬe■z{4iwe■z{◤⌕2ᐗt%10iᵬe■z{3iwe■z{◤⌕3ᐗ.S1Tᵬe■z{we■z{iᔜᐗS2T▭tᔆ+ᨵxeᫀᫀ&Atᵬe■z{20iḄᑖᢥḄ8ᢚwe■z{ᨵRᫀAxe■z{ᢥḄ9ᢚ¡nopq¢£txSx>20Tiᵬe■z{30iwe■z{.জ8xeᫀḄ§ᵨy©iᦪxḄ«ᦪ)᪆Rঝ0¯°¡nopq¢£⌱±²eᫀ³ᔠ´.)AS1TUᵬe■z{ixᐗwe■z{iyᐗ᪷⚪?µ:·¸¹?»;0,)µ½QAᵬe■z{i2400ᐗwe■z{i2000ᐗR(2)জᫀ&Ayi=2400X20+2400X0.8X(x-20)+2000X30=1920x+69600RᫀA”=(2400.r+2000X30)X0.9=2160x+54000.ঝÁyi=”1920x+69600=2160x+54000,)µx=65RÁyi>”BP1920A-+69600>2160X+54000,)µ:x<65RB27⚓ᐳ31⚓

27Áᓽ1920^+69600<2160x+54000,)µx>65.Átᵬe■z{65ixeᫀ&᪵RÁtᵬe■z{Ḅiᦪ20iÈÉ65i⌱±ᫀ³ᔠ´RÁtᵬe■z{É65i⌱±ᫀ&³ᔠ´.24.(10ᑖ)᝞4ᡠY&Ê«ᦪy=2x-4Ḅ«ᦪ4Ëᙠᙶ᪗Ï©xÐÑÉAÒ©yÐÑÉ8ÒÒḄÓᱥ~⚔Ò஺ᙠ~×A8ØÓᱥ~©xÐḄÙ&ÚÑÒ;C.(1)U஺ÒḄÛᙶ᪗;\Ü08Ḅ☢Þ;S,8SᐵÉáḄ«ᦪ⊤âR(2)8SḄᨬᜧå.)A(1)ÒḄÛᙶ᪗;!⚔Ò஺ᙠ~×Ø:.D(?n,2w-4),•••Óᱥ~Ò.C(2m,0),***OC=2/?i,19/.S=ì2᪷
(-2\+4)=-2m(2),:S=-2%2+4%=-2(w-1)2+2,Áî=1SḄᨬᜧå;2.25.(12ᑖ)ᙠïðñòóᑁòbÉ180°Ḅö÷ø\÷ùúûüýὃÿ
ḄᩭᯠḄᑁ!ᑮ#$᝞&ᡠ()*28⚓ᐳ31⚓

28ᑖᡂIᩭ60ᑖᑖ1᪗Ḽ89AB<3I,II,IIIC=>/@>5Bᔠ<>V᪷EF>BGBNUAC,HIABᑮM#KLMNOPQ1STUVW᪷EḄFXYMNO&Z[\]ᳮ_U`abcTUdᡂ_UF._U)>BGBN஻AC,HIABᑮM,JBN//ACZNBM—ZAQjk9VlmnZSZCBN=ZCQjk9ᑁ┯mnS:NCBA+NCBN+NNBM=180°QpqS.../CB4+NA+/C=180"QnxyᣚSQ2ST|}᯿TUḄḄᑁ\ᑁ!ᑮ#$Ḅ⚔>ᑮ\A8᝞&ᡠ(:`a}᯿TUḄ_UFXYMNO&_U.Q3STᐲḄTUT|ḄmV᝛ᑁᑖ16ᩩk9ᢚᐳ\᝞&ᡠ()*29⚓ᐳ31⚓

29
Tᐲ*ᡂḄᐵ`aᑏM_U.1
_U)>BGBN஻AC,HIABᑮM,".'BN//AC,.ZNBM=ZAQjk9VlmnS/C8N=/CQjk9ᑁ┯mnSVZCBA+ZCBN+ZNBM=\^aQpqS.".ZCBA+ZA+ZC=180°QnxyᣚS.ᦑᫀ
)jk9VlmnZjk9ᑁ┯mnZ2
_U)>0GON஻AC,@BCABD,>஺GOM஻8C,.'.ZNOB^ZA,NODB=NC,•OM஻BC,.ZMOA=ZB,/MON=NODB,,/NAOM+NMON+NNOB=180°,.,./A+/B+/C=180".3
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F._U)•.,ªCMNᢚ«ᑮJ.CH1.AB,ªCMN¬ªFWN,C”Ḅᚖkᑖ9*30⚓ᐳ31⚓

302:.MN஻AB,NCMN=/A,4CDM=NMEA,CD=ME,/.ªCA/D^AMAE(A4S),.CM=MA=MH,VᳮCN=NB=NH,:.MAEMHE,4NBFNHF,"NMHN+NMHE+NNHB=180°,ZA+ZB+ZC=180°.*31⚓ᐳ31⚓