6、一个三角形的另外两边的长.1. 2.B3.解:∵Rt△ADC∽Rt△DBC,∴=,即=,∴DC2=12,则DC=2,∴△ADC与△DBC的相似比为=.4.D .5.B6.70 AC ED 7.解:(1)==.(2)==.(3)==.8.解:(1)∵△ABC∽△DAC,∴∠DAC=∠B=36°,∠BAC=∠D=117°,∴∠BAD=∠BAC+∠DAC=153°.(2)∵△ABC∽△DAC,∴=.又∵AC=4,BC=6,∴CD==.9.C [解析]∵DE∥BC,∴△ADE∽△ABC.∵EF∥AB,∴△CEF∽△CAB,∴△ADE∽△EFC,共3对.故选C.