数学物理方法部分作业答案_姚端正_梁家宝_编著new

《数学物理方法部分作业答案_姚端正_梁家宝_编著new》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

1、Pleasevisithttp://tieba.baidu.com/f?kw=%B4%F3%D1%A7%CA%FD%D1%A7formoreinformation^_^6.21.TTtanBudxCudxtandxu21tttTuuxdxBudxCudxxtttdxuTBuuCxdxxuuutttdx2aubucuuxxttt2.EuEuFdxdxuxdxxttEFuuxdxxuttdx2aufuxxtt3.tkuAdxxdxxtkuAdxHeAdxcAdxu

2、kHuuxdxxteutcdxctDuheuxxt6.Txdxtan21TxtandxuttTxdxuxdxTxuxdxuttl2212Txxdxlxx2122lxuxuttx2大学数学吧~~~~~~~~~~百度Pleasevisithttp://tieba.baidu.com/f?kw=%B4%F3%D1%A7%CA%FD%D1%A7formoreinformation^_^7.2Txdxtan21Txtandx

3、udxutt2TxdxuxdxTxuxdxudxuttlTxgdxglxx2glxuxuuttx9.dIVxdxVxLdxdtVLIxtdVICVIxdxIxCdxxtdtVLILILCVxxtxxtttICVCVCLIxxtxxttt7.11.11?+??u(x,t)=[?(?+??)+?(?−??)]+∫?(?)??22??−??(1)φ=0,ψ=1,11?+??1u(x,t)=[0+0]+∫?

4、?=[(?+??)−(?−??)]=?22??−??2?(2)φ=sinx,ψ=?2,3?+??11?+??21?u(x,t)=[sin(?+??)+sin(?−??)]+∫???=?????????+∗

5、22??−??2?3?−??(3)φ=?3,ψ=?,2?+??1[(?+??)33]+1?+??1[(?+??)33]+1?u(x,t)=+(?−??)∫???=+(?−??)∗

6、22??−??22?2?−??(4)φ=????,ψ=?−1,11?+??−1?−1u(x,t)=[cos(?+??)+(x−at)]+∫???=cosxcosat+[(?+??

7、)−(?−??)]22??−??2?大学数学吧~~~~~~~~~~百度Pleasevisithttp://tieba.baidu.com/f?kw=%B4%F3%D1%A7%CA%FD%D1%A7formoreinformation^_^3.11xatuxt(,)xat[()(xat)]a'()d22axat-11[(xatxat)()][(xa)()]txat22()xta4.2VaVttxx1Vx(,0)AcoskxaCLI1Vx(,0)AkkxsinxtCCL111x

8、atVxt(,)A[cos(kxatA)cos(kxat)]sinAkkx22aCLxat11[cos(Akxat)cos(Akxat)][cos(Akxat)cos(Akxat)]22Akxatcos()2IaIttxxC1Ix(,0)AcoskxaLCLV1xIx(,0)kAsinkxtLL11CC1xatIxt(,)A[kxatcos(Akxat)cos(Akkx)]sin22LLaLxat11CCCC[Acos(kxatA)cos(kxat)]A[kxa

9、tcos(Akxat)cos()]22LLLLCAcos(kxat)L大学数学吧~~~~~~~~~~百度Pleasevisithttp://tieba.baidu.com/f?kw=%B4%F3%D1%A7%CA%FD%D1%A7formoreinformation^_^5.vvvxuu,,x2xxxvvxxx22vuxx23xxx2vavttxxvuttttxvxt(,)6.222xuxu11122xhxahtvttuttvhxlet,vhxuu

10、hxvhxxvux2hx