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1、极限证明(精选多篇)第一篇:极限证明极限证明1.设f(x)在(??,??)上无穷次可微,且f(x)??(xn)(n???),求证当k?n?1时,?x,limf(k)(x)?0.x???2.设f(x)??0sinntdt,求证:当n为奇数时,f(x)是以2?为周期的周期函数;当n为偶数时f(x)是一线性函数与一以2?为周期的周期函数之和.xf(n)(x)?0.?{xn}?3.设f(x)在(??,??)上无穷次可微;f(0)f?(0)?0xlim求证:n?1,????n,0?xn?xn?1,使f(n)(xn)?0.sin(f(x))?1.
2、求证limf(x)存在.4.设f(x)在(a,??)上连续,且xlim???x???5.设a?0,x1?2?a,xn?1?2?xn,n?1,2?,证明权限limn??xn存在并求极限值。6.设xn?0,n?1,2,?.证明:若limxn?1?x,则limxn?x.n??xn??n7.用肯定语气叙述:limx???f?x????.8.a1?1,an?1?1,求证:ai有极限存在。极限证明(精选多篇)第一篇:极限证明极限证明1.设f(x)在(??,??)上无穷次可微,且f(x)??(xn)(n???),求证当k?n?1时,?x,limf(
3、k)(x)?0.x???2.设f(x)??0sinntdt,求证:当n为奇数时,f(x)是以2?为周期的周期函数;当n为偶数时f(x)是一线性函数与一以2?为周期的周期函数之和.xf(n)(x)?0.?{xn}?3.设f(x)在(??,??)上无穷次可微;f(0)f?(0)?0xlim求证:n?1,????n,0?xn?xn?1,使f(n)(xn)?0.sin(f(x))?1.求证limf(x)存在.4.设f(x)在(a,??)上连续,且xlim???x???5.设a?0,x1?2?a,xn?1?2?xn,n?1,2?,证明权限lim
4、n??xn存在并求极限值。6.设xn?0,n?1,2,?.证明:若limxn?1?x,则limxn?x.n??xn??n7.用肯定语气叙述:limx???f?x????.8.a1?1,an?1?1,求证:ai有极限存在。极限证明(精选多篇)第一篇:极限证明极限证明1.设f(x)在(??,??)上无穷次可微,且f(x)??(xn)(n???),求证当k?n?1时,?x,limf(k)(x)?0.x???2.设f(x)??0sinntdt,求证:当n为奇数时,f(x)是以2?为周期的周期函数;当n为偶数时f(x)是一线性函数与一以2?为周
5、期的周期函数之和.xf(n)(x)?0.?{xn}?3.设f(x)在(??,??)上无穷次可微;f(0)f?(0)?0xlim求证:n?1,????n,0?xn?xn?1,使f(n)(xn)?0.sin(f(x))?1.求证limf(x)存在.4.设f(x)在(a,??)上连续,且xlim???x???5.设a?0,x1?2?a,xn?1?2?xn,n?1,2?,证明权限limn??xn存在并求极限值。6.设xn?0,n?1,2,?.证明:若limxn?1?x,则limxn?x.n??xn??n7.用肯定语气叙述:limx???f?x
6、????.8.a1?1,an?1?1,求证:ai有极限存在。极限证明(精选多篇)第一篇:极限证明极限证明1.设f(x)在(??,??)上无穷次可微,且f(x)??(xn)(n???),求证当k?n?1时,?x,limf(k)(x)?0.x???2.设f(x)??0sinntdt,求证:当n为奇数时,f(x)是以2?为周期的周期函数;当n为偶数时f(x)是一线性函数与一以2?为周期的周期函数之和.xf(n)(x)?0.?{xn}?3.设f(x)在(??,??)上无穷次可微;f(0)f?(0)?0xlim求证:n?1,????n,0?xn
7、?xn?1,使f(n)(xn)?0.sin(f(x))?1.求证limf(x)存在.4.设f(x)在(a,??)上连续,且xlim???x???5.设a?0,x1?2?a,xn?1?2?xn,n?1,2?,证明权限limn??xn存在并求极限值。6.设xn?0,n?1,2,?.证明:若limxn?1?x,则limxn?x.n??xn??n7.用肯定语气叙述:limx???f?x????.8.a1?1,an?1?1,求证:ai有极限存在。极限证明(精选多篇)第一篇:极限证明极限证明1.设f(x)在(??,??)上无穷次可微,且f(x)?
8、?(xn)(n???),求证当k?n?1时,?x,limf(k)(x)?0.x???2.设f(x)??0sinntdt,求证:当n为奇数时,f(x)是以2?为周期的周期函数;当n为偶数时f(x)是一线性函数与一以2?为周