上海金山2023年高考仿真卷数学试题含解析

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2023
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g'(x)>l-co5x>0,ᡠ!ᦪ"(x)ᙠR%ᓫ'⌴).x>0,ᑣ/(+>/'(0)=0,x<0,ᑣ"(x)("(0)=0,ᡠ!ᦪ/(ᨴḄᓫ'⌴)/01(0,+9),ᓫ'⌴4/01(-8,0),ᡠ/(%)ᙠx=0ᜐ89᩽;<
=>ᔠ⚪A
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g'(x)<-1-cosx<0,ᡠ!ᦪ"(x)ᙠR%ᓫ'⌴4.Ex>0,ᑣ/(x)"(0)=0,ᡠ/(x)Ḅᓫ'⌴4/01(0,+8),ᓫ'⌴)/01(-8,0),ᡠ/(%)ᙠx=0ᜐ89᩽ᜧ<
>ᔠ⚪A.ঞ-g2aᓽg'(x)<0,ᡠ!ᦪ"(x)ᙠ(0,x0)%ᓫ'⌴4
ᡠ/'(x)ᔠ⚪A

18P%ᡠQ
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mno⚪.21.(I)C=j,(H)SMBCEO,t)ூk᪆௃(I)᪷wcos?A-cos?5=J^sinAcosA-Gsin5cos3,ᑭᵨ9ᑮ1+c°s2A1+c°s2'=3sin2A—gin26,ᵫ9ᑮsin(2A-᧡]=sin(2B—,ᯠ᪷w2222I6JI6J!ᦪḄឋjk.(II)᪷w(I)ᵫᳮ9ᑮ3=/-ah,ᑭᵨ⌕=9ᑮᯠᵫ=,arsinejk.ூk௃(I)cos2A—cos2B=sinAcosA-GsinBcosB>iJ+cos2Al+cos2BG.6.…ᡠ--------------------------sin2A----sin2B,2222>/3...cos2A>/3cos26——sin2A-------=——sin28-------,2222sin[2A-^=sin[2B-^.2A—£=28-£ᡈ24—£+23—£=4
6666A=BᡈA+3=-^
᪗b,ᡠ4+3=^ᑍᡠc=,,3(II)ᵫᳮ9§c2=a2+b2-2abcosC,ᡠ஺2+/=3+஻/?22ab)ᡠ¨43,©ªa=88«,

19¬b,ᡠa஺3,ᡠ=—absinc=4-0,®2ூUV௃X⚪Y⌕ὃ\
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/(+=x2-1...........3ᑖ¸G(X)=3(X—×(X—1)2,áᔠ/(x)^G(x)ᙠ(0,1µ%âãÆä
åɲ!ᦪḄâãᙠ(0,1µ%ᨵɲçU
ᓽ\W)Mx)ᙠ(0,1µ%éUḄ²ᦪ1.........................5ᑖ(ᡈᵫêë/(x)=G(x)ᙠ(0,1µ%ᨵÉ᪷Æ9)3(1)Ꮇ¸³ᙠíᦪae(-2,«ïo),J9g(x)µX+4a¹xe(a+2,-K»)ឤᡂô,x+lnx<—x+4஺2ᑣõ,¹xe(a+2,+o஺)ឤᡂô,(1X…43-x2+ci2—|x+2஻+47f஺<—x+4஺I2)2Inx——x<4aᓽõ2,¹xw(a+2,+oo)ឤᡂô..................................6ᑖ(ù+2)(ù-*>0জ¸H(x)=Inx-,x,(1)=~~~2=2-x2xßH'(x)>0,902,"(%)⌴4,

20:.H(x)]=஻(2)=In2-1,1ax[n2]Ova+2<2ᓽ2VQvO4a>ln2-l,a>—----)Va<0,e4ᦑae(,()1,<4஺£(஻+2,+00)ឤᡂ#,8ᑖa+222ᓽaNO”(x)ᙠ(a+2,+oo),⌴.H(x)0xe(a+2,+oo)ឤᡂ#ᑣa+22a@”A1,2]..........11ᑖᵫজEঝF2.ᦑGᙠHᦪae(-2,+oo),JFg(x)