江苏省某中学2022-2023学年化学高三上期中联考模拟试题（含解析）

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2022-2023
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9N2+O2=2NO,;ᙠ=ᘤ?ᐙᐭHe,=ᘤ'BCᜧEᱥᡂᱥHIJKEL⌮ḄO᳛QJKEᦑB┯TC⚗EVWXYḄZ[\YḄ6moiL“^⏚`Eᔣᘤ?bᐭcYḄCuSChdeEZfg⏚hᡂhE᪀ᡂiᵯkiᳮEbmnᓄ+O᳛EpᡂqrḄYJcEᦑC┯TD⚗EstᔠᡂvwxyE⌱ᵨ450࠷Ḅ|I}X$~wnᓄ᳛E~wnO᳛EᨵᵨḄ|I⌕~ᙠ450C`ᓄᑺ6:ḄᓄᦔᨬEᦑDL஺3ஹDூ4ᫀ᪆௃ᱥḄYHIḄ^⏚⏚EQ~Wᐗ⏚EḄH,ᦪYE^⏚~⏚EᐰᵯE⏚~¡⏚E¢ᑖᵯEᡠde?HI^⏚ᜧ¥⏚஺ூ⚪§7௃A⚗ஹb¨©100ª«E^⏚deḄpH¬ᜧ2ᔜᓫ¯E⏚~¡⏚Eq°HIKEPHᜧ¥^⏚EᦑALB⚗ஹஹ'BEHIᙳw0.1molL’Ḅ^⏚⏚²"de?E⏚~¡ᵯ³ᙠᵯ´⊝Ede?Ḅq°HIK¥^⏚?Ḅq°HIEᡠbᐭZ`E^⏚ḄO᳛⌕m¥⏚EᦑBLC⚗ஹ;¶'BḄ²deᑖ·fHIḄNaOHdeា?E^⏚ᡂ¹ᓄºEdepH=7,⏚ᡂ⏚ºE⏚º»depH>7,ᑣ½?ឋ`E⏚$ᐰE¿ᨵ^⏚ὑḄNaOHde'Bᜧ¥⏚ECLD⚗ஹ'BEHIᙳw0.1molL’Ḅ^⏚⏚²"dedᱥḄYEQ~Wᐗ⏚EZnᡂᕒEᦑD┯T஺ᦑ⌱D஺ூ4ᫀÁÂ௃Ã⚪ὃÄn¡ᵯḄᵯ´⊝ᵨE¨©`de?°HICᓄḄᑨÆஹ⏚Çា?ḄÈdeÉ?ឋḄiÊᑖ᪆~4ḄᐵÌ஺4ஹDூ⚪§7௃A⚗ஹᙠÍÎḄÐÑÒZᙽ~ÔᡂZiᵯkEÕÖ×ØZÙÚ᩽EÜÝ'EᦑA┯TB⚗ஹᙠÍÎḄÐÑÒZᙽ~Þᱨ□᩽Ḅ▢᩽ÜÝâEᦑB┯TC⚗ஹ'ÙiᵯkḄL᩽Eᵯ᩽wO2+2HO+4e=4OH-,ᦑC┯T2D⚗ஹZᙽÙiᵯkḄÚ᩽EZᜫᵯ°äᓄᡂZ°Eᵯ᩽wZn-2e-=Zn2+,ᦑDLᦑ⌱D஺5ஹCூ⚪§7௃A.CrOs?³ᙠ2\äÌஹ1Cr=OÌEᡠ4Oi°É-1åஹ1Oi°É-2åEᡠCrᐗæÉ+6åEᦑA$⌱B.\äᓄç?äᐗæḄᓄᔠåᨵ-1åEᓄᔠåᓣᑮ஺åEᡂärE4CrO5+12H+=4Cr3++7O2f+6H2஺

10
ᦑB⌱()0()c.᪀ᨵᐳ"#$ᨵ%&#ᦑC⌱1/\|ooD.'(ᓄ*(ᐗ,Ḅᓄᔠ"ᨵT"0-2"-1"Ḅ(ᨵ12ឋ4⏚ឋKMnO6789⁐ᦑD⌱ᦑ⌱;C«6ஹBூ⚪?@A௃A.MgOᰚDEᵯAG◤⌕JᐸᰚᓄὑMᜧᑴᜓMgQRᵨᵯAᰚTMgCLUV(ᓄ╅ᦑA┯B.XᔆZᵨ☟ᵯ◀]^_Vᑭᵨabc&Ḅdᵯឋe◀ᦑBfgC.hᶭjᵨḄ“l⚶”ᐸᡂᑖVq⏚lrstḄᡂᑖuvw⏚┛ஹwᓄ┛ᨵᦔᡂᑖVvw⏚┛ᦑC┯D.ᔣ{|ᐭ~4{|ᓄM◀{|Ḅw%&ஹ┛%&ஹ╅%&M4{|ᓄᦑD┯ᦑ⌱B஺7ஹCூ⚪?@A௃Fe,஺,ឋ(ᓄᐹᨵឋᑴᢣᓭ┐ḄḄ⌕ᡂᑖVFe?஺”Cᫀ⌱C஺8ஹAூᫀA᪆௃Gὅ78w%&ᱥḄu0.05mol,ὅ78w%&ᱥḄu0.05mol,ᑣᔠ8஺ḄᱥḄu(Mmol,ᔠ78bu100mLCtḄᱥḄu1mol/Lᦑ⌱A9ஹDூᑖ᪆௃A.t0,¡¢£¤¥ᐸ|A¦ᱥ¡Vℍ⃔¥B.©ªᑖ&ᙠ10000«jḄᓄᔠᱥuEᑖ&ᓄᔠᱥC.¬ᨵ®0¯®Ḅᨵ°ᱥM±ᓄ
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11dED┯Tᦑᔠᳮ⌱⚗~D஺ூ4ᫀÁÂ௃Ã⚪ὃÄᨵêᱥë᪀ឋEìᱥ%ᨵḄíîïᐸfឋᐵñ~4Ã⚪ḄᐵÌEòóôõCឋ^᪆ö·Ew4᧕┯Á஺10ஹDூᑖ᪆௃᪷ùúûEüå°ᙠýþᵯ᩽ÿᑮᵯᓄᵯ᩽▢᩽ᑣAᵯ᩽Bᵯ᩽ᵯ᩽□᩽஺ூ⚪௃A.᪷"#$ᑖ᪆ᵯḄA᩽᩽ᦑA)*B.+ᵯB᩽,-ᵯ᩽□᩽᪷"./0ᙠ□᩽#ᜫᵯ3456ᵫ5GOH),ᵯ᩽8H2O—e-=H++'OH,ᦑB)*C.ᵯ3ḄH2O2+Fe2+ᡂḄ456ᵫ5(OH),ᵫ./:;<=HO-e=H++OH,Fe3++e-=Fe2+,2O+2e+2H+=HO2ᑣH2O2+Fe2+=Fe(OH)2++OH,Fenton?H2O2+Fe2+=Fe(OH)2++OH,ᦑC)*22D.D.@Aὑ1molOz,C4moiᵯ᪷"H2()2+Fe2+=Fe(OH)2++OHDEC1molᵯᡂImolOH,ᡠGHᡂ4moiOH,ᦑD┯J*Kᫀ⌱D஺11ஹDூ⚪௃OᬀQḄᑖ8Cl8H27NO3RᨵTḄUVWᨵ⏚Yஹ45ஹZY3[*OᬀQ\R]]^YV_`RᨵZYV0*+OᬀQ\]]^YaḄ],-Ḅ◀acd᜜f᜜ac0WᑖgHCpp,h~jஹacWk,lᑣmᙠno᪀ᦑABC)D┯J஺Kᫀ⌱D஺ூKᫀqr௃sᨵtᱥRᨵv45

12ூᫀDÉ௃Ã(ᓄqM4Ê|ᡈ⏚ឋE═⏚Í789⁐ÎVÏuÃ(ᓄqḄrsឋUVÃ(ᓄqḄ12ឋÃ(ᓄqrsឋḄᱯDuM0ÑÒ78ᨵ⁐ᱥᓄᔠᡂÓÔḄÕ⁐ᱥ஺13ஹCூᫀA᪆௃Aஹ1ᑖ&ℍ⃔¥¬ᨵ5Ö¯®Imolℍ⃔¥×ØḄÙ
M¦2.5molH2,AfgBஹagÚÛb¬ᑖ&ᦪub,ᑣÝÛbḄ©ªᑖ&VÞ᝕ÏàegÝÛbḄᱥḄV2ᑣᙠ᪗âãḄbubaNAbe——molx22.4L/mol=(22.4bc)/(aN)L,BfgCஹJImolCLäᐭᑮ|æᑖwÛ×|
ᡂÆ⏚0vwA⏚ᑣ᪷èw2&éឤêN(HClO)+N(Cl-)+N(CKy)V2NA(N⊤ìc&ᦪ)C┯DஹNa2(h0Na2sḄ©ªᑖ&ᙳV78,▢□%&ḄÖᦪðñᙳV1:2,ᙳ¬ᨵ38Ö&ᡠ©òḄNa2(h0Na2sóbᐹᨵ©òḄ▢□%&ᦪ0&ᦪDfgᫀ⌱C஺14ஹDூ⚪?@A௃A.ᓫô×|
ᡂHF0(Ûõᨵö⏚ᦑA┯B.ôᓄ╅V%&ᓄᔠᱥᵯ&fgᦑB┯C.M÷øḄᱥ÷ÓÔùèúûᦪèᑖ᪆üÓÔឋýþuMgl24)3/ymoL᪷1Mg2*ஹAl2*+ឤ:x+2y=0.1,᪷1SO/-)*+ឤ-x+3y=0.2-0.075,ὶ5:x=0.05ஹy=0.025»╅7Ḅᱥ:Ḅ;ᑖᦪ/50%,>?$:;ᑖᦪᦑA┯Bஹ"#@Mg2+ஹAF+ាBCDEᐰ!Ḅ"#/Na2s"#᪷1SCV-)*%Na+)*+ឤGn(Na+)=2n(Na2so4)=2(HSO)=2x0.1Lx2moi•I24i=0.4mol,ᡠKLᐭNaOH"#ḄNO/V(NaOH)=0.4mol/lmolL-l=0.4L=400mL,ᦑB;Cஹ&ᔠᱥ/O.lmoLᐸ@╅Ḅᱥ:Ḅ;ᑖᦪ/a,ᵨ100mL2moi/LS⏚"UVWᐭ450mLimol/LXYᓄ["#ᡠ"#\A1(OH)3CD]^_ᡂḄXYᓄaᐰb%XYᓄ[cdeᔠB⌱⚗Gvi=400mL,VWᐭ50mLimol/LXYᓄ["#ᡠA1(OH)3CDEᐰ"gXYᓄ[_ᡂha⏚[A1(OH)3+NaOH=NaAlO2+2HO,A1(OH)3ᨬᜧkl0.05moLᓽ20

13qr?½⚪ὃ¿.ÀÁÂᔠᱥḄÄÅ,Æᔠ⚪ÇÈÉᜧ⚪ᐵY?Ì)@Í.ÀḄᓄÎஹ=⍝Ðqx⊤ḄRÒÓ¡\¡ÔḄᡂᑖÆᔠÕÖ8×ᨵᐵØ⚪ÙÚᑖ᪆஺⚪ᢈÜ?ÝឤßàᙠᓄÎÄÅ\ḄᵨÕ஺⚪áâÎḄᑖ᪆VãÓᓄÎÄÅVã.×.Àᑖ᪆⚪Ḅ⚪åæ?ÇqC⌱⚗D⌱⚗᧕┯q஺16ஹCூ⚪௃A.éê⏚×Ḅ3ᱥNO,A┯J*B.ᵯ₹kÝឤ:2Fe3++Fe=3Fe2+,B┯J*C.AL(SO4)3Áí0ᡂ(NHQ2SO4ÁA1(OH)3,ÕÖ8?AP++3NHH2O=A1(OH)31+3NH4+,C)*3D.NazSKh<¡ឋîïᑏᡂNa+ÁSiCh5D┯J஺Kᫀ⌱C஺17ஹBூ⚪௃ᵨILlmol-UNaOH¡ᔾᦈ0.6molCO2,ᡠó3ᱥᨵNa2cO3ÁNaHCCh,ôCCh?-ÁHCOjḄᱥÔḄöᑖgxஹy,÷I]x+y=0.6mol,2x+y=lLxl.0mol/L,óx=0.4mol,y=0.2mol,l¡\øȤùᱥÔḄö¤ùᑣᡠó¡\ḄCCV-ÁHCO3-ḄᱥÔḄöøȤùú0.4mol?0.2mol=2?1,ᦑ⌱B஺18ஹCூ⚪௃sᱥÔ+ûüýᨵµþᡂÌᑖ\Rᨵ-OH,ᓽ
4CḄḄᐗᱥᵨḄ஺4CḄᐳᨵ᪀ᐳᨵ8ᐗᱥᐳᨵ4ᐗᱥᐳᨵ12ᦑ!ᫀ⌱C஺19ஹDூ⚪'()௃A.+ᙠ-./01ᡂFe3O4,ᦑA34⌱5B.67-.891ᡂNaO,ᦑB34⌱522C.╅ᙠ;./01ᡂM&N2,ᦑC34⌱5D.+ᙠ<./=>?41ᡂFeCb,ᦑ⌱D஺20ஹBூ⚪'()௃A.ᵨ@AজCᑴ250mL0.1mol.IEḄNaOHFGNaOHHI34JᙠKLMᑁF)>JᙠOᑁF)F)GPᓾRSTU4
VᐭKLMA┯Y5B.ᵨ@Aঝᑴᜓ\LFe(OH)2HIᙠ]^_᛻ᑁab■d1ᡂḄFe(OH)2eF)Ḅf./Ḅ02-ᓄBh5C.ij⏣l4m⏚ឋKMnChFGp⁐ᵨ@AঞᑴsḄjt/uvᨵj⏣ᡠx34yzjtḄ1ᡂC┯Y5D.ᵨ@Aটᑴ\Lj⏚j|}~1᎔ᔾiGG☢D3h஺ᦑ⌱B஺21ஹDூᑖ᪆௃A.pH=lḄ⏚/0.1mol-L1,᪷n=cV5

14B.⏚᪷ᙠFG/ᙠ)⊝ᙠᵯ⊝5C.᪗<¡Ḅ¢᝱3¤.I34mᵨ᪗Ḅ.I᥅¦I§;mND.6ᙠᱥ/ᓄᔠª+1ªᔠ஺7rMNAூ⚪'()௃A.lLpH=lḄ⏚/®ᨵḄᱥ¯ḄL°0.1mol-L^xlL^.lmol,®ᨵO.INAH+,ᦑA┯Y5B.lL0.1mokL“NaHC03FG/®ᨵ0.1molF¯⏚6i⏚᪷±ᑖ)ஹ±ᑖᵯᑣHCCh-ᦪµO.INA,ᦑB┯Y5C.᪗¶¢<¡·¸<ᵬº3¤.I22.4L<¡·¸<ᵬºᱥ¯ḄL3¤Imol,ᦑC┯Y5D.23g6Ḅᱥ¯ḄLImoLImolNaᐙᑖ0ᱥ/6Ḅᓄᔠª¤+1ªᑣ=>
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VᵯᦪNA,ᡠxDh஺ᦑ!ᫀ⌱IK22ஹCூᑖ᪆௃j⏚ᐹᨵ⏚ឋ7⏚½ஹ¾¿À1Áᑖ)=>j®ᨵÂÃÀ1-ᓄ=>xÄ)!Å⚪஺ூ⚪'()௃A.ὅÇFÈᨵÉÊËÌ34␺ÎᦑA┯Y5B.j⏚ᐹᨵ⏚ឋ7NaHCChFG1ᡂ.IjÂ7NaHCChFG3=>␺ÎÏÐÑÒÏᓫᦑB┯Y5C.¤bḄᫀÔmᵨCuSO,NaOHFG◤ᐜ1ᡂ-ᓄ×ᯠÙ7j⏚À1/=>ÚyjÂ◤⌕89ÑÒÜÁᩖᦑCh5D.mᵨpHÞßj⏚ᐹᨵ⏚ឋmpHÞßàjÂ34mpHÞßà␺ÎÏᓫÑÒÏÐᦑD┯Y°!ᫀ⌱C஺ஹá⌱â⚪·ᐳ84ᑖºClCHC!23ஹᵬã+2CLä+2HC1=>a—CHO3Na274aCl—^y-OCHOூᑖ᪆௃AḄᑖåC7H8,ᨬçᔠᡂèéÃãᵬ⏚|ᵫiÄAᵬãᑁ°ᵬãᙠ+Òëᓄᑺᩩîã_

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2129ஹA1O+3C1+3CMa2A1C1+3COSO32+CI2+H2O=SO?+2C1+2H+◀äFeCh;2373Fe3+3OH=Fe(OH)1AP+4OH=[A1(OH)]'96%34ூ⚪௃(1)᪷ᑴᜓA1C13ḄçèÂr!aᵫéᓾᘤ{ᩭḄíᨵCOnCL,coZîᓄ᮱.ḄᡂᱥaðCLZñḄaîᓄ᮱.Ḅᓄpqr
ALO3+3CL+3C᦮2AlCb+3CO(2)Na2s03CLIᓄóaNa2s03ôóᑺöIᓄ
Na2s04,CLôIᓄᑺa÷Ḅøqr
dSO2+C12+H2O=SO42+2C1+2H43(3)ᓣúᘤ.û⌕AᨵA1CLnFeCb,◤SᐭýAl,þᐹᨵ
ឋᐸᵨ◀ᩖFeCb;(4)জAlCb(ᩖFeCb)NaOHᑮḄ!"Fe3++3OH=Fe(OH)I,Al3++34OH=A1O+2H2OᡈAl3+4OH=[Al(OH)]';24ঝ&'ᱥ)*+ஹ-.ஹ/ᓾஹ12ᑮḄ0.32g345ᓄ7,n(Fe2Ch)=0.32g4-160g/mol=0.002mol,ᑣn(FeCb)=0.002molX2=0.004mol,m(FeCl)=0.004molX162.5g/mol=0.65g,ᑣAlCbḄ"16.25g-0.65g3=15.6g,AlCbḄ:;"15.6/16.25X100%=96%஺