2021年湖北省高考化学冲刺试卷（附答案详解）

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2021
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⏚◀(4)ᑖ᪆ᘤAஹBḄᑖᑖ!ᧅஹᙊ$%&F'(ᴻ*+ᑮ-./Ḅ0ᵨ(5)2345678ᐰᑖ:;ᡂḄᓫ>7ᙠFᜐ./AB(6)᪷RFG34SᑴUVᑣ7;ᡂSC"XᨵYZ[ḄH\]^OḄᡠHᐵ`Ḅa0Sᑴb34Ḅcd4஺¶⚪ὃvᱥ>Ḅᑴᜓrs¸ᫀ¹º6ὃ»¼⚪½6⚣ὃ¿ÀÁὃvÂ;ÃÄᔠ[ᵨஹ᪷RrsÅḄ\ᱥ>Ḅឋ>ÇÈᑖ᪆ஹrsɶa0ÊË\rs¸ᫀ¹ºÊËÄᔠឋÌÍÎÏÐÑᱥ>ឋ>H\Ò⚪ÅFGḄÓÔᵨÕ4EÖ஺18.ூᫀ௃Û1750.6A25<ூ:᪆௃:(1)᪷Ràáâã2x(জÛঝÛঞx2){ᑮLᓄ¸èéCH(g)+42NO(g)=CO(g)4-2H20(g)+N(g)AH=2x(-890.3-674-41x2)kJ/mol=222-1750.6kJ/mol,ᦑᫀ:-1750.6(2)ù{ᙠúûMüᑁᙠUû34}NO?Ḅÿᓄ᳛400஺(2ஹ50(TCᓄ᳛ᨬᜧᜐ⊝᝱ᨵᑮ⊝ᓣᓄ᳛!⊝⌮ᔣ$%A.()200*+,-ᨵᑮ⊝ᔣ.,-/01ᢝᙠ200456+7NO2Ḅᓄ᳛;ᜧ19%,ᦑA.ABB.bE,-ᔣ.,-/0eᜐ⊝᝱GEᦑbEḄv(⌮)CH4ஹp஺Ḅqrsᑖug0.2mol-2L,0.8m஻L,0.8mol}2~~==25Bg200*+,-Ḅ⊝SᦪK=64.8,ᡠYᓣKa⊝ᔣ⌮,-ᔣ$%ᡠYH<0Bᦑeᫀgh25B

21(1)᪷:2x(জ—ঝঞx2)CH4(g)+2NO(g)=CO(g)+2HO(g)+222N(g)h2(2)(gᙠR+7ᑁᙠQRNo2Ḅᓄ᳛40(rcஹ50(rcᓄ᳛ᨬᜧᜐ⊝᝱ᨵᑮ⊝ᓣᓄ᳛!⊝⌮ᔣ$%A.()200+,-ᨵᑮ⊝ᔣ.,-/0hB.bE,-ᔣ.,-/0eEg⊝᝱BC.cஹdQR⊝SᦪQRBD.Vᜧ,-ᱥqXYZ[,-\᳛¢ᐸ¤ᱥ¥Ḅᓄ᳛¦`abc,-\᳛`᠒B(3)ᙠ300஺(h+jklm,-ᑮ⊝+CO2ஹH>CH,ஹH2OḄqrsᑖug0.2mol-2Lஹ0.8mol-L-^0.8mol-L-^1.6mol-L_1,K=©1ª▲¬300࠷®200࠷+C(CO)C4(H)22Ḅ⊝SᦪKḄ¯ᑨ±,-ḄaH஺²⚪ὃµ,-¶Ḅ·¸ஹᓄ¹⊝Ḅº»¼ஹᓄ¹⊝Ḅ·¸½¾¿ὃµ¹kᑖ᪆ÁÂஹÃ(ÁÂÄ·¸ÁÂ᪷⚪ÅÆÇÈᔠஹÊËᱯᑡÎᳮஹᓄ¹⊝ÐÑÒ½ÓÃÔeÕ⚪Ö)½஺19.ூeᫀ௃0.02387ூÔ᪆௃Ôhজ600k+ᙠÛÜg1LḄឤÛÞßÛᘤ)ᐙᐭ2moiäåA,ᑣ,-ᱥAḄçèq“(A)=2mol/L,⊝+ë.=v⌮ᓽk.•c(A)=5•c(B),ᑣ⊝SᦪK=ὶ=]600K+ᵫ⊤ñXÓk.=32min-\k⌮=8minT,K=^=4,ôAḄᓄqgxmol/L,ᑣAஹBḄ⊝qᑖug(2-x)mol/Lஹxmol/L,ᵫ⊝SᦪK=E=4,Ôx=1.6,ᑣÕ+q(A)=0.4mol/L,c(B)=1.6mol/L,ᵫ2.31g,”=t/-XoZXU.4+oXl.o(32min_1+8min-1)t,Ôt=0.023min,ᦑeᫀgh0.023Bঝ,-Ñ+7ôAḄᓄqgymol/L,ᑣAஹBḄ⊝qᑖug(2-y)mol/Lஹymol/L,A,Bq½,ᓽ2-y=y,Ôy=l,ᑣÕ+.(A)=q(B)=lmol/L,ᵫ2.31g3=(32min-1+8min-1)t,Ôt=0.0115min,ᑣüÑ+7ᑁ.,-Ḅ32X1+8X1ᙳ,-\᳛v=•I\"/ஹ«87mol(L-min),0.0115minᦑeᫀgh87oÿ22⚓
ᐳ26⚓

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$ᐭK3x,ᓽᑮ⊝Ct(A)ஹc(B),5$ᐭ2.31g67
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(AḄ)ᓄ+ymol/L,᪷)ᓄ,-./0ᓄ1&,ᦪ-.AஹBBḄ
5᪷A,BC/3y,ᓽBḄCt(A)ஹc(B),5$ᐭt=(32mm-1+3t,ᨬA᪷v=E&'F?@ᑁ3ZX1+oX1AtḄᙳI᳛஺K⚪ὃMᓄ1I᳛N⊝ᦪḄ&'Nᵨ
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f1gḄhi&'jk⌕mno஺CH320.ூeᫀ௃CH=CHCH_^CH-Cstuvஹwxy$z{232COOCHj(CH)CHCHO+2CU(OH)&(CH)CHCOOH+CuOI322322+2HOHCH=C{CH^COOH+nHOCH^H^H22ᓟ_᫥//2O0-CH=CH2|ᓄᑭ}~COOCHcHOH1z©-CH2cH2OH3-CH2CH஺/0H4-O-CH-C4rOHOHCH5>CH2cHeOOH46

23CH3c-L
C+ூ3᪆௃3(1)XḄ᪀b+CH2=CHCH3,FḄ᪀b+__(•.IJnCOOCHj(CH)CBrCOOH,CᨵḄj+tuvஹwx,32CH3ᦑeᫀ+CH=CHCHJ_(H-cJ-<¡uvஹwx;23<9IJnCOOCHj(2)BHuv£¡uvy$gᡂCஹD⏣§x¨gz{gᡂE,ᡠ«B-C+y$ஹD-E+z{
ᦑeᫀ+y$=C(CH,i)COOH+nllOCHyCHjOH¸>¹+(n—¼COOCHcHOH1z1)HO,2ᦑeᫀ+(CH)CHCHO+2CU(OH)3(CH)CHCOOH+CuOI+2HO3223222½nCH=C[CH)COOH+nHOCH>CHVH-•-FCHj-C+(-23+nCOOCHcHOH1z1)HO<2(4)C^(CH)CBrCOOH,¿0t$À⏚CḄÂᑖÄ᪀Å
᝞ÇÈÉ᪀+C>C>C>32COOH,Êuvᨵ2Ë᣸ᑡ®b({◀ᐸKÐ)
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CH,ᵫH66Þ24⚓
ᐳ26⚓

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⁐ᨵ⛳XḄᩩḄ21#$UXḄ&ᑖ()*42,X./(0ᦪ==3…6,ᑣXC3H69ᨵ⛳ᡠ;ᐸ=᪀?@CH?=CHCH;XCDEF(1)ḄIJDᡂA,3AMᑴOᓄQRSTCDOᓄIJDᡂB,BCDVWIJDᡂC,CCD
IJᯠY⏚ᓄDᡂD,᪷]DḄ=᪀?@^A(CH3)2CHCHO,B(CH3)2CHCOOHஹC,CH3-CI(CH)CBrCOOH,DCDbcIJDᡂHCI-DCDdeIJDᡂE32H3CnCHg3CH=C(CH)COOH,F^_L(lH-c;Gy¥r232COOCHjCOOCHcH0H1z??H4-O-CH—C-h-OHH4-O-CH—C4r<)H(5);wxy/ᧇᔠᡂᓄᔠᱥi.CH,ᵫH66OHCDbcIJᑮwxyCDᡂIJDᡂwx⏣wxCHCHCOOH2CDᓄOᓄDᡂwxwxHCNCDᡂIJᯠY⏚ᓄDᡂ

25OHCH2CHCOOH°⚪ὃᨵᱥᔠᡂὃᑖ᪆ஹ^ᔠJᵨᑭᵨ=᪀?ஹIJᩩ⚪EFᔜᱥ)=᪀?@
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