2021年广东省高考化学热身试卷（附答案详解）

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2021
ḕ᫥ὃᓄᔁஹᓫ⌱⚪ᜧ⚪ᐳ16⚪ᐳ44.0ᑖ1."#$
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1|4mL0.02mol/LKMnO
4_2mL0.2mol/LW/HCO,
5mL0.5mol/LNaAO,
5mL0.5mol/LH2SO4
ÙÚÙটA.ÔÕজᵨ@|ᡂ§Ḅ᳛B.ÔÕঝßàá⁐â᠒äåæ3çst᳛ḄèéC.ÔÕঞßàUëìíî☢ḄðᑨòNa_ÙstḄᦔtD.ÔÕটßà()õöḄâ᠒äå÷3çst᳛Ḅèé5.ᑭᵨø□]ᑖÙᑴ§úᐝ0.02molÙ5ᑡkº9:Ḅ;A.|ᡂᵯḄûSü0.02gB.|ᡂ§Ḅýᦪü2.408x1023ÿC.
ᡂḄ0.224L᪗D.
ᡂḄᳮ0.04molNa
ᵯḄ6.WஹXஹYஹZᙳᕜᐗ"#$%&#'(Ḅᨬ*+,ᓄᱥ/Ḅᓄᱥ0123ᙳOOlmol•LTḄpH45678ஹ569ᦪḄᐵ<᝞>ᡠ@஺&ᑡCDEFḄGA.ᓄᔠᱥX2I2JKᨵ᩽ឋᐳ+P4Q᩽ឋᐳ+PB.RᓫT᝱VᓄᱥḄWXYឋZY>ZC.Rᓫ[678ZZ>Y>W>XD.\]^ᐗ"J#ᐗ"XḄ_`ឋᨬa7.bᓄc
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,ᓄB.01JH+ᔣGaNᵯ᩽uvC.iVᑣᡠ§ᵨḄÉᘤlG2A.ÕÖB.×C.ØÙÚYÛD.mÉᘤᙳl11.ᙠ01J#ROb4MM+s
ZRO5-+3Mn2++3HO=R'+3MnO122+6H+,ᑣROᔆJRᐗ"Ḅᓄᔠ+456ᨬ᜜ßᵯ6ᦪᑖàA.+4ஹ6B.+7ஹ7C.+5ஹ7D.+5ஹ5

312.áₐ"ã᪀RÙ᝞>GₐåḄæ⌕èឋᡂᑖ#ᐹᨵᢙ,ᓄஹᢙëஹ◀íîᵨ஺FᑡCDJEFḄGA.áₐ"0#᧕0ᨵð0ᑺB.áₐ"NaòVTC.áₐ"lóô,ᓄD.áₐ"JõYᐳË☢56ᨵ12÷13.ᵫ&ᑡõYl{ãḄG⌱ABCD⚗12þ#ÿ
|_NaBr|_2NaiDûN&Br01ḄüᳫjXT—►eft■■fpB§k(I/HQJr2mLRKNa-JwO.IffAgCIজᳫᐜ"#⁐&ঝᳫ%&'"⁐%&*+,ឋ.(0ᓄឋ.23.456ឋ.Na2c஺3>)Cl>Br>IAgCl>AgBr>AglOSi222NaHCO3A.AB.BC.CD.D14.7ᵯ9:;<Ḅ>?@ABCDᐕF᣸HḄI>᪗K᝞M⊤ᡠP஺QẆST>CM+ᜐᳮḄᨬXpH,Y5Z[\ḄT>ᑖ^ᵨ30%ḄNaOH`⁚pHb8.5ஹ9ஹ9.5ஹ10ஹ11,☟e'ᑖ᪆ghijᐗlḄm\no(p᝞qᡠP஺r▅tᧇv⊝I.CU(OH)+4NH[CU(NH)]2++20H-xv⊝H.Cu(OH)+2334220H-U[Cu
OHy4]2z,Mᑡ}~Ḅy⚗T>>?᣸H᪗KpH1.069Cu2+/mg-L-172<0.5NH^/mg•L2632<154⚓ᐳ25⚓

4A.T>CM+ᜐᳮḄᨬXpHQ9B.bc.pHᓣCu(0H)2Ḅ\v⊝Iᔣjᐗlm\gᓣC.cd.pHᓣc(OH-)v⊝I⌮ᔣjᐗlm\MD.d'c(OH-)jᐗlm\gᓣ15.᛻¡ᩭ¡£¤¥7ᓄ¦§¨Q©ª᛻I«¬tḄᑭᵨ᳛°±ᔆஹ³´ᔆஹᵬ⏣ᔆ·¸ὶᔠ஺ᐸ¼⌕¦¾᝞q.(FeTi()3TiQ+4¿MᑡÀÁḄ()A.ÂÃÄÅᨵ“ᵯ2”ஹ“³ᓄ”ÉB0ᓄÊËÌÍB.“³ᓄ”ÎÏÐὑ36gᯖÓᑣÕ7moiᵯÖC.“ᔠᡂ”ÌÍ0ᓄᑺÙÊËᑺḄᱥ?Ḅ\ÛÜQ1.1D.gÁÃÄ“Mg,Ar”ᵨ“Mg,CO?”ÝÞ16.25ßÎᔣlLO.lmol/LḄzᐗ⏚HR⌲âãᐭåæ(çè25éÎz>ᔠåḄᵯêv⊝ëᦪQK=1.76x10-5),ᢝḄî3ï&ðñᔠḄpHÙòÖó3ÜôḄõᦪᓄᐵ÷᝞qᡠP஺MᑡÀÁ┯ùḄ()A.25ßÎO.lmol/LḄzᐗ⏚HRḄᵯêv⊝ëᦪQKa=10-5B.ãᐭO.lmolåæÎc(NH[)>c(R-)>c(OH-)>c(H+)

5C.c(R-)=c(HR)ÎQ⏚ឋD.HRQú⏚25஺(.ÎḼåæḄãᐭü᪗⌲âᜧþஹÿ⚪(ᜧ⚪ᐳ3⚪ᐳ42.0ᑖ)17.C(ᑏVc)ḄᑖC6H8஺6,⏚ឋᙠᡈឋᩩ"#᩽᧕&'ᓄ஺)*+,-./012ᨵ45ḄVc,+,671Vc289500mg/L஺:ᓄ;<=>?ᵨABCDB:EFGᒹI671VcḄ28JKLMᡂOPQR஺(1)OPSḄT஺(2)OPUᳮT⏚ឋᩩ"#C6H8஺6W&12'ᓄC6H6஺6஺ᑏXYZ[Ḅᓄ;\]To(3)OPᵨET2.00x10-3mOi.^I᪗`aஹ2moic⏚ஹdeஹᢣgᑺஹiᘤ(ᶍ)஺ᐸ1ᢣgᑺ⌱ᵨo(4)OPopTজrsiᘤTrs⏚ABt஺ঝvwiᘤTᡠᨵiᘤᵨdevyz◤ᵨ|Ia}vḄiᘤ~஺ঞIaTᔣ⏚ABt1ᑖᐭᓃ᪗`a.67a☢ABtᜐ஺ᢥ⌕᦮a☢Xᦪ஺ট67TABtX10.00mL67┵1ᐭ10mL2moi/Lc⏚.ᦪAᢣgᑺ஺ঠABTᵨ᪗`aABᓽ஺¡¢AB3£஺(5)ᦪ¤¥¦§ᜐᳮTজMᡂOPᦪ¤¥¦⊤©(ª«ᑏXḄᦪ¤¬®X)|D612᪗`aAB7£ᦪ¯°/mL123¡ᙳ²³6⚓ᐳ25⚓

6ঝᦪ¤ᜐᳮABµ¶ὑ12᪗`aḄ¯°¡ᙳ²10.00mL஺ᑣ|D671VcḄ28mg-^1஺Â6ÄÅÆজDBÇ-ᩭÉÊGᒹI67ÂËᑏ“Wª~”ஹ“ÎB~”ᡈ“Ï~"ÄÑᜩᯠ67஺ঝᑴ⌼ᖪ×Y67µWªØᵨḄÙC~ÂËÚÛÄ஺A.Ýᜩᯠ67ÞßB.ᔣᜩᯠ671áVcC.ãäᜩᯠ67D.ᵨ.ᐸæUᧇèᔠᑴê18.:Ẇí>Î2îïðÂñ8òᑖ>ᡂT40.5%ZnO,19.8%CuOஹ5.7%FeOஹ7.3%F”஺3.5%MnO,ᐸSiO?ᦈ⏚"#15%ḄH2sO4⏚*+Ḅ,ᫀᐸ./0᝞2ᡠ4"5ᑖᩩ8ᶍ:;<=>?⏚ḄᓄA>Zn"OH2ZnCO»3⏚;<5ᑖFGHIᓄᱥK>LMNOPQᐰNOḄpH᝞T⊤ᡠ4:FGFe2+Fe3+Cu2+Mn2+LMNO6.51.54.27.8QᐰNO9.73.26.710.4"1ᑏ./0`ᑺaஹbḄᓄA>:a:eb:oফ“◀ᩖ”k0lmᡂᑖᨵFe"OH3ஹMnO,SQqr⁚Ḅuv:2◀═xyḄFGxy,0>:“◀ᩖ”k0zI{ᵨ}~ᜧ0k

7(3)ᙠl.Omol•LZnS()4+ᔜK᝱(ZM+)Ḅᦪ(lg[c/mol•L])+pHᓄḄᐵ᝞2ᡠ4:;:,N+⌕¢ḄᓄA>vo(5)£=>?⏚¤¥ᑖ¦§¨ᑮᐹᨵ«ᓄឋḄ®ឋIᓄ§ᵨ¯«ᓄ°±²ᵬ⏣ᔠᡂ?⏚¶ᵬ·(DMC)Ḅxy஺=>?⏚ᑖ¦¹Iᓄ«ᓄ®ឋᨵº»¼½¾¿ᑖ¦¹ᜧ¯600ÀÁᡠᑴIᓄ®ឋTÃḄÄÅvo19.᯼Ç⌕Ḅ#Èᩖ¢ᨵH2sPCSzஹCOSqᨵÊÈ᯼ÇËÌ#Èᩖ¢~ÍᓄᡂSO2ÎÏÐÑᜧÇÒÓ஺᯼ÇH2sḄῃ◀0;ᡂᐸÕÖḄº×Ø⌕ᢣ᪗ῃ◀᯼ÇH2sḄ,ÛᨵÜÛῃÈÝÛῃÈᐸÝÛῃÈḄÄᳮvᑭᵨNa2cO3+ᔾᦈH2sâᡂNaHS,ãäºåæçÇIᓄᡂNa2s2O3஺èéTᑡë⚪:(l)Na2s2O3ḄᓄAíî஺(2)ῃ◀᯼ÇCOSḄ,Ûᨵï2ḄKOH+IᓄÛஹᵯñÄÛP{¦Ûq஺জCOSḄᑖGó᪀²CO2õöCOSḄᵯG>஺ঝᵫ2ḄKOH+£COSIᓄÈ⏚ù?⏚ùḄFG,0>:úᜧûüCOSḄÍᓄ᳛(þ“ÿ”ஹ“”ᡈ“”)oঞImolᓄᡠ◤Ḅ᝞ᓄH—HC=0C=SH—SC=0E/kJ-molT4367455773391072%&'COS)*Ḅ+,-.(g)+COS(g)=H2s(g)+CO(g),5+,Ḅ4H=kJ-mol-1oটᵨ=ឋa-AI2O3BᓄCOSCDḄ+,-COS(g)+HO(g)UCO(g)+HS(g)F222H<0,HIᢗᧇLஹHIMNᙠBᓄᑺ⊤☢SᶇHIUVUWᙠHIḄUVᑁY8⚓Wᐳ25⚓

8\]I^_COSḄ`ᓄ᳛(bcd⊝)᝞f1ᡠghi^_WcosḄd⊝`ᓄ᳛klḄᐵn᝞f2ᡠg஺n(COS)ᵫf1rWBᓄᑺ=ឋᨬᜧUu,Ḅ^_v-hᵫf2rWPxUd⊝yᦪK=(|ᶇ2}ᨵᦔᦪ)஺(3)ᦈᜐᳮ᯼SO2ḄᵨCᐜSO2`ᓄ-NH4HSO3Wᐭᐸᓄᡂ(NH4)2S()4஺᯼SO2◀᳛Ḅᨵ()஺a.¢ᜧC£_b.¢ᜧ᯼ḄM¥c.ᓣ^_d.¢ᜧ¨©ªஹ«⚪(ᜧ⚪ᐳ1®⚪Wᐳ14.0ᑖ)20.°±²³ᑴᜓᢙ·¸ᱥḄᓄº'ᧇ஺ᐸ³ᔠᡂ¼½᝞(1)BḄ¿À-h°±²ÁᨵḄÁÂÿÀo(2)A-BḄ+,ÄÅhCḄÆ᪀ÈÉ-o(3)ᑏ%EtFḄᓄÎÉ______oO(4)FḄIᑖÐ᪀ÑWÁᨵW"ஹ^஺Æ᪀NCDÔᱥ-Õ✏⏣ḄØᐳᨵ³

9,ᐸ᪶ÚᐳÛÜÝᔾᦈßᨬàḄᑖáÆ᪀ÈÉ-஺O0HIIHCN(5)CH,—C—H'ãCH—C—Hä᯿æçMÎWèCH?=CH_CN0HI(:--'ᧇᔠᡂCHᔆ1ߟCH,,ëìᨬÈᔠᡂ¼½஺CNY10⚓Wᐳ25⚓

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11ூB᪆௃BGA.ᵨ£¤⏚¦§¨ᴻᓄ*ª#«RGSiO+4HF=SiFT+2HO,ᦑA242CDᵯB.rs:ᵨᵯB¸ᑴ╅ᓄ*ª#«RGMgC12(ᰚÁ)ÃMg+CkÅᦑBCDC.NazOz^É+,ÊNaz஺2ËᓄᑺÌ|tᑺÉḄᐗKQ{஺2ᑖÍ3180,18஺,Ðᙠ0H-CDḄÒͪ#«RG2HÓO+2Na2()2=20Ô+218OH-+4Na++0T,ᦑC┯2D.£ᓄÖ×Ø☄xÚᓄ*ª#«RG4Fe(0H)+0+2HO=4Fe(0H).ᦑ2223DCD஺ᦑ⌱GCoA.ᓄấ^£¤⏚+,%ᡂߤᓄấÉB.ᵯBᰚÁàᓄ╅%ᡂ╅àC.Ð+,"ᓄáËᓄᑺÌ|tᑺÉḄᐗKQ{18஺,ÐᙠOH-D.£ᓄÖ×^É+,%ᡂ£ᓄ×஺W⚪ὃZ[ᓄ*ª#«Ḅâᑏ_Dᱥ(Ḅឋ(+,(B⚪ᐵg⚪hijᜧ஺4.ூnᫀ௃CூB᪆௃BGA.,Ðᵨᑖäåᧅᔲᑣ%ᡂḄéêë⚠åᧅ⍎ᦑA┯B.îïðñ⏚òḄójôõ⁐ôöᔠ÷ᑴQ¸,øùðú⏚òój`ôᵨôójḄ₝⏚ᩭüýᦑB┯C.á^+,þᜧÿᑁ
U☢☢ᓣᦑCD.ᨵ!"#$%&'(ᑨ*"+ᓄ-./0᳛2345/6ᑴ89ஹ";<ᩭ>?"+ᓄ-./0᳛Ḅ23ᦑD┯Bᦑ⌱DCoA./ᵨᑖIᧅDB.LᨵM$%&N#OP═⏚SḄ;<T⁐VᩭW;<;Xᔠ6ᑴ%&(C.U#Z☢[P\]Na`aḄ./bD.ᨵ!"#$%&஺V⚪ὃfᓄ-gᫀḄijkP⚣ὃmnob./!ᔾ./ஹᓄ-./0᳛23459qᓄ-./rᳮ!ᢈuḄὃfvwxyzḄ{Ḅឋஹ}~Ḅ12⚓ᐳ25⚓

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ᐳ°<³<¶ᨵ·¸Ḅ¹▲ᦑBpqC.NalᨔY»\ᨵ<᝞ᦋḄ᪶¾¿"ᐳ°<ÀKÁᙠÃᨵ<Äᨵᐳ°<ḄŵᦑC┯qD.NalᨔYiᓄᔠᱥ᝞ᦋḄ᪶¾¿"ᐳ°ᓄᔠᱥÀ"ÆÇᱥKiÈᔠᱥᦑD┯஺ᦑ⌱SBoA.ᨔY\ᨵ<¯\ᨵᐳ°

15ூ᪆௃ᙠRO"+3Mn2++3H2஺=R-+3MnOI+6H+-./01232ᵯ₹6ឤḄ9:;<n=1,ᑣᙠ-RO1,RḄᓄᔠBC+5BR0F-RᐗHḄᓄᔠBIJKCᨬMNB᪷Pᱥ-R-/0ḄᓄᔠBRSᑨU᪷PVᡂX/0;NaHCO,ᦑAN233B.VᡂḄÚ-Ûᨵܤܤ¦ᓄKIVᡂỚᑣI¡᣸◀ܤḄI¡á¦ᓄឋBraு"ᦑB┯´C.ÜᓄåÓæçèIéᙠAgBrஹAglìíḄ±ᓄI¡îËïpAgBr>Agl,ᦑC┯´D.VᡂḄÔ¦ᓄÕ-ÛᨵÜᓄ£I¡îËÕ⏚Ḅ⏚ឋấ⏚óᑣI¡îËôõöឋ:e16⚓ᐳ25⚓

16C>Si,ᦑD┯´஺ᦑ⌱AoA.জ-ÊËÌÍÎÏËIঝ-ÑVÒÓÏËVᡂÔ¦ᓄÕ¤B.I¡᣸◀ܤḄC.ÜᓄåçèIéᙠAgBrஹAglìíḄ±ᓄD.VᡂḄÔ¦ᓄÕ-ÛᨵÜᓄ£஺y⚪ὃ|ᓄ}ù1ᫀḄúBCM⚣ὃ½¾¿ᱥḄឋஹᐗHᓄᔠᱥ<ûஹùÍÎஹùᢈ¡CḄᐵ¯ÃÄᑖ᪆»ù¡ÆḄὃ|~ùḄúBឋᑖ᪆⚪:Iᜧ஺14.ூᫀ௃Bூ᪆௃ூᑖ᪆௃y⚪ὃ|ýᵯ¬⊝Ḅÿᑖ᪆ᑨஹᓄḄᳮᵨẠ⚪ᐵ⚪஺ூ௃A.!Ḅᓄ"#$%pH=9&'()*ᨬ,-.C1+ᜐᳮḄᨬ0pH129,ᦑA456B.b7c89:;᪷()*=ᜧ╄᪷()@:;᪷()AᔠCᡂE.ᔠFFG*=ᜧCU(OH)+4NH[CU(NH)]2++20H-,H⊝4ᔣKLMN'ᐗPQ2334=ᜧᦑB┯S6C.c7d89:;᪷()*Ḅ=ᜧCU(0H)+4NHU[CU(NH3)4++2OH-⌮ᔣK23L'()*V,'ᐗPQWXᦑC456D.dYZ[9c(OH-)=\H⊝H]Cu(OH)2+20H-=[Cu(0H)412-4ᔣKL_`aN'ᐗḄPQ$b_ᓣᦑD456ᦑ⌱]B஺15.ூᫀ௃Bூ᪆௃]A.hij“ᵯ”ஹ“nᓄ”ஹ“ᔠᡂ”ZoTiCl,@MgḄpᙳrᙠᐗᓄᔠtḄᓄuvw;ᓄxypᦑA┯S6

17B."nᓄ"C}ᓄ2C°Cp22FeTiO3+6C+7ck2FeC13+2TiC14+6CO,ὑ36gᓽ2=3molᯖὑnG23.5mol,}3.5molx2=7molᵯ)(LNg/1I1O1ᦑB456¤ᓄᑺC.“ᔠᡂ”pCO@¦pCᡂCH4O,p¨j©2co+2H23CH4OᑣCO2;ᓄᑺ¦2xyᑺ;ᓄᑺ@xyᑺḄᱥ¬ḄQ®21]2,ᦑC┯S6D.Ar@Mg³pᡠZAr$Zᵨµ¶·GMg@CO2pCᡂC¸MgO,ᡠZ³bᣚᡂCO?µ¶·GᦑD┯S6ᦑ⌱]Boᵯ⛳¸¼½.Cᡂ:GஹnGஹNaOH,¿ÀÁḄÂÃÄÅÆᜐᳮÇᐭnᓄ᮱ஹ\ᐭᯖÊᐭ;ᓄᑺCkCᡂCOஹTKI4¸FeCbCO¸ᵯᔠᡂᵬ⏣ᙠArGiᵨMgxyTiCLjÐᑮÒvTiZÓh⚪஺Ô⚪ὃÖᱥ¬ḄᑴᜓÙÚ2ÛὃÜÝ⚪ÞßijCḄpஹ;ᓄxyp2Ḅᐵàáᑖ᪆@ÙÚbâḄὃÖãäᐗᓄᔠᱥ%åஹpyᳮ@ÙÚḄAᔠ⚪³ᜧ஺16.ூᫀ௃Dூ᪆௃]A.æc(R-)=c(HR)&Eឤᗞ=஺Eᐗ⏚HRḄᵯ(H⊝Üᦪ2ì=,íî=c(H+)=10-5,ᦑA456B.ÊᐭO.lmolFG&ὅាòóᐰpCᡂNH4Rᵯ(H⊝Üᦪ((HR)C(H+),Aᔠᵯ₹ûឤÐ2c(NH6)>c(R)ýᐸ.jÿ
ᡠᙠc(NHi)>c(R-)>c(Ofr)>c(H+),ᦑBC.c(R-)=c(HR)
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ᦑC+D.-./0123⊝5ᦪ/0
ᑣ8/ᯅ=:;/0
ᦑD┯=lc(UHKh(HK)ᦑ⌱+D஺A.c(R-)=c(HR)
Tg⊇=஺
Bᐗ⏚HRḄᵯE3⊝5ᦪFKa=IJK=c(H+)B.LᐭO.lmolQR
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18H0),ᑣ12e.NHt

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ᡠᡃØ◤⌕ᑖþÿ:12᪗ᦪ/mLᦪ/mLᦪ/mLὑ/mL110.00210.00310.00ᙳ10.00ᦑ!ᫀ#:12᪗ᦪ/mLᦪ/mLᦪ/mLὑ/mL110.00210.00310.00ᙳ10.00ঝᵫC6H8஺6+12=c6H6஺6+2Hl+n(Vc)=n(I)=10.00mLx10_3L/mLx2.00x210-3mol/L=2x10-5mol,ᑣ;VcḄ=>#"i஺”*.='lO.OOmLxlO3L/mL3.52x102mg/L,ᦑ!ᫀ#:3.52x102@(6)জBC;Vc=>D500mg/L,EF352mg/L,ᡠHIJKᩭMNEOᒹQRSFTᜩᯠNᦑ!ᫀ#WRSF@ঝX#352<500,ᑴ⌼ᖪ]^_`Nabcdᜩᯠᡈὅᵨbhᐸjkᧇmᔠᑴo,ᦑ!ᫀ#WCD஺(1)᪷q⚪stuvᓄxyz{|}ᵨ~vOᒹQ;VcḄ=>;(2)⏚ឋᩩNC6H8஺6R12ᓄ#C6H6஺6`]ᡂHI;(3)᪷qỚᓫ⍗ᑮᑖ᪆@(4)জᵨ⌕Fᔲb@20⚓Nᐳ25⚓

20ঝ⏚¡¢ᵨQ£¤N¥{¦§@ঞ©᦮☢N◤⌕☢ᙠ¯°±“0”H²2³3mL,´ᢥ⌕¶©᦮·☢N¸ᦪ@ঠº»N⍗ᑮ12ᕈ⁐@(5)জᡃ¿◤⌕12᪗NᓽR+ὑḄNᡠHᡃ¿◤⌕ᑖÁÂW/mLHÃᙳஹᦪஹὑḄ@ঝ᪷qÅÆC6H8஺6+I=C6H6஺6+2HlὑḄỚḄᱥḄ>nQ)=n(Vc)ÈÉNÊ2ËÌÈÉᑣ;VcḄ=>@(6)জBC;Vc=>D500mg/L,EF352mg/L,᪷qÍὅᑖ᪆@ঝX#352<500,ᑴ⌼ᖪ]^_`Nabcdᜩᯠᡈὅᵨbhᐸjkᧇmᔠᑴo஺Î⚪ὃᱥ=>ÐÑNÒÃᓄÓkḄÔᵨNᐵÖF×kᳮḄᳮÙN⚪ÚÛÜὃx]ÐÑSÝஹÈÉSÝ.18.ூ!ᫀ௃ZnO(ᡈZn(OH)2)Zn3.2³4.2Mn2++HO=MnOI+2H+Fe3+,MnO2222àᓄ{஺2áâã]ᑖÙäÔNὑå஺2æç3.16x10-172Zn2++4HCO3=Zn(OH).ZnCOI+3C01+H0è⏚éᑖÙê°ëìNᓄíḄ⚩ïᜧNñò2322☢¥{NóôàᓄᑺḄyឋூÙ᪆௃ÙW(1)᪷qöÆᑖ᪆R÷øᑺaᵨù©⁚ḄpH,ûüSýᐭᩖ
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pH%⁚Ḅ893.2:4.2;ᵫ*+Mnᐗ=MnOz>?@ᙠ
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ᦑᫀ3.2:4.2;Mn2++HO=MnOI+2H+Fe3+,MnO2Mᓄ%஺2\]^_222ᑖPCD
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gpH=7h,c(Zn2+)=10-25mol/L,lg(3.16x10-3)=-2.5,ᦑc(Zn2+)=10-2Smol/L=3.16X10-3,K[Zn(OH)]=c(Zn2+)xc2(OH-)=3.16xsp210-3x(10”=3xio"16

21ᦑᫀ3.16X10T7(4)s⏚uvw⏚HxCD_ᡂy?w⏚uz{FᓄwஹSஹs⏚x
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ᦑᫀ2Zn2++4HCO3=Zn(OH)-ZnCOI+3COT+HOs⏚2322(5)ឋFᓄuMᓄᑺ
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⚪ÆåW#஺19.ூᫀ௃sès⏚é$C0COS+4Br+120H-=CO"+S0î+8BL+26HOñ+8150࠷0.048ad2ூP᪆௃P(l)Na2sO,9s⏚é
/÷øùNa2s2O3sès⏚é
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22ᦑ2ᫀ4+84টQR*15(TCS,COSḄ/ᓄ᳛ᨬᜧ,USVᓄᑺXឋᨬᜧ8ZCOS[\Slmol/L,COS(g)+H0(g)=CO(g)+HS(g)222]\(mol/L)1300/ᓄ(mol/L)0.30.30.30.3^⊝(mol/L)10.72.70.30.3C(CO)XC(HS)_0.3X0.3MK=2X0.048,`JC(COS)XC(HO)0.7X2.72ᦑ2ᫀ4150࠷80.0488(3)bcdeᓄfᙠ(hi+᝞-.k᯼mciSO?n◀᳛+,$ᜧbpḄq*,ᓣ.R*+csḄ()*tu+$ᜧk᯼mcḄvw+x>ᐙᑖᔾᦈ+⌱⚗ad+ᦑ2ᫀ4ad»(l)Na2sO4f⏚+UNa2s2O3Ḅᓄ8(2)জCO2ḄᵯsCOS,ᵯs᪀,᪷deᓄḄᑖḄᵯ,COSᵯ8ঝCOSBr2K0HᡂCOgஹS0ஹBL0;$ᜧ&'+$ᜧ()*+ᑭcsḄᔾᦈ8ঞ:=;Ḅ=;>-ᡂ;Ḅ=;>8টQR*15(TCS+COSḄ/ᓄ᳛ᨬᜧ8ZCOS[\Slmol/L,COS(g)HH20(g)UCO2(g)+H2S(g)]\(mol/L)1300/ᓄ(mol/L)0.30.30.30.3^⊝(mol/L)0.72.70.30.3ᑣ᪷K=c);(3)bcdeᓄfᙠ(hi+᝞-.k᯼mciSO2n◀᳛+,$ᜧq*+$ᜧec+ᓣ.R*+csḄ()*tu+$ᜧk᯼mcḄvw+x>ᐙᑖᔾᦈ஺£⚪¥ᔠὃ¨ᓄ^⊝Ḅ+.⚣ὃª+«¬ὃ¨Ḅᑖ᪆>®ஹ>®+¯°±²ᱥ´Ḅឋ´+:Ḅµ¶^⊝Ḅ+⚪·¸*i஺20.ூ2ᫀ௃(1)¼½¾8¿ÀফÂᡂ8

23ভ58^2/cooc,,=CH2=CH-CHS^-CHB-CHOH-mᑖª>AHমoHCN??CNூ)᪆௃)4AḄᑖC6H6,¼+ᙠVᓄᑺᩩÇȽᯋÊÂᡂᡂ0-CH=CH,,ᔠEȼᵬÌḄÍᱥḄ᪀,+¼½¾ÈHC1ÊÂᡂᡂCOÍ(8”,cÊp)ᡂD,DÊVᓄeᓄᡂCl0H00H0EC-CH,EȼᵬÌᙠÏឋᩩÇÐᡂCH-CH-CᨬÑÊ32Ònᡂ¨ÓÔ+µU)2Õ⚪஺(1)ᵫ᪀×,B¼½¾+¨ÓÔØᨵḄØeÚ>ÛÜÀ+ᦑ2ᫀ4¼½¾;ÝÀ8(2)AȽÞÊÂᡂᡂ¼½¾+Cᦑ2ᫀ4Âᡂ8CI)ßà.Cl(3)Eᱥ´ᙠ0H-áᙠSȼᵬÌḄᓄOᦑ2ᫀ:0(4)FḄãᑖä᪀si+Øᨵ-᪀åp)Íᱥæ✏⏣Ḅé+êḄãᑖä᪀sᦪ·ìíæ✏⏣+æ✏⏣᝞Øᨵ1î«ï+ᨵ-CH0HCH3ஹ-CH2cH20Hðñ+᝞Øᨵ2î«ï+,-CH2OHஹ-CH,ᨵòஹóஹê3ñ+ᐳ5ñ+ᐸi᪶öᐳ÷ø3ùᔾᦈúᨬûḄᑖ᪀×஺COOCIL஺?CH,,ᦑ2ᫀ45M24⚓+ᐳ25⚓

24COOCIL^A-CH,OH(5)µCH2=CH-CH3üᧇᔠᡂCHj—(j—CHஹ+,ᵫCH2=CH-CH3ÈpÊÂᡂCN2-þ⏣+eᓄᡂþÔ+þÔÈHCNÊÂᡂ,ᡂ·᪗ᱥ
ḄCH=CH-CHCH3-CHOH-CH>233oHCN?H,CHT-CH,T55CNCH=CH-CHCH3-CHOH-CH3>23HᦑᫀoHCN-7஺CH/-&-CH,ᓄCH-C-CH.CN⚪ὃᨵᱥḄᔠᡂ
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