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1、第1章习题及解答1.1将下列二进制数转换为等值的十进制数。(1)(11011)2(2)(10010111)2(3)(1101101)2(4)(11111111)2(5)(0.1001)2(6)(0.0111)2(7)题1.1(11.001)2解:(8)(101011.11001)2(1)(3)(11011)2=(27)10(1101101)2=(109)10(2)(10010111)2=(151)10(4)(11111111)2=(255)10(5)(0.1001)2=(0.5625)10(6)(0.0111)2=(0.4375)10(7)(11.001)2=(3.125)10(8)(1010
2、11.11001)2=(43.78125)101.3将下列二进制数转换为等值的十六进制数和八进制数。(1)(1010111)2(2)(110111011)2(3)(10110.011010)2(4)(101100.110011)2题1.3解:(1)(1010111)2=(57)16=(127)8(2)(110011010)2=(19A)16=(632)8(3)(10110.111010)2=(16.E8)16=(26.72)8(4)(101100.01100001)2=(2C.61)16=(54.302)81.5将下列十进制数表示为8421BCD码。(1)(43)10(2)(95.12)10(
3、3)(67.58)10题1.5解:(4)(932.1)10(1)(43)10=(01000011)8421BCD(2)(95.12)10=(10010101.00010010)8421BCD(3)(67.58)10=(01100111.01011000)8421BCD(4)(932.1)10=(100100110010.0001)8421BCD1.7将下列有符号的十进制数表示成补码形式的有符号二进制数。(1)+13(2)-9(3)+3(4)-8题1.7解:(1)+13=(01101)2(2)-9=(10111)2(3)+3=(00011)2(4)-8=(11000)21.9用真值表证明下列各式
4、相等。(1))ABBABAB(2))ABCABAC(3))ABCABC(4))ABACABAC题1.9解:(1)证明AABBBABAABBBABAB0000011110111111(2)证明ABCABACABCABCABAC000000010001000011001000010111.1101111100(3)证明ABCABCA0B0C0AB1CABC100100010110110010000101001101111100(4)证明ABACABACA0B0C0AB1ACABAC100100010110110010011101111100011100.1.11用逻辑代数公式将下列逻辑函数
5、化成最简与或表达式。(1))FABACBCACD(2))FAACACDD(3))F(4))FBDDDBABCADBCADBCD(5))F(6))FACBCBACABBC题1.11解:(1))FABACBCACDABC(2))FAACACDDACD(3))F(4))FBDDDBABCADBCADCDBDABBCABCD(5))FACBCBACACBC(6))FABBCABBCAC或ABBCAC1.13用卡诺图将下列逻辑函数化成最简与或表达式。(1))FABCDABCACD且ABCD0(2))FACAB且A,B,C不能同时为0或同时为1(3))F
6、(4))FA,B,CA,B,C,Dm3,5,6,7m0,4,6,8,13d2,4d1,2,3,9,10,11(5))F(6))FA,B,C,DA,B,C,Dm0,1,8,10m3,5,8,9,10,12d2,3,4,5,11d0,1,2,13题1.13解:(1))FABCDABCACD且ABCD0FBADAC(1))FACAB且A,B,C不能同时为0或同时为1FBC(2))FA,B,Cm3,5,6,7d2,4FAB(3))FA,B,C,Dm0,4,6,8,13d1,2,3,9,10,11FADACDB(4))FA,B,C,Dm0,1,8,10d2,3
7、,4,5,11FBDAB或FBDAC(5))FA,B,C,Dm3,5,8,9,10,12d0,1,2,13FBDABCDAC1.15将下列逻辑函数化简为或非—或非式。(1))FABCBC(2))FACABCABC(3))FABCBCDABD(4)F(A,B,C,D)m0,2,3,8,9,10,11,13题1.15解:(1))FABCBCFBCACBC或FBCBCAB(2))