盖斯定律的运用（详解）.doc

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1、盖斯定律的运用：30、（1）已知：N2(g)+O2(g)2NO(g)ΔH1N2(g)+3H2(g)2NH3(g)ΔH22H2(g)+O2(g)2H2O(g)ΔH3则4NO(g)+4NH3(g)+O2(g)4N2(g)+6H2O(g)ΔH=___________________________求解过程：N2(g)+O2(g)2NO(g)ΔH1①N2(g)+3H2(g)2NH3(g)ΔH2②2H2(g)+O2(g)2H2O(g)ΔH3③首先消除H2，3×③得到6H2(g)+3O2(g)6H2O(g)3ΔH32×

2、②得到2N2(g)+6H2(g)4NH3(g)2ΔH23×③－2×②得到3O2(g)+4NH3(g)2N2(g)+6H2O(g)④ΔH’=3ΔH3－2ΔH22×①得到2N2(g)+2O2(g)4NO(g)⑤2ΔH1④－⑤得到4NO(g)+4NH3(g)+O2(g)4N2(g)+6H2O(g)ΔH=？得ΔH=3ΔH3－2ΔH2－2ΔH1