化工基础习题答案---马淑兰.doc

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1、第1题P=(Pilg-P液)ghHg=(13600-1200)X9.81X200X1O'3=2.43X104(Pa)p2.43X104h液一=P液g1200x9.81F=PS=2.43X104X丄X3.14X(1000X103)2=1.91X104(N)43、设容器上部空间压强为P尸+0水=P+p油gHoH=^H.=x0.5=0.4m坯k1000第4题P水gh水=卩油gh油h?K=—h油=0.8X20=16(m)P水第5题笫6题gP水g1x103x9.81qv=-d2wn=-X[(25-2.5X2)X10-3]2X10X38=0.1

2、2(m3・s'1)44P=Po+pgh=101.3X103+l3600X9.81X250X10'3=1.35X105(Pa)PMp二RT=1.35(kg•m3)1.35x105x29x10~38.314x(298.15+50)qm=qvP=O.12X1.35=0.16(kg•s'1)1800第8题3600714^-x(300xl0-3)2二7・08(m・s")兀4d；1800314"uu=i5.92(ms-1)于X(200x10-3尸=0.382(kgnf3)P0M1.01x105x10x1Q-3"rF"8.314x(298.15+

3、20)p(ci)2-CO.)O.382x(15.922-7.O82)…PrP2=22■丄———==3&83(Pa)22P,-P.38.833h

4、・h尸=；=3.96X10(m)~p水g1x10*9.81h]=20+3・96v24(mm)H=^H°-^-x0.5=0.4m10009、27°C干空气P=1.177kg/m3do=O.O2m202gA7?(0—p)Is0.61启X0.02X率心x(1000-肿4V1.177qm=乞.•p=1.177x0.0156x3600=66.2畑/力第10题2gAR(Pip)PVsoX100%=-1.

5、2%VsoXioo%=1.3%7F8-V20X1OO%=_51%V20指示液改变，流量的的相对误差不变。第11题(心2MR(pr)=o.62x2x9.81x500x10」x(13600-865)7.9(m•s'1)=2.0(ms'1)(o()d；_7.9X16.5?(38—2x1.5)2兀314qm=p-di2coi=865x——x[(38-2x2.5)xl0'3]2x2.0=1.5(kgs")4412、设粗管口处为截面1,细管口处为截面2以截而1为基准，H]=0H2=4.5mdj=0.3md2=0.2m旦+咗+H严旦+墮+仏Pg2

6、gpg2g咗乂=◎+//,=(1°一®"+4.5=-0.597,n2g兀,713、阻力为+H。=PS~巴=厶-d}4•w2/2g,贝!J1000x9.81q、，0.12m3/5=432m3/Aw2w2一十一P—P2_PMw2PSPS2gpg2g2gPS2.疋Pg2gg1000x9.81x0.0251.2143m/s第14题4肿4003600=1.3X104湍流M[3.14x25xl03+3.14x(57-2x3.5)xl0"3]x2xIO'3第15题Re=d^=(24-2xl.5)xl0-3xl.5xlxl03=3iyi()4湍流

7、0.001005e0.01e=—==0.0005d24-2x1.5查入与Re、£的关系表得X=0.025皆X1必。.025X12—rX亠十仲)d2g(24—2x1.5)x10—32x9.8110第16题eE=—==―——=0.00152蚁=d38-2x2査入与Re、£的关系表得1=0.0412g+吃二PgH+咗+E+HfP.=02gPg(38-2x2)x10_3x—x1840^x[(38-2x2)xl0-3]2=5.5X103湍流42.5X10120.002=11.94(m)心丄丄皿2。+2。罟阳2X2)XTd2g(38-2x2)x

8、10」2x9.81—=HrH04-Hf=10+11.94=21.94(m)(co(产0,®太小可忽略)PgP=1840X9.81X21.94=4.0X105(Pa)第17题H°+込+吃二H】+^-+冬+H”Ho二H】+乂+Hf(a)o~O)2gPg2gpg2g_dco/9_(32-2x2)xl0-3x880Re==:cop6.5x10"假设Re<2000,滞流，co<0.053(ms_1)64J_a?Red2g64500.05322000(32-2x2)xl0-32x9.81=0.008(m)J(H°-H]-比)x2g二J(5・0.

9、008)x2x9.81=9.9(mJ),矛盾，故应为湍流。e0.031£=-==0.001,Rc>2000,CD>0.053(ms_1)d32-2x2当没有阻力时co1=7(H0-H,)x2g=75x2x9.81=9.9(nrs“)取