复变函数复习提纲new

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;(6)
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r2e=(r1r2)e:(9)Eêû:“ê/ªŒ^(1.

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nininre=re:121˜ÙEê†EC¼ê(11)EêŠ:én½•ê/ª,/mŠ,˲þ0pnpi+2krei=nren;k=0;1;


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7、uá,ËÿÂ.1••fzjzj>rg.1Ù)Û¼ê˜.ꆇ©1.ê½Â/ªÓu¢˜¼êê,=0f(z+
z)f(z)f(z)=lim:
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xÚ
yÓžC.¦{K/ªþ†˜¢¼êƒÓ(ë„P.50).2.‡©½Â/ª•Óu¢˜¼ê‡©,=e
f=f(z+
z)f(z)=A
z+o(
z);Kf(z)3z:Œ‡,dž7kA=f0(z),¤±‡©df=f0(z)dz.3.†¢¼ê˜,/Œ‡0†/

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