2022年江苏省泰州市中考数学真题

《2022年江苏省泰州市中考数学真题》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

2022
ḕὃᦪ⚪ὃ120ᑖᑖ150ᑖ1.ᔁᑖ⌱⚪⌱⚪!ᑖ.2.ᡠᨵ⚪Ḅᡠᨵ⚪Ḅ%ᫀᙳ(ᑏᙠ%⚪ᓱ,-%ᫀᑏᙠᔁ,.ᦔ.3.0123ᵨ2B56-7898:.;

133A.y=3xB.y=3x2C.y=—D.y=——xx6.᝞1-NABC஺Ḅ^2,E^஺ᔠḄ-OE<0NQEFG.஺E=4,FஹGCḄᑖ^-ᵫ-ᑣ4+ᑘ+Ḅᨬ@^A.V2B.2C.272D.4ஹ⚪ᜧ⚪ᐳᨵᓝ⚪⚪3ᑖᐳ30ᑖ஺ᫀᑏᙠ⚪ᓱ஺7.¡x=—3,ᑣ|x|Ḅ^.8.N¢<᜜¤Ḅ¥ᦪ^.9.20225ᨴ15§440ᑖ-ᡃ©ª«Ẇ᩽J0-xḄåçG.13.᝞1-2஺஺UᑗéA,PO஺஺Uêé8,CᙠAmS,-A,8ᔠ-¡ZP=26°,ᑣNCḄ¥ᦪ^\

2OmC14.᝞1ᡠ¼îïð-ᔜ@NḄᙳ^1.“ò”Ã1ḄWXà-ôõö÷-ᢥ᯿“òô§”Ḅùᑣ
ôúBḄûàḄᨬü^.15.þ஺=2
2-
=
஻-2஻2,஺=2-஻2
/஻ᵨ⊤bஹcḄᜧᐵ.16.᝞AABC,/஺=90,4஺=8,3஺=6,0ᑁ'()0Ḅ*+ᑖ-.ACஹAB012஺ஹ3ஹ45⚪7⍝⚪ᐳ10⚪ᐳ102ᑖ:ᙠ5⚪ᢣ=>?@5஺45ABᑏDE⌕ḄᦻHIJKJ(LᡈNOPQ஺17.SOT1SOTV18—GxY2ᢥ⌕[\]T2x1^SO:--------Ḅ(L᝞`Tx2-4X+2

32x14:—4x+22x1deP(x+2)(x-2)x+22xx-2—dfP(x+2)(x-2)(x+2)(x-2)lx—x—2d3P(x+2)(x-2)_x-2dgP(x+2)(x-2)_x-2dhPx+2^SOḄdePi(\“᦮lmn”ᡈ“plᑖ4”)SO(LḄdPDq┯s.*tᑏDuvḄSOwxi.18.yzஹ{z|}~z“3”2021“3”᳛ᙠᐰḕ᣸de.`ᑡS5⚪.2019!"#“%&”&(ᑖ)2017.2021*"#“%&”&(+,᳛ᢚ/010B”(%)234312.0%ICH)%11810.0%2?/%%M0%e73%6.ᴉ;

4☢ü1260M12,⍝öḄïBýþÿ50m38m21.᝞
QE4ᑖAABCḄ.(1)AF஺Eᑖ(2)BC᪵Ḅᦪᐵ,!"#4OFE$#%&'(ᳮᵫ.22.,-ᙠᱥᳮ0123☢5ᡂ789:ᙠὁ<Ḅ=⚞?ᑮAᔆCDEFE.᝞
ὁ<ᙠGᔆC⚔IJKL☢5MN,MNᜋ☢ABᡠᡂḄONMNB=118஺ᔆCPAB=8m,C⚔AMQᙢ☢S,-ᙠTMḄU?VCᜐX☢5YZ[\ᑮḄQᙢ☢1ᨬ^ᜐ஺ᑮ_Ḅ`aCObcd%(fghiᑮ0.1m,jὃᦪlsin340=0.56,tan34°=0.68,tan56°~1.48)23.᝞
জ$#A8CDn£pqḄrᙊ஺ᙠp/Ḅ1V48TEஹvᙠp/1wAB=7,E=10,BC>5.TBn1xᓫ/zḄ{|XTEᜐ}~EFVᔣ$#ABCOfz

5(1)᝞
2,2.5rᙊ஺ᙠ$#4BCOᑁḄḄ|(2)ᙠTBḄ3AOஹBCvrᙊ஺xTGஹH஺G,0H.NGOHpOfḄ.24.᝞
¡¢ᦪ£=/+᝞+1Ḅ
7y§¨TA,©ª«¢ᦪ¬=L(*>0)Ḅ
7x¨T8(3,1).(1)x¢ᦪḄ⊤³´;(2),xḄ·ᜧ¹·ᜧw,<pᑏ}¼Ḅ½¿;(3)S¨À§Ḅp/¢ᦪXḄ
7¨TCஹD(TCᙠT஺ḄÂ")¢ᦪ᜜Ḅ
7¨TE.ÄAACELBDEḄ☢ÆÇTEḄᙶ᪗.25.Ê8ZV1BC஺8c"1ḄLT.(1)᝞
জ3T஺Î஺E஻ABAC"¨TE,ÄA8=5,BD=9,DC=6,஺EḄ(2)ᙠ
ঝᵨÒÓ|pÔÕᙊÖᙠAC"1DTF,Ø/஺⚗=Ú4(ÛᶇÎ
ÝÞß⌕ᑏÎá)(3)᝞
ঞTFᙠAC"1BFஹDF,Ä/஺ã=NA,åFBCḄ☢ÆǨAB,FD2rqÎ஺æᑨèpBC஺FḄéᐵê'(ᳮᵫ.

626.ëìí¨L¡¢ᦪX=1,TPᙠ¢ᦪXஹÀḄ“ôᔠ¢ᦪ”
7Ḅ1VoḄ½¿ঝÄù1,¢ᦪXஹ¬Ḅ"ôᔠ¢ᦪ”
7ú3Tûbᔲüᙠᜧ,iëḄýí¨ßǨ1ḄþÿᦪP
ᨵ“ᔠᦪ”x஺Ḅ?ᙠḄ!QḄᙶ᪗;ᙠ%&ᳮᵫ.

7ᦪ+,⚪.ὃ,!01120ᑖ34ᑖ1150ᑖ5671.8,ᔁᑖ⌱;⚪<=⌱;⚪>?@ᑖ.2.ᡠᨵ,⚪Ḅᡠᨵ,⚪ḄBᫀᙳEᑏᙠB⚪ᓱHBᫀᑏᙠ,ᔁHIᦔ.3.KLMᵨ2BOPQRSRT.UV@ᑖ⌱;⚪.ᐳ18ᑖ5Vஹ⌱;⚪.8ᜧ⚪ᐳᨵ6Z⚪[Z⚪3ᑖᐳ18ᑖ.ᙠ[Z⚪\ᡠ]Ḅ^?⌱⚗`ាᨵV⚗bcᔠ⚪d⌕Ḅfgh⌱⚗ḄijklEmᙠB⚪ᓱnoH5ூ1⚪Bᫀ௃ூBᫀ௃Bூ2⚪Bᫀ௃ூBᫀ௃Bூ3⚪Bᫀ௃ூBᫀ௃Aூ4⚪Bᫀ௃ூBᫀ௃Dூ5⚪Bᫀ௃ூBᫀ௃Dூ6⚪Bᫀ௃ூBᫀ௃CrஹEs⚪.8ᜧ⚪ᐳᨵᓝ?Z⚪[Z⚪3ᑖᐳ30ᑖ஺uBᫀvwEᑏᙠB⚪ᓱnoH஺5ூ7⚪Bᫀ௃ூBᫀ௃3ூ8⚪Bᫀ௃ூBᫀ௃60°##60xூ9⚪Bᫀ௃ூBᫀ௃9.032xlO3ூ10⚪Bᫀ௃ூBᫀ௃1

8ூ11⚪Bᫀ௃ூBᫀ௃y᳝ூ12⚪Bᫀ௃ூBᫀ௃x

9ூBᫀ௃11.8m[23⚪Bᫀ௃ூBᫀ௃(1)y(2)8ᡈ9ூ24⚪Bᫀ௃3ூBᫀ௃(1)y=X2-3X+1y=-(%>0)t23(2)-

10