机械原理大作业-曲柄滑块机构[精编].doc

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1、机械原理大作业机械五班李剑斌一、题目：已知如图e=50mm/jL1=100mm/L2=312mm,a>1=10rad/s/每隔10度记录一组数据，并且记录该Illi柄滑块机构的位移、速度、加速度图。叫I二、程序选择：机械原理课程设计平台三、数据结果记录：2.数据记录如下：曲柄转角/rad滑块位移/mm滑块速度/(m/s)滑块加速度/(m/s2)0407.9675-0.1624・13.332710403.1215-0.3914・12.803320394.3923-0.6054・11.608530382.1427-0.793-9.79

2、6740366.9221-0.9443-7.464750349.4372-1.0514-4.761360330.5062-1.1095-1.885270310.9995-1.11760.930480291.7686-1.07883.450390273.57635.4829100257.039-0.89086.9232110242.5955-0.76187.7708120230.5062-0.62258.1148130220.8796-0.48078.0944140213.7133-0.34127.8562150208.9376-0

3、.2077.5238160206.4538-0.07867.1854170206.160.04416.8928180207.96750.16246.6673190211.80770.27726.5052200217.63050.38976.3824210225.39750.56.2564220235.06860.60776.0682230246.58490.7115.7446240259.84550.8075.2049250274.68420.8914.3715260290.84550.95753.1853270307.96751

4、1.6235280325.57521.0121-0.2877290343.08820.9884-2.469300359.84550.9251-4.7951310375.14240.8211-7.1111320388.27750.6779-9.2527330398.60250.5-11.0641340405.5690.2944・12.4114350408.76930.0701-13.1909360407.9675-0.1624-13.3327