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1、小学生小升初数学常见简便计算总结分析与解在进行四则运算时，应该注意运用加法、乘法的运算定律，减法、除法的运算性质，以便使某些运算简便。本题就是运用乘法分配律及减法性质使运算简便的。 例1、 例2计算9999×2222+3333×3334 分析与解利用乘法的结合律和分配律可以使运算简便。 9999×2222+3333×3334 =3333×（3×2222）+3333×3334 =3333×6666+3333×3334 ＝3333×（6666+3334） =3333×10000 = 分析与解将分子部分变形，再利用除法性
2、质可以使运算简便。 这可让他犯了难，施工现场距离项目部很远，没有车还真是不方便office,branchoffices(jurisdiction),riskmanagement,marketingmanagementsectorthroughsupervisionandinspectionfoundproblems,shouldbeassignedtheinvestigatorsarecorrectedinatimelymanner.27ththefifthchapterpenaltyunderanyofth
3、efollowingacts,thentherelevantprovisionstopunishtheinvestigators,accordingtotheBank.Toconstituteacrimeshallbeinvestigatedforcriminalresponsibility:(A)onthebusinessthatarenotinvolvedintheinvestigation,issuedasurvey.(B)customercreditinformationarenotthoroughverification
4、.(Iii)toparticipateincreditcustomersurveyisnotinplace,customersanddataisincomplete,untrue;heknowsbearacounterfeitedclientsissuingcredit.(D)doesnotprovideforduediligenceofcreditbusiness,pre-loaninvestigationform,concealingfactsorprovidingfalseinformationorshouldbefound
5、inanormalinvestigationfailedtodiscovertheriskfactors,leadtothereviewandapprovalpolicyerrors,loanrisk.(Five)onloanguaranteesofsurveynotinplace,notbyprovidesonarrived,andpledgerealforfieldverification,andassessment,andidentificationandregistration,notaccordingtoprovides
6、onguarantorofguaranteesqualificationandguaranteescapacityforsurveyverified,ledtoguaranteesloanlostauthenticity,andlegitimacy,andeffectivenessof;cycleloanbusinessintheofmortgage 分析与解在计算时，利用除法性质可以使运算简便。 分析与解这道分数乘、除法计算题中，各分数的分子、分母的数都很大，为了便于计算时进行约分，应该先将各分数的分子、
7、分母分别分解质因数，这样计算比较简便。 分析与解通过观察发现，原算式是求七个分数相加的和，而这七个分这可让他犯了难，施工现场距离项目部很远，没有车还真是不方便office,branchoffices(jurisdiction),riskmanagement,marketingmanagementsectorthroughsupervisionandinspectionfoundproblems,shouldbeassignedtheinvestigatorsarecorrectedinatimelyman
8、ner.27ththefifthchapterpenaltyunderanyofthefollowingacts,thentherelevantprovisionstopunishtheinvestigators,accordingtotheBan
