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ID:34469350
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页数:17页
时间:2019-03-06
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1、ONTHEBPPHIERARCHYPROBLEMCHRISTERBERGANDJOHANH?STADAbstract.InthispaperwegiveargumentsbothforandagainsttheexistenceofanoracleA,relativetowhichBPPequalsprobabilisticlineartime.First,weproveastructuretheoremforprobabilisticoraclemachines,whichsaysthateitherwecanxthe
2、outputofthemachinebysettingtheanswertoonlypolynomiallymanyoraclestrings,orelsewecansetpartoftheoraclesuchthatthemachinebecomesimproper.ThistheoremcouldhelpcompletetheconstructionoftheoracleA,whichwasproposedbyFortnowandSipserin[2].Second,weshowthatthereareprevious
3、lyunknownproblemswiththisconstruction.Thusthequestionwhetherprobabilisticpolynomialtimehasahierarchyrelativetoalloraclesremainscompletelyopen.1.IntroductionkIfweareabletosolveaprobleminpolynomialtimenforsomek,itisnaturaltoaskifitispossibletosolvethesameproblemfast
4、er,forexamplek?1intimen.Eventhoughformostproblemswendthatthereissomelimitastohowfastanalgorithmweareabletodesign,wealsoknowthatitisveryhardtoprovethatouralgorithmisthebestpossible.However,fordeterministicandnon-deterministicpolynomialtimeatleastweknowthattheredoe
5、xistproblems(althoughtheyaresomewhatunnatural)whichkk?1aresolvableintimenbutnotintimenandhence,thesecomplexityclassescontainsahierarchyofincreasinglymoredicultproblems.Thehistoryofthesehierarchytheoremsisasoldascomplexitytheoryitselfthatdeterministicpolynomialti
6、mehasahierarchywasshownbyHartmanisandStearns[5]in1965andthecorrespondingtheoremfornon-deterministictimewasshownbyCook[1]1973.ThecomplexityclassBPPconsistsofproblemssolvableinpolynomialtimebyprobabilisticTuringmachineswhichforeachinputacceptswithprobabilityeitherle
7、ssthan1=3orgreaterthan2=3.Althoughitisnaturaltosuspectthatalsothiscomplexityclasscontainsahierarchyofproblems,thishasnotbeenprovedtobethecase.Thetechniquesthatworkfordeter-ministicandnon-deterministictimedonotapplyintheprobabilisticcase.Itisnotcompletelyclearwhypr
8、obabilistictimeisdierentinthisrespect,butonemajorobstacleistheexistenceofimpropermachines.Namely,ifforsomeinputamachineacceptswithprobabilitybetween1=3
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