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1、第十章配位化合物(Thetenthchaptercoordinationcompounds)Thetenthchaptercoordinationcompounds1.anhydrousCrCl3andammoniacanformtwocomplexes,whichareequivalenttoCrCl3?6NH3andCrCl3?5NH3.AddingAgNO3solutionfromthefirstkindofcomplexesinaqueoussolutionofalmostallofthechlorineprecipitati
2、onisAgCl,andfromsecondwiththeprecipitationofequivalentcompositionofchlorinecontentin2/3AgClcanonlymatterinaqueoussolution,addingNaOHandheatingtwokindsofsolutionarenoNH3taste.Theinternalandexternalboundariesofthecomplexesarecalculatedfromtheformofcomplexes,andthechargenu
3、mber,theoxidationnumberofthecentralionsandthenameofthecomplexesarepointedout.Answer:thefirstkind:thechargenumber[Cr(NH3)6]Cl3ion3+:Thatis,[Cr(NH3)6]3+,Cr(III),threechloridesixammoniachromium(III).Secondspecies:[CrCl(NH3)5]2+,Cr(III),twochlorinechloride?Fiveammoniachromi
4、um(III).2.namethefollowingcomplexes,andpointoutthecentralionsandoxidationnumbers,ligandsandcoordinationnumbers.(1)[Co(NH3)6]Cl2(2)K2[PtCl6](3)Na2[SiF6](4)[CoCl(NH3)5]Cl2(5)[Co(EN)3]Cl3(6)[CoCl(NO2)(NH3)4]+Answer:NamingCentralionoxidationnumberLigandcoordinationnumber(1)
5、twochlorideandsixammoniacobalt(II)+2NH3Six(2)hexachloroplatinum(IV)acidpotassium+4Cl-Six(3)sixfluorinesilicon(IV)sodiumsalt+4F-Six(4)twochlorinechloride?Fivecobaltcobalt(III)+3Cl-,NH3Six(5)threechloridethree(ethylenediamine)cobalt(III)+3EnSix(6)onechlorine,onenitro,four
6、ammoniacobalt(III)coordinationion+3Cl-,NO2-,NH3Six3.writethechemicalformulaofthefollowingcomplexes(1)twothiosulfatesilver(I)sodium(2)threenitrothreecobaltcobalt(III)(3)twothreeammoniachloridechloridehydratedcobalt(III)(4)twochlorotwohydroxydiaminoplatinum(IV)(5)chromium
7、chloride(two)(ethylenediamine)andchromium(III)(6)twochlorineionsagrass(ethylenediamine)Fe(III)ionsAnswer:(1)Na3[Ag(S2O3)2](2)[Co(NO2)3(NH3)3](3)[CoCl2(NH3)3(HO2)]Cl(4)[PtCl2(NH3)2(OH)2](5)[CrCl(NH3)(EN)2]SO4(6)[FeCl2(C2O4)-(EN)4.accordingtovalencebondtheory,thebondingan
8、dspatialconfigurationofthefollowingcoordinationionsarepointedout(1)[Fe(CN)6]3-(2)[FeF6]3-(3)[CrCl(H2O)5]2+(4)[