高考真题及模拟——流程题

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=1.05mol/L,îïᡠãᑴNHnÒḄÏ⊝ÅᦪKzᑏòïä:òï®Kóᶇôõᨵᦔᦪö஺4
ᙠ×ØᩩøuᩖḄôÈᓄùxg⏚xḄ¥¦679:;vUzú5
ûü®ᨔä:◤⌕Þᵨ6070࠷ný×Ø9;ᐸ3Qv஺33.þÿ
ᳮ-
᪷ஹᩈᙠẆ“ᨵᔠᡂḄᓄḄ"#Ꮤὶ”'()2010*+,-.ᓄ
ᝄ஺ᨵᔠᡂ1ᵨḄ/4ឋ6ᓄᑺ89:;ᵨᓄᑺ<=ᩖ?@᝞BCஹᨵᱥEFGH'ᜫJ4ឋ8ᡂKLᓄᑺ8◤NᐸPQRᦈ஺TᵫLᓄᑺᑴWXᓄYḄZ[\]᝞^B_ᔁa16⚓8c17⚓

16550,C(1)Lᓄᑺhijk8Pᙠ700࠷Ḅop^ᯏr8ᯏrs]◤tᐭvwxyḄz{;ᵬ⏚zᓄYḄᓄ
]K஺(2)ᙠ(⏚⏚ᢥ1B3)ᓄKH#dCI“8⏚zKNO,Ḅᓄ
]KB஺(3)YḄRᦈ᳛o⌕W¡¢£¤Ḅ¥¦ᩩ¨8©ªp+ஹ«¬ᵨwNRᦈ᳛Ḅ®᝞^¯1°¯3ᡠ²8ᑣ£¤´Ḅ〉¶ᩩ¨(p+ஹ«¬ᵨw)(4)¸¹«8ºK»£ឋ¼Pd(NH3)J",À«CḄÁᙠÂ{(ᑏᓄ
)஺(5)700࠷ᯏr1ḄÅḄ{B;550࠷ᯏr2ḄÅḄ{B

17

18ÆὃÈᫀ1.(1)Cu+2N(V+4H*=£=Cu2'+2N02T+2HzO3Cu+2N0+8H4=^=3Cu2*+2N0T+4H0AuஹPt32(2)ÊF/ᓄKFe"ËÌᐭᩖ?8NÍ᛻ÏGHÐFe"ஹAÑÐ(3)¸ÒῃÐ(4)ᵬÐᡠ)ÑÔÕᨵÖ×ḄFez(SO஺3ᩖ?ÐØÐcmol-U'xbx10~3Lx250g-mc>r'x5,-----------------------------------------------x10A0A%n/(5)agÐCo2.(1)Ù(2)জzᑺঝÜ⁚£ÞpHᙠ89߬বজCu(OH)C03+2HS04=2CUS04+C0T+3H0OঝHC0-஺222223KT஺ঞMnO2+2Fe"+4H+=Mn2++2Fe3++2H0»ট23.(1)জ2Al+Fe03==AI0+2Feঝ4AI+3SiOz==3Si+2AlQ223(2)%ஹAICI;NaCI(3)CI+20K==CI'+CI0+H0322(4)□᩽Ð□᩽BAl-3e=AI3\(▢᩽:4A1C17+3e=7AIC14+AI)2(5)åᙠxy᧕Âᡂç᩽ↈḄéê'ëìḄᓄí8îïðñᓄòᐭᑁô8õᑮ■ῖùú¦ᵨ4.(1)QᡂTi",ùúFe”Ë=ᓄ(2)10ym(3)2.79X103(4)Ti0(s)+2C(s)+2C1(g)=TiC|(I)+2C0(g)AH=-81kJ-mor1224(5)ÑQûLy8LÞ8LE(6)üý(ᡈᑖ)5.(l)4FeS2(s)+llO2(g)=2FeO(s)+8SO(g)AH=-3408kJ/mol232(2)2HO+SO=H2SO4+H222(3)HIᑖ⊝ᔣHIḄᑖ᳛(4)(i)MH+OH-e'=M+HO(2)2HO+O+4e=4OH2226.(1)᳛(2)ᮞ(3)Fe2\Mg"ஹCa"(4)2Li*+C02'AizCChJ(5)NazSO,37.পজFe”ᙠឋᩩ"#$᧕&'ᓄ(*ᔠᳮ-ᫀᙳ0)ঝ(NH),Fe(SO),+LiOH+HPO=LiFePOJ+2NHHSO+HO44344442ঞ2345Q■7LiFeP.5ḄFe?+&'ᓄ”ஹ|8LiCoO,+Na2s,0
+11HSO=4LiSO+8cosQ+NaSO+11H,O942494ঝCoO803ஹCO3O48.(1)20K+CI=CI0+Cr+H0(2)AC(3)2Fe3+3010+100H'=2Fe0?+3CI+5H00.45222(4)4FeO9+10H20Ma4Fe(0H)3(:;)+3O2T+80H'(5)Fe+80H6e-=Fe0?>4H02(6)Zn+20<2e=Zn(OH)2ᡈZn+20H=Zn(OH)+2e\29.(1)FezChᡈFe3(L,ᡈὅFeB?FesO,(2ᑖ)(2)H2so“2NaVOsAᡂCDḄHVO,HVO3ᒹFᙠGHIJḄ⊤☢MNOḄPQRSTUO3HV03V᳛WVAḄHV03XY஺[᜜]Ḅ'ᓄᱥ_?`⏚Aᡂ]bcde᡾bcgὑ`⏚ijkl஺(4ᑖ)(3)mn(2ᑖ)Na\AV(2ᑖ)D(2ᑖ)-ᫀo1⚓q4⚓

194
V0+20H=2V0+H02ᑖrs0tuᨵwxyr253210.1
Si0+20H-=Si02'+H02ᑖr2322
Fez2ᑖr{|ᨬ~GᐭKSCNDX⁐ᑣ{ᔲᑣ2ᑖᐸᔠᳮ-ᫀᑖr3
2CeO+H2O2+3H2sO4=2CeS0
3+O2T+4H02ᑖr22424
ஹᓾᨔs31ᑖᐳ2ᑖr5
46.632ᑖ◤ᶇᦪ~r11.1
〉¡ᓣ£{dᜧᔾᦈ§{2
CIOH2O2+2C10+2Na0H=2NaCIO+2HO+O22223
¨©£mª`⏚«¬᧕ᑖ{4
NaS0;5
mn2412.1
ᤅ®D{¯°஺2
34{±'ᓄᑺ³´µ]bc'ᓄ¶·µ]bc{3
bd;4
ᐭ¸ᑺ¹º»`⏚ᡈ»¼⏚½;¾ᐰDWÀ4ÁVAKSCNDDXÂ⁐ᑣÃÄVᱥ¶FeOH2O2DD¶⁐13.1
b1ᑖr2
mn1ᑖrmn1ᑖr1ᑖr3
KCI01ᑖr{3Mn042-+4H+=2Mn04-4-Mn0X+2H02ᑖr4
963ᑖr32214.1
Mn2++CI0-+H0=Mn0J-+2H*+CI-2ᑖrÅPAl"ஹFe"ÆÇMn"'ᓄᡂMnO?2ᑖr222
Fe0H
32ᑖrAlOH%2ᑖr3
|mnII~Ḅn12mLȸÉ5ᐭÊËKSCND᝞ÍDXÎ⁐ÏÐn5ÀFe"3ᑖr4
CaSO"2H2஺ᡈCaS02ᑖrt■MgSO”ᙠ£UÑᨔ᪆2ᑖr஺415.1
SiO2ᑖrHSO2ᑖr224ফᙠᑖÔᧅ#Ö×GØIÙsÔᧅ#ÚÉÛÜ☠IÙᑁßrᡭáᑖÔᧅâÛãcsᡈ³ᑖÔᧅâÛãcäåæçÔᧅÛ⚠âérᡭáêã³#ë;×ᐭIÙ¡ᑖ☢ìísᡈᶍïmrêãᜐÑᐵòêã{âë;RᑖÔᧅâÛ᎔ᐭ[GIÙ5஺2ᑖr⌕õᡭáᑖÔᧅâÛãcsᡈ³ᑖÔᧅâÛãcäåæçÔᧅÛ⚠âér1ᑖr{ᐜᡭáêã×#ë;~³âë;RᑖÔᧅâÛ᎔ᐭ[GIÙ51ᑖr஺বᐭ5?`⏚⊝ஹøùú⃓|2ᑖrᑏ“ᐭs0týNaOHஹKOHஹþÆr5?`⏚⊝”
2ᑖᑏ“⃓”
2ᑖᑏ“ᐭMgஹFeஹ⏚”2ᑖᑏ“ᜧ⃓ᑺḄᐭ”1ᑖᑏ“ᜧ⃓ᑺ”
ᑖᑏ“H2s0,”1ᑖ஺4
1010+6V02*+6H*=6V0"+1CT+3ᖾ_2ᑖ%⊡C'()0,1ᑖ஺*+,-1ᑖ஺ᑏ“1”ᡷ1ᑖ஺5
1.7—1.82ᑖ%ᑏ1.7ஹ1.8ஹ1.75ஹ1.7—1.8/0ᙳ2ᑖ஺ᑏᡂ1.6,1ᑖ஺য45ᨵ7⃓ᑺ2ᑖ%ᔜ1ᑖ஺9ᑏ:;ᡷ1ᑖ஺16.1
<=>?@AஹᓣCDஹᜧE5FGH2ᑖ%IJ:K1ᑖL2
2Fe>+2H++H0=2Fe3+2H02ᑖ%I*+┯NᡈᓄQRᑏ┯0ᑖL222CuOஹCUU0H%2ஹCuCOsᡈCuzOH
2cO3YḄZ:[2ᑖ%3
1X10-mol/L2ᑖ%:\ᱏpH^_`ᙠbᴻᱏᡈ⊤☢fgᵨbᴻᣟᡈjᜮlmnopKᙠpH^_Yqnr⁐tᓄuvwx᪗z)⁐ᓱJ)|pH}஺2ᑖ%c
OH~
XcCuNH

,~%4
-c-NH
•H0
2ᑖ%5
GḄ⁐ᨔ᪆2ᑖ%17.1
100mLbᴻjᜮlmU9E1ᑖᐳ3ᑖ%ᫀ2⚓4⚓

20(2)2Fe2+H0+2H=2Fe3t+2H0(2ᑖ)222বZnO(ᐸᔠᳮᫀ¢£)(2ᑖ)3.1¦5.2(2ᑖ)ᓫ©CuᡈCu(Zn(2ᑖ)(4)Zn(0H)4C0-HzOCD3Zn0+C0T+3H0(2ᑖ)332218.(1)ᜧ¯Ḅ⊤☢°±ᓄQ²³G᳛஺(2)TiO"+2HQ=HTiO1+2H*(2ᑖ)23(3)CI0-+2Fe"+2hT=2Fe"+CF+H0(4)ᣚg¼Ḅ½¾ᘤ<ÀÁ¾p¼½¾(2ᑖ)2(5)ÃC(1ᑖ)lᨬw:lKMnO,᪗zpptᡂÈÉ⁐ÊᙠËᑖÌᑁÎ⁐ÏÐ(2ᑖ)஺28cV/a%(3ᑖ)19.(1)NaCI+NH+C0+H0->NaHCOl+NH4cl(2)92%(2ᑖ)3223(3)■ÐÛÜᮞᐜßpYḄNaHCOs²³áÛâ⏚┛äå(1ᑖ)(4)bd(2ᑖ)(5)èéáÛᜧêᨵCaCI2Ḅëp(ᡈ⁚ḕÜᮞîஹï4ᛞHñᜓ)(1ᑖ)(6)জ20.20mL(1ᑖ)0.020ILX0.6000mol/LX84g/molX20nlঝ3(NaHC03)=5.000gX100%(1ᑖ)ঞac(2ᑖ)20.(1)2AI+20H+2H0=AI0+3HT(1ᑖ)ফFe*(2ᑖ)C0?(ÿ(2ᑖ)222(3)4Fe2+80H+0+2H0=4Fe(0H)i(2ᑖ)(4)2Cu+4H++02=Cu2t+2H0(1ᑖ)2232(5)4ᨵᑺAḄ□!(᝞Na'&)'()AICL,-.(2ᑖ)(6)AlCh-6H0+6SOCI2=AICl3+12HCI+6S0t(2ᑖ)2221.(1)SO?789ᜧ;<=(1ᑖ)'>?⌕AὑᜧCḄDE(1ᑖ)(2)FeS(1ᑖ)ஹCuS(1ᑖ)(3)4CuC1~+0+4Ht=4Cu2++8CI-+2H0(2ᑖ)2222(4)HIJK'L⏚NḄOJPQRᓄN(2ᑖ)(5)BCD(2ᑖ'V⌱1XY1ᑖ'┯⌱ᡈV⌱2X\],Yᑖ)(6)জSOz+2Fe"+2H0=S0/+2Fe'4H+(2ᑖ)ঝ12.00%(2ᑖ222.(1)dᓄefgh(2ᑖ)(2)CN+CIQ-CNO+CI(3ᑖ)(3)j⁚lmpH,)ᐸqᓄᡂCr(0H)3tuv(4ᑖ'ᐸwᔠᳮzᫀ|}ᑖ)(4)3szCV+MnO+26H*6soy+8Cr"+13H2O(3ᑖ)(5)CU2'+20HCU(OH)1ஹCu(OH)(s)+S2_(aq)___CuS(s)+20H(aq)22ᡈKsp(CuS)?IJä'çèজÄ⊝ᔣ⌮çèᔣîï(4)ஹজL⏚(ᡈHzSOJ(2ᑖಕHzNSO3H+NaNO?=NaHSO+NT+H?0(2ᑖ)42ঞ98.0%(3ᑖ)26.(1).2Fe"+2H'+H202T2Fe"+2HzO(2ᑖ)ᫀ3⚓4⚓

21(2).■L⏚NᙠôÈõöØ÷Cu"ÈømO(Y,ᑮ-.ḄᨔÝ(2ᑖ)(3).úC'£ᐭKSCN(N&SCN)'üýþᔲᯠ⁐஺(2ᑖ)(4).ᨵᨔ(ᡈᯠ)(2ᑖ)(5).ஹᐭNaOH(aq)(ᐳ2ᑖ%ᔜ1ᑖ)(6).91.9%-1.4%(ᡈ-1.39%)(ᐳ2ᑖ%ᔜ1ᑖ)27.(1)ஹ4(2ᑖ)(2)0.20mol/L(2ᑖ)0.014(2ᑖ)4(3)ஹ2:1(2ᑖ)CaSs(2ᑖ)(4)ஹn(Ca0)=50.4/56=0.3moln(S)=96/32=3mol(1ᑖ)ᑣn[Ca(0H)]@n(S)=3:10ᵫBCDE@3Ca(OH)+10S^-^2CaSx+CaS20+3H02232IJ@x=4ᓽLMᓄᱥPMQRḄTᙳV4.(1ᑖ)ᦑXYZLMᓄᱥD[@CaS?]CaSsᡈCaS3]CaSs஺(2ᑖ)ᵫ5/DE%n(CaSz):n(CaS)=1:2_ᵫ`ஹiDE%(CaS)@n(CaS)=1:1(1ᑖ)5n3528.1)Ca(0H)2ᡈCaONa2C032)cdec3)ᨵᨔf᪆(ᡈhi)j⏚lmnj⏚olᜧ4)NH4clr᪵%t⏚⏚ᓄ%t⏚u%ᨵv⁐wx%y▢{R|}{R5)""T
+HQ■ᮞj⏚┛wxa)NaHCO=84(.¡)36)31ml29.(1)2Al(0H)+Mg(OH)=MgAI0+4—03224(2)ᧅᘂᑁAgNCh(ᡈt⏚⏚ᓄḄAgNOs)_ᵨ(3)Al(0H)Al*+3NH-HO=AI(0H)+3NH/3323(4)◀HCI_ᔾᦈd¢_£ᮞ(ᡈNaOH]CaO¤ᔠᱥ)(5)4.00g30.(1)H2O2+2F/+2H*=2Fe*+2HzO(2)Mg(OH)2¨©m(3)জᔣ¬®Pᐭ12¯0.1mol/LH£(Lঝ±r²᪵³%wx´³%µ¶⌼ᡂḄ¹ᜫ´ᜧঞ¼BaSO+40=400+BaSᡈBaSO«+2C=2C0+BaS42টBaCrO,Ḅ᥅ÂÃᜧÄBaSO”31.(1)ÆpH²ÈÉᙠËஹḄ⊤☢ά%ᵨËஹḄÏᴻÑ↾r³ÓÔ¯ᙠpH²ÈPÕ,Ö×Ø⁐Ù]n⁐ᓱnÛ(2)ÜPḄSn"ÝᐰßᓄSnS,àFe"áᡂFeSwx(3)ÏᴻÑஹᧅ(4)ÆPḄFe*{RßᓄFe2+{R(5)deâãc(6)äåæḄm%ç³åæḄ¹ᜫ32.(1)èNH_+%0=NH3•HQ+K,MgO+2H=Mg2+H0,ëᓄ╅íὑo{R%ï᪷{RT⊝ᔣòóô%2áõ¨öH'ÜMgOáõ(3ᑖ)(ᑏYùúûü´ý2ᑖ%T⊝ᔣòþÿ1ᑖ)(2)(NH,)2s0,(3)250ml(2ᑖᨵᑖ)K=5.00X10-3mol«L-'(4)Fe0+6NHJ=6NH3T+2Fe"+3H?0(ᩩ+,-.)(ᨵᑏᩩ+01234ᡷ1ᑖ67ᡷ1ᑖ8)23(5)9:-.;<=>?MgS(L•7H2OᜫFGᑖᡈᐰGḄKᨔM(2ᑖ)33.(1)NOឋQᐙᑖSTU◀F(2ᑖ)Pd0+HC00H=Pd+C0+H0(2ᑖ)22(2)3Pd+12HCI+2HN0F3H2PdeI4+2N0+4H2O(2ᑖ)(3)8090°C(ᡈ90࠷_`)ஹbcdefg8hஹijklmMḄnog1,8(3ᑖ)(4)Fe(0H)(2ᑖ)(5)◀FOឋQpᨵqᱥ(2ᑖ)8ῃt(uPd(Nh஺஺wxygPdCh)(2ᑖ)3ᫀ4⚓4⚓