安康市重点中学2022-2023学年数学九上期末学业质量监测模拟试题含解析

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2022-2023
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1.ூ௃⚪ὃÖḄឋN¹nᦪkàḄឋN\⚪Ḅᐵ]áâÖḄឋNt⌕ªḄBDºᓄᡂ}ªᨬ+ØḄAC.ஹ\⚪¦ᐳ66ᑖ©19ஹä¹5å2ூᑖ᪆௃mAP=NP=x,ᙠRtAAPMæ}ª«MP=6X,ᙠRtABPMæZMBP=30°,ªx,ᑭᵨMN=MP-NPᓽªᫀ.ூ\௃\
•.•ᙠRtAAPNæZNAP=45°,.PA=PN,MPᙠRtAAPMætanZMAP=-----,APmPA=PN=x,VZMAP=60°,.MP=APtanNMAP=6x,MPᙠRtABPMætanZMBP=——BPVZMBP=30°,AB=5,••-----------y3x+55X=-92.".MN=MP-NP=V3x-x=5G-5.

13:åæçḄèMNḄé+ê^ë.2ூ&u௃M⚪ὃwfᙠ>▭í⚪îḄïᵨ>▭í⚪ð+ᦪñí⚪⌱ᵨ〉*Ḅ┦ᦪfzf⚪Ḅᐵ}ô5îὃḄõὃ&.20ஹ(l)AABCzCῪ)(2)AABCz)(3)xi=0,x=-1.2ூf᪆௃H⚪ᑖ᪆9(1)÷x=-ljᐭlᐵ5a,bḄCøù2l2=1),ᓽqᑨûüABCḄ)(2)ᑭᵨ᪷Ḅᑨþøù2lᐵ5a,b,cḄCøù2ᑨûAABCḄ)(3)ᑭᵨüABCzCᑣa=b=c,
ᐭᓽ.⚪᪆(1)AABCῪᳮᵫ-1Ḅ᪷:.(a+c)x(-1)2-2b+(a-c)=0,Aa+c-2b+a-c=0,.*.a-b=0,:.a=b,/.ABCῪ(2)•ᨵḄᦪ᪷(2b)2-4(a+c)(a-c)=0,4b2-4a2+4c2=0,:.a2=b2+c2,.'.ABC"(3)#$ABC&(a+c)x2+2bx+(a-c)=0,᦮ᳮ(2ax2+2ax=0,:.x2+x=0,)Xl=0,X2=-1.ὃ+,ᐗ./Ḅ0ᵨ.31521ஹ(1)y=-x2-2x+3,D(-1,4)(2)F+ᙶ᪗((-5,ߟ),(3)5ᙠ78ᩩ:ḄP+ᙶ᪗((-1,6-1)ᡈ(-1-V5-1)ூᑖ᪆௃(1)AA(—3,0),C(O,3)ᐭஹ=-/+E+஺))ᑮᐵIJcḄKᯠMKᓽNᱥP᪆QRA᪆QSᡂ⚔+Q)D+ᙶ᪗;

14(2)᝞k2,gFQ஻yhACVQ,ᐜᑭᵨîᦪ磌ACḄ\᪆mÃ(x,-f-2x+3),ᑣ0(x,x+3),ᑣ⊤ô«FQ=_3%,,᪷J☢¬ᔠ¹nᦪḄឋNᓽª\ø(3)mP(-l,᪷JᑮJ=ἠᨬÏᑖ`ýþÿ
ᓽ.ூ
௃
(1)A(—3,0),C(0,3)ᐭ=%2+ᡈ+஺'9-3஻+஺=0,c=31'=—2/.\ஹ+c=3,ᱥ.Ḅ
᪆12=/—23+3,Vy=—x2—2x+3=—(x+1)'+4,.•.9DḄᙶ᪗2(-14)=(2)᝞?2,@FQ஻yCDACEQ,FG.ACḄ
᪆12>=᝞+஻+A(-3,0),C(0,3)ᐭ-=*+஻,—3m+n=0c.n=3m—\
c+n=3JG.ACḄ
᪆12y=x+3.FKL,—%22%+3),ᑣ஺(x,x+3),

15:.FQ——x2-2x+3-(x+3)=-%?—3x,•••5.FAC=g.3”Q=|(-x2-3x)=-|x2-|x=-|(x+|)2+y+3315X=WAFACḄ☢Yᨬᜧ\WF+ᙶ᪗((--,—),224(3)5ᙠ.VD(-1,4),A(-3,0),E(-1,0),•••A£=2,AD=V22+42^722+42=275»`P(—1,f),ᑣP£=PH=WDP=4T,᝞c3,VZHDP=ZEDA,ZDHP=ZDEA=90°:.RMDHPsRtADEA,9PH_DP••,AEDA.M_4T#t>oW5=5^)t=-i.#t<0W~2~~2Js")f=,d,1efᡠh78ᩩ:ḄP+ᙶ᪗(
-1i-1ᡈ
-1,-⌲-1ூ+k௃l⚪./mᦪeᔠ⚪o⌕ὃqr./mᦪcsf+Ḅᙶ᪗ᱯuஹ./mᦪḄឋwxḄᑨz{ឋw|ᑭᵨ~zᦪmᦪ᪆Qᑨl⚪Ḅᐵ.22ஹ
1y=600-5x
0

16ᦪᐵ\1y=-5x2+100x+60000=60420,ᔠᐗ_`ab
cᓽ.ூ
௃
(1)dᙳfg᪛Ḅijkᦪy(k)lxmnḄᐵ\2y=600-5x(0⊤ᑁᦪ0.26,0.25,0.25(1)0.25(2)1(1)—.16ூᑖ᪆௃(1)Gᑭᵨ⚣ᦪ+uᦪ=⚣ᫀ᳛=ফFj¡ᳫᨵXk,ᑭᵨ⊤ᦪ¤¥ᑮ¦ᳫḄ⚣᳛ᑡᐵEXḄᑖ1ab+ூ
௃(1)2514-1000=0.251;•••ᜧw¨©ª«¬®¯Ḅ⚣᳛⌲±²³ᑮ0.25▬µ0.25,•••¤¶·᥎kᳫ¦ᳫḄᭆ᳛0.25;(2)F¡ᳫ2xk+1——=0.25,1+Xx=l.¤¶ᨵ1k¡ᳫ.(1)ᵫ⚪»᪛¼?/7K/nxᵫ᪛¼?½,ᡠᨵ¿ÀḄoᐳᨵ16r,ÂÃoÀḄ¿ឋÅÆ,ᐸÈ`É᥎¡ᳫḄᨵ9rÊË.9ᡠP(È`É᥎¡ᳫ)=5.16

17ூ9௃Ì⚪⌕ὃÍÎÏ«Ð⚣᳛cÑ᪛¼?clᑡ⊤cᭆ᳛+
ÒÌ⚪Ḅᐵ⌕ÓÔÕÖᭆ᳛¶¥ac.24ஹ(1){|Cx=l,⚔9ᙶ᪗(1,-4)=(2)xx>ls+yØxḄ}ᜧÙ}ᜧ.ூᑖ᪆௃(1)Ú
᪆1Ûa2⚔91Ü1+ᓽᑮ?ÝḄ{|CÐ⚔9ᙶ᪗=ফ᪷a=l³ßàaᔣ+ᓽ᪷{|CᑮyØxḄ}ᜧÙ}ᜧḄxḄâãå.ூ
௃
(1)Vy=x2-2x-l=(x-1)2-4,.,.{|Cx=l,⚔9ᙶ᪗(1,-4)=(2)Va=l>0,ᦪ?Ýßàᔣ+xx>ls+yØxḄ}ᜧÙ}ᜧ.ூ9௃⚪ὃ_`ᦪḄÛacᓄ2⚔91
᪆1+_`ᦪḄឋç.25ஹ(1)è
᪆=(2)m=l.ூ
᪆௃(1)¶¥᪷Ḅᑨê1ë,ìíëm()=(2)î1ᑖ
ïabḄÈk᪷+᪷m2᦮ᦪஹÈkðÅÆḄñ᦮ᦪ᪷ᑮmḄã.ூ
௃-(m+3)f-4mx3,=m2-6m4-9+=(m-3)2,•.•(m-3)2NO,BPA>0,_ðm2òã+abuᨵÏᦪ᪷.(2)(mx-3)(x-l)=0,3τX]=—,x=1,2mvabᨵÈkðÅÆḄñ᦮ᦪ᪷+/.m=l.ூ9௃Ì⚪ὃᐗ_`ab᪷Ḅᑨê1ஹᐗ_`abḄ
c•
Ò(2)Ḅᐵᵨî1ᑖ
cabḄÈk᪷.26ஹ(1)100ᐗ=(2)x├ôᓫö³2105ᐗs+÷ᨬᜧᑭù+ᨬᜧᑭù2025ᐗ.

18ூᑖ᪆௃(1)᪷⚪ᑡab+
ᐗ_`abᓽ=(2)ᐜ᪷ᑭù=fḄᑭùX├ôw⊤üᑭù+ᯠþᑭᵨ_`ᦪḄឋçᨬᜧãᓽ.ூ
௃(1)ÿ⚪
(x-60)(-x+150)=2000,x=l(X)ᡈx=110(ᔠ⚪
).(2)ᜩḄᑭWᐗ!"#jW=(x-60)(—x+150)=-X2+210X-9000=-105)2+2025,.•.(├*ᓫ,-105ᐗ.!/0ᨬᜧᑭ!ᨬᜧᑭ32025ᐗ.ூ56௃8⚪9⌕ὃ<=>?ᦪABᐗ=>CDḄEᵨ!GHBᐗ=>CDḄCIJ=>?ᦪḄឋL3⚪ḄᐵN.