【中考数学】2022-2023学年山东省济宁市专项突破仿真模拟试卷（一模二模）含解析

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44(a+2)(a-2)a2+a-5a+4(a+2)(a-2)a(a-2)\+3>2£1¤x-1ஹcḄ(¦ᙠᦪ—T--x^>-22_J—,1.1—I—A.-2-101234;1¨..©B.-2-101234C.-2-16~I~2~3""4^D.-2ª0~~1~~2~34>ூᑖ᪆௃ᐜP«¬£1Ḅ(¦P£1¤Ḅ(¦ᙠᦪ⊤¯£1¤Ḅ(¦ᓽ&.fx+3>20()*xு-2ঝ'(£1জ²X2-1,(£1ঝ²x<3,ᡠµ£1¤Ḅ(¦-lWx<3,ᙠᦪ⊤¯ᩭX:-2-10~1~2~34^ᦑ⌱)B.Q45⚓/T64⚓

457.᝞
¸¹/BCDENC/QḄtᦪX()ூᑖ᪆௃✌ᐜ&᪷¸¹ᑁ¼½¾1P«¬ᑁ¼ḄtᦪᯠLPNC43½/D4E,ᓽ&PNC4O.()᪷À¹ᑁ¼½¾1&²¸¹/8CCEḄᑁ¼½=180°X(5-2)=540°,ᑣ—=108°,5᪷¸¹ḄឋÁG4Bg/\AED,.ZCAB=ZDAE=^-(180°-108°)=36°,2.♦./C4D=108°-36°-36°=36°,ᦑ⌱)C.8.ÂÃ<”¨ᐗAÆf+x-2021=0ḄǬÈᦪ᪷ᑣÉᦪ1/+2<+"ḄË£Ì()A.2019B.2020C.2021D.2022ூᑖ᪆௃᪷¨ᐗAÆ᪷ḄÍβᑮ+Ð=2021,ᑣ+2<+஻=2021+<+஻ᑭᵨ᪷@9ᦪḄᐵ9²ᑮ<+஻=-1,ᯠLᑭᵨᐰÉᐭḄJK.()•.”?¨ᐗAÆ/+Ö-2021=0ḄÈᦪ᪷-2021=0,)஻[2+<=2021,m2+<+<+஻=2021+<+஻•஻?n¨ᐗAÆx2+x-2021=0ḄǬÈᦪ᪷஻7+஻=-1,஻?2+2஻7+஻=2021-1=2020.Q46⚓/T64⚓

46ᦑ⌱)B.9.᝞
×ÃØZ5C.(1)µÙ/XᙊÚµ〉ÜXÝÞßàáZCÌÙM,ZABஹN.(2)ᑖⵓNXᙊÚµᜧÌḄXÝÞßàÇàᙠ/ᔊ1CḄᑁæ;áÌÙç.2(3)èéêZPáBCÌÙD.(4)ᑖâµ4஺XᙊÚµᜧÌL஺ḄXÝÞßàÇà;áÌG,஻ÇÙ.2(5)èëêGb,Z4C,ZBᑖâÌÙE,F.᪷µè
j/ç=2,CE=3,BO=2ᑣ8Ḅ()2A.—B.1C.2D.4104ூᑖ᪆௃ᑭᵨè²4)ìᑖN8/C,£çᚖëìᑖ/஺ᡠeNE4D=NE4D,EA=ED,FA=FD,ïðñ¹/EOFXò²ᑮç=2,ᯠLᑭᵨì"êᑖêóᡂõöÍᳮJKCDḄ.()ᵫè²4஺ìᑖN8/C,Eøᚖëìᑖ:.NEAD=NFAD,EA=ED,FA=FD,EA=ED,:.NEAD=NEDA,.ZE4D=ZEDA,.DE//AF,4ᳮ&²4E஻஺çñ¹AEDFXì"ñ¹,*EA=ED,Q47⚓/T64⚓

47ñ¹/EZ)/Xò,.AE=AF=2,

48$:ᵨGHIᦪJ⊤L61000()0,Ii6.1X106,ᦑ!ᫀ:6.1X106.12.᝞klmn/3CZ)NBAC=NDAC,o⊡ᐙ1/ᩩsAD=AB(!ᫀt)vG4BC/A4DC.ூᑖ᪆௃?⚪1⍝xyzḄ᪗⚪!ᫀt|◤~ᔠᐰnḄᑨPPᳮᓽ.$%Ḅᩩsᳮᵫ%ᙠZBC4CCAC=AC

49Dூᑖ᪆௃᪷⚪i±ᔠ〉Ḅ³´µᓽ¶஺EḄ¸ஹḄ¹ᦪᯠ»᪷knᨩ©ªᑖḄ☢¬Z3CḄ☢¬½¾Ḅ☢¬ᡧnBODḄ☢¬ÀÁ¢$!?⚪.$Â஺iZ)E_L8cE,ᙠÈ8cZABC=90Q,AB=2,AC=4,,1•sinC=^-=T=y5C=VAC2-AB2=V42-22=2V3'.,.ZC=30",.NDOB=60°,0D=,BC=aP.DE=^~,2_;.ᨩ©ªᑖḄ☢¬%8x2X2Í-8x«x—Ï-xm=Ð1-2L,22236042ᦑÒ.4215.᝞k;Ôᦪ᜛;1+ᔊ""#஺)ḄkØ_xÙḄÚ¥Ù§X4ÛÜÙµx=l.Þ☢ßà%জabc<0ঝ2a+b=0dঞ3a+c>0dটç(a#0)èᨵ1/᪷ᜧ-1ÐB0.-50⚓/g64⚓

50ᐸÚOḄজফট.í|îூᑖ᪆௃᪷⚪ᦪkØ¢ᑨïᔜ/B⚪Ḅßàñᔲᡂó?⚪¢ᜐᳮ.$%ᵫkØa<0,b>0,c>0.ᑣobcVO,ᦑজÚO;2a:b=-2a,2஺+6=0,ᦑঝÚOd••ᦪkØ_xÙḄÚ¥Ù§XᙠXí2,0îí3,0îùúÛÜÙµx=l,...ᦪkØ_xÙḄû1/§XᙠXí0,0îXí-1,0îùúᦑটÚOd••2x-15y=a-b+c<0,.\y=a+2a+c<0f.3a+c<0,ᦑঞ┯ýdᦑজঝট.ஹ$!⚪%?ᜧ⚪ᐳ7B⚪ᐳ55ᑖ஺16.í5ᑖîþÿ|&-l|+cos45°-V2["gூᑖ᪆௃᪷Ḅᦪ᦮ᦪᢣᦪ!"#᪷$Ḅᓄ&'(ᓽ*.,-$=&-1+02--=+2&22A/2=11+23+2424=-1+5᝞•17.7ᑖ9᪥;<,=>?ᐜABCᏉEFGHIJK

51PQXYZᑴ<\]^Ḅᩩ`a'bcᡧ`a'befghᑡᡂk.2------------°RSTST]^_`ᡂb1ᙠm#nopᡠᙠᡧ`ḄᙊsḄtᦪu108°c2e⊡ᐰᩩ`a'bx3yz᪥=>?ᐳᨵᐜA1200}ᑣ'z᪥“”Ḅ}ᦪu510}x4“\”Ḅ3ᐜApᨵ2ᵱAஹ1᝕A᝞YpHIJKMNBOQeᵨᑡ⊤ᡈ᪛bḄJᑮᵱAḄᭆ᳛uூᑖ᪆௃1ᵫ360°¡¢Ḅ}ᦪᡠᓰḄ¤¥ᓽ*x2¦m#noḄ}ᦪ;12+30%=40}§¦Ḅ}ᦪ⊡ᐰᩩ`a'bᓽ*;3ᵫz᪥V}ᦪ¡¢“”Ḅ}ᦪᡠᓰḄ¤¥ᓽ*x4᪛bᐳᨵ6©ª*OḄXYJᑮᵱAḄXYᨵ2©ᑣᵫᭆ᳛«$,ᓽ*.,পᙠm#nop“”ᡠᙠᡧ`ḄᙊsḄtᦪu360°X30%=108°,ᦑ108°x2m#noḄ}ᦪ;12+30%=40}ᑣḄ}ᦪ;40-3-17-12=8}⊡ᐰᩩ`a'b᝞hS52⚓/V64⚓

52•Qᦪ86420864°RSTSTf^g`ᡂb(3)'z᪥“”Ḅ}ᦪ;1200x31=510(}),40ᦑ510}x(4)᪛b᝞bBCᵱiᐙ/\AAk᝕ᵱ᝕ᵱᵱᐳᨵ6©ª*OḄXYJᑮᵱAḄXYᨵ2©JᑮᵱAḄᭆ᳛;2=´.6318.(7ᑖ)᝞bRtZ\/BCpN4cB=90°,4C=BC,¼C(2,0),ஹB(0,4),½¤¥ᦪy=K(x>0)ḄbÁ¼4X(1)½¤¥ᦪḄ,᪆$x(2)ÃÄÅᔣÇ3ÈIÉᓫË̽¤¥ᦪy=K(x>0)bÁÇḄ¼(1,஻)m,x஻Ḅ.S53⚓/V64⚓

53ூᑖ᪆௃(1)ÏÐÑ40J_xÔÕ஺×ØÙBOCgZXCZ)/,@A0B=CQ,OC=AD,᪷C(2,0),B(0,4),§Ð(6,2),ܽ¤¥ᦪy=K(x>0)ḄbÁ¼Ðᦑ2=K,x6,§Ý=12,ᓽ*§½¤¥ᦪḄ,᪆$;Þ=12xX(2)¦ÄÅOA,᪆$;*§ÃÄÅOAᔣÇ3ÈIÉᓫËÌᡠ§ÄÅ,᪆$;y=L+஻z,áᵫ¼(1,஻)ᙠ½¤¥ᦪÞ=â=(x>0)bÁǧ஻=12,ᓽÄÅ043xᔣÇ3ÈÉᓫËÌḄ¼u(1,12),ᓽ*¦I=ã..ZOBC=90Q-2BC0=NACD,ᙠÙ50CcÙ(7£/pZB0C=ZCDA=90",ZOBC=ZACD>,BC=ACS54⚓/V64⚓

54./\BOC^^CDA(44S),OB=CD,OC=AD,VC(2,0),B(0,4),••AD--2.9CD=4,.A(6,2),•½¤¥ᦪy=K(x>0)ḄbÁ¼Z,x.'.2=—,,§Ý=12,6...½¤¥ᦪḄ,᪆$;y=â2xx(2)ᵫ(1)§Ð(6,2),ìÄÅ,᪆$;í=îᑣ2=63,§/=—,3ÄÅOA,᪆$;y=1x,ÃÄÅ04ᔣÇ3ÈmÉᓫËÌᡠ§ÄÅ,᪆$;᜛=ð+”,•¼(1,")ᙠ½¤¥ᦪy=12(x>0)bÁÇÄÅ஺4ᔣÇ3ÈÉᓫËÌḄ¼u(1,12),.•.12=´+319.(8ᑖ)᝞b¼Cᙠ¢;ÄñḄ஺஺Ǽ஺u8CḄp¼òó஺஺Rôõö஺஺Õ¼E,0NEBP=NEBC,BPöOEḄôõÅÕ¼P.(1)×PBu஺஺ḄᑗÅx(2)yZC=2,PD=6,஺஺Ḅúñ.S55⚓/V64⚓

55ூᑖ᪆௃1ᵫ43;Äñ*§N/CB=90°,\DhBCiஹ,஺;p¼*§//AC,jkNODB=90°.ᵫOB=OEANOEB=NOBE,\NOEB=NP+NEBP,NOBE=NOBD+NEBC,ᡠeNP+NEBP=NOBD+NEBC,\4EBP=ZEBC,ANP=NOBD.üZBOD+ZOBD=90°,Ü*§NBOO+NP=90°,ᓽ/஺8ý=90°.ᑣ*×P8;஺஺ᑗÅx2ᵫ1*§8=1,Üý஺=7,*×ØÙ8஺ýþZX08P,ܧ¤¥BP=DP,,OPBP§8ý=/4ᵫÿ
ᳮ05.1••18AZACB=90°,\DhBCi,஺Z8ᦑOO=_^ACOD//AC,.ZODB=ZACB=90°.'0B=0E,.ZOEB=ZOBE,\,:N0EB=NP+NEBP,N0BE=NOBD+NEBC,.ZP+ZEBP=ZOBD+ZEBC,\NEBP=/EBC,2P=20BD.,:/B()D+4OBD=90°,:.NBOD+NP=90°,.ZOBP=90°."56⚓/%64⚓

56'OBᦑ)8*஺஺Ḅᑗ-.(2)'AC=2,ᵫ(1)2OD=£AC=IPD=6,.PO=PD+OD=6+[=7.VZP=ZP,NBDP=NOBP=90°,BPDPᓽ8)=0)•஺)=7X6=42,A=jOPBP.BP={^.-•OB-{op2-Bp2-V49-42-V7•ᦑ஺஺Ḅ20.(8ᑖ)CᖪEFGᵬஹJKLᖪMᐳ100OᐰQRSTᵬᖪMᐳUᑭ900ᐗJᖪMᐳUᑭ400ᐗᵬᖪMXJᖪMYOZUᑭ5ᐗ.(1)ᵬஹJKLᖪMYOᔜUᑭZ\ᐗ](2)ᵬஹJKLᖪMᐰQRST^ᖪE'FG_ᢇᵬᖪMᙠbYOUᑭcdḄefghᙳYᜩᓬl100O.᝞n᦮pqYrp1ᐗhᙳYᜩZᓬl20OsturpZ\ᐗv^ᖪEᑭw]ᑭw*Z\]ூᑖ᪆௃(1){ᵬLᖪMYOUᑭxᐗᑣJLᖪMYOUᑭ(x-5)ᐗ᪷⚪ᑡlᓽᑖᶇ᪷(2){ᵬLᖪMrpaᐗᑣYᜩZᓬl20aOᑭwwᐗ᪷⚪ᑡlᦪ᪆"57⚓/%64⚓

57᪷ᦪḄឋlᦪḄᨬ.1{ᵬLᖪMYOUᑭxᐗᑣJLᖪMYOUᑭX-5ᐗ᪷⚪2900400=100,+xx-5᦮ᳮ2X2-I8x+45=0,2x=15ᡈx=3x=15*bᑖḄᔠAx-5=15-5=10ᐗᵬLᖪMYOUᑭ15ᐗᑣJLᖪMYOUᑭ10ᐗ2{ᵬLᖪMrp஺ᐗᑣYᜩZᓬl20஺Oᑭwwᐗᵫ⚪2w=15-a100+20஺=-20a2+200a+1500=-20a-52+2000,Va=-20,ua=5vᦪᨵ*2000ᐗurp5ᐗv^ᖪEᑭwᑭw*2000ᐗ.21.9ᑖẆ¢£¤¥¦ᡂ¨Ḅ©ª«¬*£¤¥¦ᡂ¨®ᓄh☢¥¦ᡂ¨.1▅²ᩞᧇ£¤¥¦µc¶·¸ch¹ḄKᩩ-ᡠᡂḄ¼½*¾-h¿Àᐸ¶·ᡠᡂḄ¼.Â᝞äZBCD-HB'CD'¥1,ᵫÅᙠh☢44'CCCC'//AA,AA,Ƕ·ÅÈᡠÉ-48ÇA4'ᡠᡂḄNB44'½*µc¶·¸ch¹ḄKᩩ-Ë8ÇCC'ᡠᡂḄ¼.ᜐᳮᡂ¨᝞¥1,ÍÎä/BCD-"B'CD',µc¶·¸ch¹ḄK-Ð4'ÇZCᡠᡂ"58⚓/%64⚓

582᝞¥2,M,N*ä¶ÑKÒ☢ÓḄজgᑡᵬஹJஹÕÖÒ¥¦×⌕_Ò¥¦ÉÙ¥2ḄÚÛ¥ÜÒ¥¦*Õঝᙠᡠ⌱ÃßÚÛ¥àMᑮZ8,8cḄäåᑖæ*2ç5,NᑮBO,8CḄäåᑖæ*4ç3,)*Ó_èPM+PNḄᨬé.ூᑖ᪆௃1᝞¥1êëBC'.ì/'BC'*íîÖ¼¦ïlC=60°,ᵫ⚪ÎNC'A'8*Kᩩ-/CÇ3HᡠᡂḄ¼.2᪷£¤h☢ÚÛ¥Ḅᱯòᜐᳮᡂ¨ᓽ.3᝞¥ÕÙNᐵÅ4DḄôõK,êë·4DÅ)êë)N,÷v)M+PNḄᨬéᨬé-øA/KḄùúÙM/_LNKÅ/ᑭᵨý
ᳮlMKᓽ.1᝞¥1êë8C'."59⚓/%64⚓

59BC*íîÖ¼¦:.NBA'C=60°,'AC//A'C,:.oCA'B*Kᩩ-/CÇ8/'ᡠᡂḄ¼,K-8/'ÇZCᡠᡂ¼60°.(2)জþÿ

2Ḅ,ᦑ.ঝ᝞Nᐵ4DḄK,"K49P,PN,M+PNḄᨬᨬ!"KḄ"MM_LNKJ.ᵫ⚪%ᙠRtZXMKJNMJK=90°,M7=5+3=8,JK=8-(4-2)=6,/.M/f=^j2j2=^g22=10,H+K+6M+/WḄᨬ10.22.(11ᑖ)᝞*-■|.+>|ᑖ1x2ஹ424B,"ZḄ5ᱥ-j/c7x2Ḅ89C,7y2஺(0,3),5ᱥḄ2//I஺E,OE=60⚓/?64⚓

60@8.(1)C5ᱥḄD᪆.F(2)CHIOEVAB-.(3)P5ᱥLḄ9M*஺4஺OᔲQᙠR᪵ḄP,TU40,"⚔ḄXY
7Z/C஺\]^_QᙠCPḄ`ᙶ᪗I_cQᙠd▊fᳮᵫ.ூᑖ᪆௃(1)᪷k*l=-*+ᔁᑖ1x2ஹy24,B,Cr/ஹ5Ḅᙶ᪗tᑭᵨwxyᦪ{ᓽC}~ᫀF(2)ᵨwxyᦪ{Cr*ZQḄD᪆.y=-x+3,}rEQ,2),ᵨXYᦪx}rtan/O/B=tanNOEG,}NOEG,ᓽH}F(3)ᵨwxyᦪ{Cr*CZ)D᪆.y=3x+3,᪷kU/,0,஻⚔ḄXY
7Z/CZ)\]ᑖIজZZQMsZ/CDZAOM=ZACD,}rOM"CDஹ}r*ḄD᪆.y=3x,t5ᱥḄD᪆.y=-/+2x+3,ᓽC}Ḅ`ᙶ᪗Fঝᑭᵨ=⇪Cr@M,C}MḄᙶ᪗}rAOAD*@ḄD᪆.ᓽC}~ᫀ.DIপ•.•*-£+¤ᑖ1x2ஹy2ᨴB,.A(3,0),B(0,3),2•.,5ᱥy=-/+6x+c/(3,0),D(0,3),(o.0=-3+3b+c[3=-02+0+C)D}:«=2,Ic=3=61⚓/?64⚓

615ᱥḄD᪆.y=-f+2x+3F(2)•-X2+2X+3=-(x-1)2+4,.♦•5ᱥḄ2*x=l,°*ḄD᪆.y=fcr+a,²/(3,0),D(0,3)³ᐭ,}I3+b=0,lb=3D}I1,lb=3*ADḄD᪆.y=-x+3,.E(1,2),VG(1,0),NEGO=90°,tan/OEG=5>=LEG2V0/1=3,OB=—,ZAOB=90°,23_tanZOAB=-^-=—=—,OA32tanZOA3=tanNOEG,PNOAB=NOEG,'ZOEG+ZEOG=90°,./OAB+/EOG=90°,ZJFO=90°,.OEVABx(3)Qᙠ.'A(3,0),5ᱥḄ2*x=l,.C(-1,0),.AC=3-(-1)=4,,OA=OD=3,ZAOD=90°,•'.AD=y[2PA=3&,°*CDD᪆.l=½¾+஻=62⚓/?64⚓

62VC(-1,0),D(0,3),.f-in+n=0"ln=3D}I"3,ln=3*CDD᪆.y=3x+3,জZAOM=ZACD,᝞2,.OM//CD,À*OMḄD᪆.᜛=3x,5ᱥḄD᪆.y=-f+Zx+B,}I3x=-X2+2X+3,D}ÂÃZHX2=2Æ22ঝZ4WOsZ\/c஺᝞3,.AMAC="AOAD'„==_^J_=2&,AD372"MMG_Lx2G,ᑣN/GM=90°,,ZOAD=45°,.AG=MG=AM-sin45°=2&XÎ=2,.OG=OA-AG=3-2=1,.M(1,2),°*0MD᪆.=ϲM(l,2)³ᐭ}I1=2,*OMD᪆.y=2x,5ᱥḄD᪆.Ð=-f+2x+3,}I2x=-X2+2X+3,D}Ix=ÃÑÒLᡠÔPḄ`ᙶ᪗ÃÕᡈᓰ2^.=63⚓/?64⚓

63=64⚓/?64⚓