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17Tcos3=mgÙ²Rt=^-COS0«Àᙽ᪷HÊ⊝ᩩͪÀᙽOᑮḄ᥅QRfÑ=2mgsin45°-T'=.mg--cosÚᯠ9=45ᑣ¾=0,Ü 45@ᳫÝ MØ⌲ß·@àá@ᑣâm☢ᔣ%ã⌲ß]ᜧᦑ⌱⚗CD9:ᦑ⌱ACD„13.ACDூ=>A.äᨽ.ᦣèÉéêᵫᱥìᑖ²ḄílᑣḄãᒓïðØé¤ñØᨵᐵñØáòáóïᦑA9:B.ôᨔöôı᪵ᐹᨵvឋùᐸᐝüឋì¤ýþᨔįÿᐹᨵᔜᔣឋ⁐ᨔᘤᑭᵨᨔḄᐝឋᐹᨵᔜᔣឋḄᱯᦑB┯C.Ḅᳮ!"ᢝ$%&'()ᓣ+ᑖ-Ḅ.ᙳ01'ᜧᑣᓫ567ᑁ!ᑖ-9ᓫ5☢;<ᘤ=Ḅ>?@ᦪBCᦑcDED.()FGஹFIḄJKLJḄᑖ-ᦪMNOPᙳQRSᳮ!ᑣJḄᑁ1TLḄᑁ1ᜧᦑDDEE.ᑗVWXYᨵᐵḄ[\]^_`ᔣḼᑖ-Wb0cdឋefḄgᔣhiḄᦑE┯ᦑ⌱ACD14.ABDூmnA.&G⚣᳛ḄrᙠtuF⍗wxfy&w\z{Ḅ|}XYᦑA┯~ᔠ⚪B.\z|}Ḅᩩ`⚣᳛FG+⚣rK⚣r⚣᳛&GF⍗6&1\z|}XYᦑB┯~ᔠ⚪C.⚣᳛r<᧕\zXYᡠ⚣rT+⚣r<᧕\zXYᦑCDE&~ᔠ⚪D.&G⚣᳛ḄrᙠGuF⍗6⚣᳛ᙳ&w\zᦋ'ᦑD┯~ᔠ⚪E.ᑗr1\zK|}|}`rᱯᨵḄXYᦑEDE&~ᔠ⚪ᦑ⌱ABD
1815.7.884##7.882##7.883##7.885##7.886B¡;ᔆeᜧூmn(2)[1]¨⚪©ᳫḄ«¬Sd=7.5mm+38.4x0.01mm=7.884mm(3)[2]ᙠ²6³©ᳫ´µ67¶·¹ᐜ»¼©ᳫᨵQ1w½X67¾¿&ÀᡠÂᐜÃÄᦪÅÆ6ᘤÇ»¼©ᳫᦑ⌱B(4)[3]¨⚪©ᳫᔣ´ஹᔣÈᐜÉÄ]ᐝᵯË6ḄÌ)ᑖÍSᑓஹÏ2,ᑣᨵdV=?dV1~hᑣ©ᳫVấÔᩞᧇ>?]^u1Ḅ×ᜫSAE=—77?v.2-—mv^=—w(—)2-—w(—)2222^2t2(5)[4]Pà+ᐝᵯËḄ+)Nàá©ᳫwâᔊNᜧḄtuäåᡠéweᜧ³têëæçḄ²è5(a-b)ூmn(1)[2]᪷íᵯîïðᱥòóïïᡠ:(2)ফ³²⁚|ᵯ÷Ḅᵯ0øùS1.5V,|ᵯ÷ḄᑁêùS3C,³ûᵯîḄᨬᜧᵯýùSE/=—=500mA³û⌱A2^]ᜧ³û⌕⌱Aiὶᵯᦋᵯ⊤ᓽᑣᵯ⊤⌱A”[3]ᘤ&ᜧᑣᘤ⌱R/#ভᵯ⊤Ai%&3mA,ᑁ*199⌕/Aiὶᵯᦋ0*500mAḄᵯ⊤᪷5ὶᵯ
197ᑖᐵ:;⌱&<=/ᵯ⊤Aiᦋ*600mA%&?@AB⌕CD3E[5J[6]ᵯ⊤Aiᑁ*199Gᵯ&1Q,IJᵯ⊤ḄKᦪ*/,ᑣᵯ7MḄNᵯ*200/,ᵫQᔠᵯ7ḄSTGUU=E-200rIᵫVWXE=aa-b|^=200r=—cxlOf;5(a-h)r=------cQ17.(1)'ᵨ#(2)12m/s#(3)66Nூnf(1)A3\y#=2axllf;a.=-m/s213(2)A8\f;9=3sBC\12/uvw+ὡz{a=2m/s22C|Ḅ}~ᜧu=ᓃ+at=12m/s22D3EᙠBC\ᨵuGUmgsin3-F=maf2f;6=66N
2018.(1)<(2)v=y/3gR<(3)y2=6Rx0ூnfD1EᳫAᑮ8,᪷5%ឤGU;Ep=g?=gmgRD2Eᳫ8ᑮ0,᪷5Gᳮᨵ-mgR+qE-.R=gmvg—gmv1f;D3Eᳫ|}~ᔣᵯᵨ/ᵯᑖfᑮxyᑣxᔣᨵ9Ecos45=maxᔣᨵqEsin45-mg=ma,f;¡¢ᳫ0|£¤<=Ḅ*xᔣ¥¦}~*§Ḅᒴ©}ªyᔣ¥ᒴ}ªᓽ¥«¬ᑣᨵ12x=2gry=V<)tὶ®f;ᳫ|=Ḅ¯°&j2=6Rxl.²²kL0v.2+2Z/£LCOS0L19.(1)F=mgsin0+jLimgcos0#(2)«=—#(3)S=~~—--------T--2m2(gsinµgeos)2ூnfD1E"¸ᩈº»ᑮᨬᜧ}~ᐸ©}~*§J¾¿¾Ḅᜧ*F,ᨵF=mgsin0+/.imgcos0D2EᩈºᙠA|JÁ¾¿ḄÂÃ%*ᑴᵫuGUᨵkx-mgsin0-/jmgcos0=malᩈºᙠB|JÁ¾¿ḄÅÆ%*X2,ᵫuGUᨵkx+mgsin0+2gcos0=ma2
21AஹBÉÊ*Lᨵxi+x=L2ὶ®;(3)ᵫv—fVWX¸ᩈºᑮAஹBḄM|ᜐᙠ0ᑮÌ\ÍᑁᎷJ¾¿Ïᩈº¥ḄÐ*WN,ᵫGᳮᨵW-mgsin--fjmgcosµ=—mv^-0NᱥᙽᙠCᜐ£¤ÓᎷJ8ஹCÔ|ÕÍḄÊÖ*S,ᱥᙽÓᑮAஹ8ḄM|ᜐḄ}~*ᵫGᳮᨵ?g(s+×L)sin6-+=-0¸ᩈºØᱥᙽÙz¾ឋÛÜÝÞß☢ᔣ*áᔣᵫ%ឤGU%ឤGUᨵmv-mv=-mv+mvt2t21->I2I1z2—mv<+—mv=—+—mv22/'=%ã'=4ᓽᩈºஹᱥᙽÉÛ=äᣚ}~ÉᔣæçᩈºÛ=£¤Þß☢ᔣÓᑮA|Ḅ&ᵫGᳮᨵ-%+mgsinéµ/jmgcos6é=0ὶ®;+2/jgLcos0L2(gsin6-geose)220.(1)p=100cmHg#(2)31cm2ூnf(1)ÏAêëẆí£¤êîÂïPi=75cmHgJ᎔ᐭòó=AêëêîḄÂï*“ᓄ=AêëÆ*L᪷5⚪öᨵL=9cm2ᑣ
22pLS=p?L2sf;p=lOOcmHg22J᎔ᐭḄòóëÆ*Lem,᪷5Ḅ¬⊝ᨵp+//cmHg=p02%=25cmᓽøùM᎔ᐭḄòóëḄÆ*L=11+2(4—L,)=31cm21.(1)BEஹ;ফ-ூnfD1ᵫᢚûGUᨵ,sin/sinrXüᐭûýiþᢚûý/ÿ ᦑEᔣB☠2᪷⚪/=ាᨵᐝABᐝᙠE!"ᐰ$ᐝ%&&ᡠ)*+,-.C,ᑣᨵᵫ12ᐵ4ᐝᙠ3Ḅᢚ-.r=9O°-2Csinrsin(90°-20cos2C7ᨵcos2C=cos2C-sin2C=1—2sin2C
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