河南省名校联盟2022-2023学年高三上学期摸底联考文理数试题及答案

河南省名校联盟2022-2023学年高三上学期摸底联考文理数试题及答案

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98.ᦪG᜜=☘ḄᜧKX-T1sin(a+Y9.tan஺=2,T----------=mtan2a,[!!msin(a-gA-2B-A4-fcu—9D-i10.ᦪᑡda"fghᓽ=1,jklḄn€N"oᨵa”+i=a,+”+l,ᑣs஺=A.36B.45C.55D.6611.z{|}~ᩩᚖḄᑖᱥ᜛2=2:A,B~|A,Bᙳᙶ᪗{|ᔠC/%ᱥḄᯖ|FᑮABḄᨬᜧ3,ᑣp=B.2C.3D.612.ᦪ%C=¥/ᐵYḄ“'=ᑭᨵ-Ḅ᪷/ᑣmḄ¢¤¥A.-8,e--B.§—^,+8CC.-8,©-eCD.ª-e,+8C«ஹ®⚪:°⚪ᐳ4±⚪,²±⚪5ᑖ/ᐳ20ᑖ஺13.ᔣ´a,bḄᜳ·120°,T|஺|=1,|"=4,ᑣQ-b=.f3%+y<6,14.Y0gh½¾ᩩᵨᑣz=2x+yḄᨬᜧ__________.1'1«1,15.%Â=12%+mÃ3/=/'2ᑗ/ᑣm=.16.ᙠ-Æ┵D-ABCÈ,CD_L8☢ABC,AC_LBC,AB=BD=5,BC=4,ᑣÊ-Æ┵Ḅ᜜ËᳫḄ⊤☢3.ூ6-᥎8ὶὃ•ᦻ=ᦪ>@2⚓ᐳ4⚓C௃G

10-ஹÎÏ⚪:ᐳ70ᑖ஺ÎÏÑᑏÓᦻÔÕÖஹ×ÖzᡈÙÚÛÜ஺@17~21⚪Þὃ⚪/²ß⚪ὃàoÞá}Ï஺@22ஹ23⚪⌱ὃ⚪,ὃà᪷ã⌕å}Ï஺'CÞὃ⚪:ᐳ60ᑖ஺17.°±⚪gᑖ12ᑖCæABCḄᑁ·A,B,CḄjèᑖa,b,c,Tsin2A+sin2C-sin2B-sinAsinC=0.পåBêফ%e=4,åtanC.CL18.°±⚪gᑖ12ᑖC᝞/ᙠ-ÆìABC-AiBiGÈ,AC=BC=l,AB=V?,BiC=l,BiCJ?F^ABC.D×Ö:ACJ_ð☢BCGBiêফå|Cᑮð☢ABB-Ḅ.19.°±⚪gᑖ12ᑖC*ñòóôõᑴ⌼øù,úûüýὅÿᐸḄ,ᐗᨴ,ᙠ,!"#$%〉'()Ḅ⊡+.-.Ẇ0᪀23Ḅ45ὅ7⊡+()Ḅ8ᳮ⚜;<=>?᪵.ABᐸ᪵C⚣᳛ᑖGHIJ᝞JᡠM.N1PQRᦪaḄ

1120.(C⚪ᑖ12ᑖ)3dFd)ᙊc£+£=l(a>b>0)ḄᯖddM(£¤ᙠᙊC¦.(1)QᙊCḄI§U(2)¨H©IªᙊC«¬]ḄA,B°d±᝞+4B=—1(O´ᙶ᪗·d)QH©I¸᳛Ḅw<º.21.(C⚪ᑖ12ᑖ)3»ᦪ/(x)=^-x2—(a+l)x+alnx.(1)'a>lÁQ/(H)Ḅᓫ.abU(2)'aVl±aWOÁ¨Å!ᨵ°ÇdQaḄw<º.(È)⌱ὃ⚪:ᐳ10ᑖ஺Ìὃᙠ22ஹ23°⚪cÎ⌱⚪eÏ஺᝞ÐÑÒᑣᢥᡠÒḄ⚪Xᑖ஺22.(C⚪ᑖ10ᑖ)⌱Õ4-4Öᙶ᪗תØᦪI§(x=l+3cosa,ᙠHÛᙶ᪗×xOycÜ©MḄØᦪI§´Ý(a´Øᦪ).ᙠÞ·d´᩽dàáâã[y=l+3sinaá´᩽áḄ᩽ᙶ᪗cH©IḄ᩽ᙶ᪗I§´çNos®+£)=m.(1)QÜ©MḄëìI§íᢣïÜ©MðñÜ©U(2)¨H©IªÜ©Mò«¬A,B°d|AB|=4,QmḄ<.23.(C⚪ᑖ10ᑖ)⌱Õ4-5Öôõ⌱ö÷»ᦪ/(H)=|H+1|+|H—a].(1)'a=lÁ,Qᐵ¬úḄôõf(ú)>3ḄüýU(2)¨/(x)<4ᙠ[0,2]¦ឤᡂaḄ.ூ᥎ὶὃ•ᦻᦪ4⚓(ᐳ4⚓)௃G

12./ᦻ1ᦪ34ὃᫀஹ5678ᑖ:ᑣ5+i(5+i)(1+i)4+6iτ.1.AT^i=(i-i)(i+i)=^-=29+3Q1-2.A-=,1,2},5={"|04$41),ᡠ&4ᡠ8={0,1}.3.CV/?=2=4n,5>4<),3=«>O,c=lg0.3V1g1=0,.\cᵫ?@AஹCᙳ2,4ḄA0=EF?@AஹCᙳ1,4ḄA0=GᒕIḄJᑖ,L:;<=Ḅ⊤☢O2X2X2+2X4X4—1X1X2=38.1R18.B•.•/Q?3R=?/QSR..,./Q3R᜻Uᦪ,᣸◀XQ.$/QᓝR=?Z>?0᣸◀\R.ᦑ⌱_`(siria+cosa)s♦inn(a+)L_sinqrcosa_tana+1_,_1_4i_99.A----------7—3n,tano2a-----r-5"entlm—•/\J2sinQ—cosatan«—11—434smீa-b)c(sina—cosa)10.Cᦪᑡ{a}hij=1,klmnᨵa-i=%+஻+l,ᑣa„+i—a=w+l,ᵫ⌴rst)ua„~a-\innttn~a„-2=??—l,a-2—a“-3=஻-2,…a1—஽3=4,a$s—យ=3,a?—a1=2,ytz{|}ᑖ~)ua“-a1=2+3+4n+…+ᐔ?2~\-n—1+஻ᡠ&%=1+2+3+4++஻-2+஻_]+஻=”(஻21),ᑣ=1)=55.ᦑ⌱C.11.B-ABḄ012=AQR,R-01ᐭᱥ-01u/?-2஻=0,ᡠ&+ᓅ=2ᑗ஻,\1=—2".0A_LQ3,ᡠ&l1/2+ᓅ=0,ᓽᑶ+»1»=0'uM2=—4/2,ᡠ&=2஻,ᡠ&-ឤ¡Q2,0,ᑣᱥ-Ḅᯖ¡Fᑮ-AB¤¥Ḅᨬᜧ2?¨=3,ᓽp=2.12.CQ©R=cª)*Uᦪ/.rḄ9«᝞9ᡠ®=/",g¯=/2?-1=0ᨵ|@°yḄ±᪷,ᑣ²=?1<0,³ᐵµ-rḄ01¶᜜?ង="ᨵ@°yḄ±᪷,ᡠ&¶vow?".ᑣgr+xp—?1>0,u3ீᓝ6e.13.-2a■b=lX4X---=~2.14.7¼½¾¿ᩩÁ⊤Ḅ)ÂÃ.ᵫ9)*Ä-z=2x+y¡Q?1,9Åuᨬᜧ7.15.—18ᡈ14ᑗ¡QÇR.ஹ•=323,332=12,S஺=±2.Ä=2Åy>=6,ᑣ6=24+5,=-18Äm=—2ÅyR=—10.ᑣ-10=—24+?஻7஻=14.16.34ᵫ⚪)*AC=CD=/FK=3,ᦑÊ┵D-ABCḄ᜜ÌᳫḄÎÏÐ=²cÑ=&Ó,ᑣᐸ⊤☢O1rூ᥎ὶὃ•ᦻᦪÕὃÖᫀ1⚓Qᐳ4⚓R௃G

134KX(-^)2=34it.17.»$(1)Vsin2A+sin2C-sin2B-sinAsinC=0,Aa2+c2~lr—ac=O,BPa2~\-c2~lf=ac............................................................2ᑖᵫIêëᳮ)u,cos4?"=W~.............................................................4ᑖZacLXV0Cᑮ/☢ABBA1ḄAB+C“—/[*+8C_L/☢ABCᡠ3BC±AC,BC±BC.11BᑣA&=72,BB1=/2.^AB=72,ᡠ3IA3B)JKLMNOᦑMQ=§X(&)2=g.........................................................................7ᑖVc-MB]A]=2VC-ABB]=2VB[-ABC=2X-^-XB\CXS^ABC=+............................................9ᑖVc-Aiil$Aj="2-•^=~3"X2X-^~•/ABC........................................................11ᑖ}ᡠ3\=]........................................................................................12ᑖ19.;:পᵫ⚪`a,1Xீ0.10+0.30+0.30+a+0.10+0.05)=1,.......................................2ᑖ;a=0.15.......................................................................................3ᑖ(2)/ᙳᦪḄefg+h=1.5X0.1+2.5X0.3+3.5X0.3+i5X0.15+5.5X0.1+6.5X0.05=3.5kᐗ......................................................................................................5ᑖூnM᥎pὶὃ•ᦻtᦪuvὃwᫀy2⚓{ᐳ4⚓}௃G

14*+0.1+0.3<0.5<0.1+0.3+0.3,ᑣᦪᙠ(3,4)ᑁ.=ᦪ+3+ᑣ0.1+0.3+0.3H=0.5,.................7ᑖ33,ᡠ3ᦪḄefg+3.33kᐗ..................................................8ᑖ(3)⊡Ḅᳮ⚜gᙠ3,5)ᵨᑖ᪵Ḅ6\ᑣ⊡Ḅᳮ⚜gᙠ3,4)Ḅᨵ4\+a,b,c,4,⊡Ḅᳮ⚜gᙠ4,5)Ḅᨵ2\+A,B,ᑣ¡ᨵ",஻ு,,(6,d),(6,A),(6,B),,(c,B),(d,A),,(A,B),ᐳ15¥¦§............................................................................................10ᑖᐸ⊡Ḅᳮ⚜g©ᙠ3,4)ᨵ(a,b),(a,c),(a,d),(b,C,(b,d),(c,d)ᐳ6¥¦§ᡠ3ᑮ2\⊡Ḅᳮ⚜g©ᙠ13,4)Ḅᭆ᳛¬=/=᧡...................................12ᑖ20.;)(1)ᵫ⚪a,®ᙊḄ°±²ᯖ>+(±´,0),...................................................1ᑖᡠ3>Mᑮµᯖ>ḄAB¶·+J(2¸2+(+)2++=4,.........................................3ᑖᡠ3a=2......................................................................................4ᑖ7*+஺=6,ᡠ3஺=1.ᑣ®ᙊCḄº+=L.............................................5ᑖ(2)»¼½/Ḅ¾᳛¿ÀᙠÁÂᔠ®ᙊḄÄÅឋa*“*+4*=0,¿Èᔠ⚪`..........................6ᑖᦑ=¼½IḄº+y="+m,A(©,yi)B(jÍ2ᓅ),ty=kjc-\~m,(4஻+Df+8ᔍ஻/+4(஻-1)=0.(e=lᡠ314(Ó±1)...................................................................8ᑖ'—=ᡃ±ÖI=16(4஻±×+1)>0,ÙH="+ᳮ=(A+Ú3+Û&+5=2&+"Ü+3)=2a+ஹ=ÞßX2JC\JC2JC\JCz4(7஻--1)஻1ߟ1ᵫka\+£(â==44+1...............................................................10ᑖᡠ3±-7*+16(4/±/+1)>0,ᡠ34/±4£>0,4ãäå€0)U(l,+8)....................................................................12ᑖ21.;:প/(1)=h-(஻+1)+è=’1)—")(>0)..............................................1ᑖ»a>lÁᵫ/'(1)>0.0<é<1ᡈz>aÍ.......................................................2ᑖᵫ/'(z)V0,lVz

15ᑣ/H=/(D=-a--1-,.....................................................................6ᑖ*+ô”€(0,1),/(")>0,õ/(2)=/±2+1112)>0,...............................................7ᑖᡠ3ö1)=±0±+<0,ᓽ±ᓝ?@A(1,1)ᙊC,3DEḄᙊ.........................................................4ᑖ(2)ᵫ-■:)="?,KL*^cos஺psin᜛-7஻=0,ḄSTᙶ᪗:;y—7஻=0.............................................................6ᑖᙊCᑮS6/ḄYZᔩ'.........................................................................8ᑖ42ᑣ(.)2=32—22,*^=±/1^..............................................................10ᑖ72—2JMV—1,23.!(1)b+1|=<2,l&zVl,................................................2ᑖ2H)1ᡠAij)k3Ḅl(OO,-l]u[Tt+o°]-.................................................5ᑖফb1610,2].ᡠA2+1+]#-a|44,.........................................................6ᑖᓽb-a|W3-x,ᑣ3W-ay3-2x,.............................................................8ᑖᡠAlya=3..................................................................................10ᑖூ{|᥎~ὶὃᦻᦪ%ὃᫀ4⚓(ᐳ4⚓)௃G

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