2023年四川省眉山市中考数学考前信心卷及答案解析

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2023
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12ᑣa+5h>cf•\a+5b-c>0,:.a~3b+c=0,ᦑ⌱C.11.QRq}~ᦪy=a?++c!a,b,cᦪ“WO$-Ḅc.x=1,ᐸ-Ḅbᑖ᝞-ᡠwᑡজlc<0ঝ2a+b=Oঞ-l>0ট4-8+CVOঠ2c-3b>0.ᐸḄUᦪ!$'•.•ᱥ¡¢ᔣwᑣ«'§¨aஹb34,ᑣb>0.ᱥ©yª6«ᑣc>0,.".abc<0,ᦑজ•.•ᱥḄc.x=l,ᑣb¬=1b=-2a,2a+b=0,ᦑঝᵫ-®Rᱥ©xḄ¯ª3#60°-1W±ᙠ2Uª3W±y>0,ᙠx=-1y<0,ᦑঞ┯³X-—1ᨵy—a-b+c<0,ᦑটᵫ2a+b=0,aa=-1,¶ᐭa-b+c<0abᢤ+c<0,2i¸¹2a2c-3b<0,ᦑঠ┯³.º1Ḅ⌱⚗ᨵজঝট.ᡠ¹ḄUᦪ3U.ᦑ⌱B.12.᝞-TḄij4,E8CḄ3¼½8£$ஹAE¾ª63஺¿lj0஺Ḅj!$713⚓ᐳ27⚓

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ḄᙊḄᑗᚖᑗḄᨵᨵᩩᚖḄᑨឋ.!"᝞$%஺஺'(Ḅ)*ᑖ,ᑗAஹB,'(Ḅ)*/0(Ḅᚖ%ᚖ1ᑖ,2CஹD,45஺4ஹOB,7ljOAA.AC,OBA.BD,,JAC//BD,.•.Aஹ0ஹBᐳ%ᓽAB200Ḅ%@A*ABDC2%.".AB—CD=1.5-3.5=4(cm).ᦑKᫀ24ᙊḄᑗᚖᑗḄ;ᨵNᨵᩩᚖ;O16⚓ᐳ27⚓

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AC=4,X20⚓ᐳ27⚓

20•.•3¸#ACEQ¹º3¸#,).DE=AC^4,KCF//DE,:.BCFsBED,).B(2,4).24.(10ᑖ)5GÇÈḄᑮᩭ+ÊSË;ÌÍᩭÎᜧᦋÐ.ÑᨵAஹB9ÒÓḄ5GÔB,ÕÖ×ØÖ᝞⊤ᡠÙPÒÓÖÚÕÖ(ᐗ/)ØÖ(ᐗ/)Ü⃩ÞᔉàÕAஹB9ÒÓÔBᐳáâ32000ᐗ,ÔB├Øᡂåᐳæᑭè4400ᐗ.(1)⃩ÞᔉàÕ4ஹB9ÒÓÔBᔜéê»(2)°⃩ÞᔉëàÕ4ஹB9ÒÓÔBᐳ30ᐸBÒÔBḄᦪì¿é4ÒÔBᦪìḄ2íÄEîïᫀP⃩ÞᔉàÕ9ÒÓÔBᔜéêÇæᨬᜧᑭèᨬᜧᑭèéê»P(1)Ä⃩ÞᔉàÕAஹ89ÒÓÔBᑖ)aஹ6(3000a+3500b=32000((3400-3000)a+(4000-3500)6=4400']P⃩ÞᔉàÕAஹ89ÒÓÔBᑖ)6ஹ4b(2)ÄàÕAÒÓḄÔBxᑣàÕ8ÒÓḄÔB(30-x)æḄᑭè)wᐔX21⚓ᐳ27⚓

21w=(3400-3000)x+(4000-3500)(30-x)=-100x+15000,ÒÔBḄᦪì¿éAÒÔBᦪìḄ2í.'.30-xW2x,÷s10,-100x+15000,k=-100,AxḄøᜧùúû.•.üx=10Çwýᨬᜧþÿw=14000,30-x=20,⃩ᔉAḄ10BḄ20ᨬᜧᑭ"ᨬᜧᑭ"#14000ᐗ.25.(10ᑖ)᝞+1,,ABC.,OCE1#23456.789:(1)ABCDAAACEBᔲᐰE?;ᐰ2=>?@A;Bᐰ2CD@ᳮᵫ.GHIᵨ(2)BஹCஹE4LBᙠNᩩPQRZADC=30°,AD=3,CD=2,S8஺ḄV.(3);8ஹCஹE4LᙠNᩩPQR(᝞+2),W,ABC.,£>(?£■Ḅ3Vᑖ\]1.2,S,ACOḄ☢_`ADḄV./\ABC.1#23456).AC^BC,DC=EC,ZACB^ZDCE=60°,ZACB+ZACD=ZDCE+ZACD,ᓽN8CD=NACE,ᙠ,BCD.,ACEdCD=CEGBCD=Z.ACE>BC=ACe22⚓ᐳ27⚓

22.♦.ACEhBCQ(SAS)(2)᝞+3,ᵫ(1)BCDiACE,.BD=AE,•••OCE#23456AZCDE=60°,CD=DE=2,VZADC=30°,.ZADE=ZADC+ACDE=3Q°+60°=90°,ᙠRtZVLDEdA£>=3,DE=2,.AE=y/AD2+DE2=V9T4=V13,.BD=V13(3)᝞+2,jAkAlLCOmF':BஹCஹE4LᙠNᩩPQRZBCA+ZACD+ZDC£=180°,,,,AABC.,£>n1#23456.".ZBCA=ZDC£=60°,AZACD=60°,Af7ᙠRtZ\ACFdsinNACF=eF5.AF=ACXsinZACF=1X=d).S^ACD=|xCDx/lF=1x2x^=^,e23⚓ᐳ27⚓

2311ACF=ACXcosZACF=1X.13FD=CD-CF=2-^=^ᙠRt"s஺dA£>2=4t+m=w2+(ᔠ2=3,).AD=V3.26.(12ᑖ)᝞+{ᱥQy=a/+bx+2xmLA(-3,0).L8(1,0),ymLCL஺Ḅᙶ᪗](-1,0),LP]e▲ᑁ{ᱥQRḄNLAPஹPCஹCD.(1)S{ᱥQḄ⊤.(2)i36AOCP☢_2m4SLsḄᙶ᪗.(3)জLMᙠ☢ᑁ,COM#>CM]3Ḅ2ῪP5456PᑏᩩḄᡠᨵLMḄᙶ᪗AঝᙠজḄᩩ¢LNᙠ{ᱥQ£¤R!NMNC=45஺PᑏᩩḄᡠᨵLNḄᙶ᪗.¥(1),
,{ᱥQᔊ:+2xmLA(-3,0).L3(1,0),
••{ᱥQḄ⊤]y=a(x+3)(x-1)=a(+2x-3)=ax1+2ax-3a,ᓽ-3஻=2,¥a=—᝕,ᦑ{ᱥQḄ⊤]y=-|f-%+2A(2)OP,°LP(x,-|/N3+2),e24⚓ᐳ27⚓

24+1,/{ᱥQs-1/-1r+2)mLC,.•.LC(0,2),111•:S=Si36-S^ODC=22xOCX|xp|-2XCOX00=4,1?o411-X3X(-5•ᔆ—²³+2)+Q,x2X(-x)N´X1X2=4,8.•.LPµ-1,N¶ᡈµ-2,2:33:জ᝞+2,;LMᙠCD¸¹AM,VZA/DC=90o,.ZMDA+ZCDO=90°,WNCDO+NDCO=90°,.ZMDA=ZDC0,WAD=C0=2,MD=CD,./\MAD^/\DOC(SAS).AM=D0,ZMAD=ZDOC=90°,.•.LMᙶ᪗(-3,1),;LMᙠCQº¹»ᳮnSLAf(1,-1)ঝ᝞+3,e25⚓ᐳ27⚓

25+3•{ᱥQḄ⊤])=N|/N*+2=-|(x+1)2+|A£¤]PQx=-l,...L஺ᙠ£¤R")MD=CD=M'D,NMQC=NATQC=90°,.,.L஺#MAfḄdLNMCC=/AfC£)=45°,.,.ZMCAf=90°,...LÂLC,L᪷ᙠ>MM]PÄḄᙊRLNᙠ>MM1]PÄḄᙊR/MNC=/MMC=45°,Æᔠ⚪È,•.,LC(0,2),L£>(-1,0)).DC=V5,:.DN=DN=V5,WLNᙠ{ᱥQ£¤R.•.LN(-1,V5),LM(-1,-V5)ÉVMC£¤ÊMl•.,LM(1,-1),LC(0,2),PQMC¥᪆]y=-3x+2,x=-1y=5,.•.LN'Ḅᙶ᪗(-1,5),:LMḄᙶ᪗(-1,5),L='(1,-1),LC(0,2),).N'C=710=M'C,WNMCAf=90°,).NMM'C=45°e26⚓ᐳ27⚓

26.,.LW-1,5
Æᔠ⚪ÈÎRᡠÏLNḄᙶ᪗]µ-1,V5
ᡈµ-1,-V5
ᡈµ-1,5
.e27⚓ᐳ27⚓