2023届高考数学一轮保基卷：直线与圆（含答案）

《2023届高考数学一轮保基卷：直线与圆（含答案）》由会员上传分享，免费在线阅读，更多相关内容在教育资源-天天文库。

2023
ὃᦪᔁᙊஹ⌱⚪ᐳ16⚪1.ᙊx2+y2+mx-[=0ᱥy2=4%Ḅᑗᑣm=13A.iB.-C.1D.2242.'(0,1Ḅ*ᙊM+y2=4./481(ᑣI4BIḄᨬ45A.2B.2V3C.3D.2V53.ᙊCḄ9:52,ᙊ;ᙠx>Ḅ?9>@*3x+4y+4=0ᙊCᑗᑣᙊCḄAB5A.x2+y2-2x-3=0B.x2+y2+4x=0C.x2+y2+2x-3=0D.x2+y2-4x=04.ᙊ/+y22y=0Dy=|x|-1ḄFᐳ(Gᦪ5A.4B.3C.2D.05.ᙊ/+I24ᑐ=0ᙠ(21,KᜐḄᑗABMA.x+V3y-2=0B.x+V3y-4=0C.x—V3y+4=0D.x—V3y+2=06.ᵫ*y=x+l@Ḅ(ᔣᙊ0—32+3+22=1RᑗᑣᑗSḄᨬ45A.V17B.3V2C.V19D.2V7.x,y,z5?XᦪᑣYZḄᨬᜧ45A.⌹BWC.iD/52538.(P5^D_3=1஺a0,ᓃa0Ḅcd@(R,F25^DḄfஹcᯖ(.hOP+0^■OP-OF^=0஺5ᙶ᪗k(l|ᡠ|=nᡠ|,ᑣ^DḄo;᳛5A.V2+1B.V3+1C.V6+1D.q9.ᙊC:/+y2=2,*[sx-y+m=0,ᑣRC.Mu2”ḄA.ᐙᑖyz⌕ᩩ}B.z⌕yᐙᑖᩩ}C.ᐙ⌕ᩩ}D.~yᐙᑖyz⌕ᩩ}10.ᙊx-2+y-1=3ᐵ/*3x+5y+6=0ḄᙊḄAB5A.x+22+y+32=3B.%-I2+y2=3C.x+I2+y+4/=3D.x+32+y2=311.ᙊ/+y2+2x+4y-3=0@ᑮ*x+y+1=0Ḅo5V2Ḅ(ᐳᨵA.1GB.2GC.3GD.4G12.*l:x-ky+k.-1=0ᙊC:x2+y2=3Ḅᐵ5AC.BCᑗCCoD.@G⌱⚗ᨵ

113.ᱥCsy2=2px,p>0Ḅᯖ(5F,'ᯖ(Ḅ*/.ᱥCM,N1(MNḄ(5G,ᑣ*஺GḄ᳛Ḅᨬᜧ45()A-TC1D.214.'(2(11,2)ᙊx2+y2+2x-4y-164=0ḄᐸS5᦮ᦪḄᐳᨵ()A.16ᩩB.17ᩩC.32ᩩD.34ᩩ15.(4(3,4)ᙊ(%-2+(y—3=1ḄᑗᑣAᑮᑗ(Ḅo5()A.V5B.3C.V10D.516.ᙊ¡+3=l(a>b>0)Ḅfஹcᯖ(ᑖ¤50,F,PMᙊ@(IP&HPF2I2g0,b>0)Ḅfcᯖ(ᑖ¤MFiF,&55ᙊ;IÀ59:Ḅ2ᙊ^DᙠÁÂ▲./(4,ᙠÁ±Â▲./(8,hIBF2I=4|42|,ᑣ^DḄo;᳛5.19.ÄᙊCsx2+y2+6x-8y+16=0,ᑣᙊ;CḄᙶ᪗5Å4(-Æ0),B(m,0)(m>0),hᙊC@»ᙠ(Q,¼½4Q1QB,ᑣmḄ©4«M.fx—y+2>0,20.'´☢ÉÊy+2NO,ᑁ(PᙊO:/+y2=iḄ1ᩩᑗᑗ(ᑖ¤5A,B,Ì(%+y4-2<0,Í4PB=aÎaᨬÏÐÏ(Pᙶ᪗5.f21.*y=kx+3ᙊ0-4)2+3-3)2=4./”N1(,IMN26ᑣkḄ©4«M.22.XᦪX,ᨴ,ÓÔsÕ+Õ=1ᗲ+×=1+y2=3ᑣØÙ3+2ÚÛḄᨬᜧ45.ஹÜÝ⚪(ᐳ8⚪)23.*(t5ßᦪ)ᙊC:p=2&cos(e+E)(᩽>x>Ḅæç9>èᔠlᓫSëì).(1)íᙊ;Cᑮ*1ḄoÅ(2)h*1îᙊCïḄS5ðíaḄ4.

224.ᙠ´☢*¶ᙶ᪗xOy*ñ'(P(l,0),ò¶5a.k(5᩽(x>?9>5᩽>óô᩽ᙶ᪗DCḄ᩽ᙶ᪗AB5psiMe=2cose.(1)ᑏö*/ḄßᦪAB÷DCḄ*¶ᙶ᪗ABÅফhC./4B1(M5ù4BḄ(l|PM|=|,ísina.25.'(4(0,1),lAᔣᔣû5d=(l,k)Ḅ*ᙊC:(x—2>+(y-3)2=1./yìḄ1(M,N.(1)hk=2ÏíùMNḄSÅ(2)hý•ÿ=12,kḄ.26.ᙊCḄP(k,O),(2(2,0),R(0,l),ᙊCᙠPᜐḄᑗ᳛1,!ᙊCḄ"#.27.᝞&ᡠ()*+,-.᫑஺42ᑜ4567᫑BC,9:;5<ᙊ=*+>2ᑜ⌕@7᫑BCA,BABᚖD)*+>ḄEFᙊGMᙠH஺4-IABCJᑗḄᙊK.᫑LM஺N4ᑮPᙊ-QR5ḄSTᙳVW80m.Z[\)4]W஺^ᓅ"ᔣ60mᜐ)C]W஺^a"ᔣ170mᜐ(OC,B))tanzBCO=(1)7᫑BCḄfg(2)h0MjV9)ᙊ=*+>Ḅ☢lᨬᜧo28.ᙊC@(x-l)2+(y+2)2=20,P(-3,0)ᙊC-5.(1)PḄDZAᙊCJᑗ)DwḄ"#.(2)QyᙊC-5z({WP),PQ|MḄ}~"#.29.ᙊCḄ"#M+(y-4=4,஺yᙶ᪗)D=kxAᙊCWM,N%&.(1)kḄg(2):Q(m,n)yHMN-Ḅ)K=+ᯅ)n⊤(Ḅᦪ.IOQI,IONI"3().ᱥy2=2px(p>0)ḄᯖF,P(p,V2p)\PF\=3.(1)ᱥḄ"#g(2)(-1,0)ḄD/ᱥWA,B%&,h|F4|=3|FB|9)DḄ"#.

3ᫀ1.Bூ£᪆௃ᵫᙊG§5H,஺¨ᑮ©ḄSTªW«¬®E,@|55§51¨|=@°|gᡠ±m=42.B3.Dூ£᪆௃:ᙊCḄᙊGᙶ᪗§Q,0¨,ᑣd=´:;X/4I=2,஺=2ᡈ஺=5¸§¹¨)WyᙊGV3+4/3§2,0¨,ᡠ±ᙊḄ"#§X—2¨2+y2=22.4.D5.Dூ£᪆௃ᙊ/+y2-4%=0ḄᙊG§2,0¨,ᑣ¾9=5¿)1—2ᦑᑗḄ᳛Á)ᵫÂÃᑗ"#y-V3=^§x-l¨,ᓽx-Æ+2=0.6.Aூ£᪆௃⌕Çᑗfᨬ)◤Dy=x+l-ḄNᙊGÉḄSTᨬÊ)ËᨬᓽᙊG§3,—2¨ᑮDy=x+lḄSTd,d==3V2,ᦑᑗfḄᨬyjd2—r2=V18—1=y/17.7.Bூ£᪆௃ÍÎ,y,z^Ïᦪ)ᡠ±x2+1y2>V2xy,z24-1y2>V2yz,ᡠ±Î2+y2+z2>y/2xy+V2yz=V2§xy+yz¨,ᡠ±Ñ?zhKÓhx=z=#y9ª¸)x2+y2+z222,ᦑÕᕆḄᨬᜧx2+y2+z228.Bூ£᪆௃ᵫ§×+Ø•§Æ5Ú¨=0Ã|°|=|ÚI)Û|Ú|=||=c,ᡠ±APF/zDÜÜ=)K|PF2l=c.ᵫÞßàᳮâIPFJ=V3c,᪷åæçḄàèᨵ\PF\-\PF\=2a,12ᓽV3c—c=2a,c=§V3+l¨a,ᡠ±æçḄTG᳛e=-=V3+l,aᦑ⌱B.9.A

4ூ£᪆௃RACJ"=í<ï)£Ã52cm<2.ᡠ±“)ACJ"y“m<2”Ḅᐙᑖô⌕ᩩö.10.Cூ£᪆௃:÷øᙊḄᙊG§a,b¨,fb-l_5ᑣú⚪RÃ|‘ý¥"13x—+5x—+6=0,I22£Ãÿ
ᡠᡠḄᙊḄx+I2+y+42=3.11.C12.Aூ᪆௃:x-ky+k-1=0%ᓄ'x+fc-y+1-1=0,ᡠ+,-./ᦪ1I2341,1.I2+I2=2<3,ᡠ41,1ᙠᙊCᑁᡠ89ᙊC:;.13.Aூ᪆௃<ᱥC'V=2pxḄᯖ4ᙶ᪗'F©,0,E89xFᚖHMNḄK4LMHG9FOᔠ஺GḄR᳛0,E9xFTᚖHU8Ḅ'x=my+l3VᐭV=2pxX'y2-2pmy-p2=0,ᑣ%+ஹ2=2\:,yiyz=-P2<ᑣx+x=myi+`2+P=2pm2+p,r2ᑣMNḄK4GḄᙶ᪗'pm2+^p,pm^,ᑣOGḄR᳛k=14.C15.D16.Bூ᪆௃UFi(-c,0),F(C,0),ᵫjᙊḄ3k%X,IPF1I+|PF2|=2a,2%UIPF2|=t,%XIP&|=4t,ᓽᨵ(
l+l)t=2a……জᵫ4F1PF2=p%XIu&-+|PF\2=4c2,2ᓽ(1+1*2=*2……ঝᵫঝ+জ2,%X02=x.ym=2+l,%X4=m—1,ᓽᨵ02={=|}=2e-+
,d+l)2m2\m2)2

5ᵫ%X!

6ᑣᙊCḄᙶ᪗(-3,4)
U4(¨0),B(m,0)(m>0),©ᙊC|ᙠ4Q,XAQ1QB,ᑣ4BḄᙊªᙊCᨵ;4ᦑ¬ᙊḄᙊ¡ᜧ,ᡈ},®,ᡈ},ª.¯4BḄᙊḄᙊ°4m,ᡠI3-m±“-3)2+42Wm+3,BPI3-m|<5

7ᦑÜMNḄÍ|MN|=2Jl-(-2=â=ã.ᓽ|MN|=ä(2)ᵫ⚪M3NḄl:y—1=k(x-0)=>y=fcx+1.U/V(xy),2,2ὶçè_3)2=1=(1+/c2)x2-(4fc+4)x+7=0.X-L+X=◤%1%2=*./=(4/c+4)2—4(1+42)x7>0=}

8ᵫᩩ4(0,60),C(170,0),BCḄ᳛k=-tanzBCO="±BC$%4B1BC,ᡠ4BḄ᳛/CAB=&♦'BḄᙶ᪗(a,b),()Jk=-ft°-=k=B"Ca-1703AABaa-04*+a=80,b=120.ᡠBC=J(170-80)2+(0-120)2=150.%,-᫑BCḄ/0150m.(2)'123Ḅ45ᙊMḄ78rm,OM=dm(0ᑗᦑM(0,d)ᑮBCḄBC0r,Dn_I3d-68O|_680-3dᓽE=%0FAᑮᙊMGHI"ḄBCᙳKL<80m,ᡠM"◤80'ஹMᓽ(r-(60—a)>80,O-dN80,^^-(60-d)>80.I5*+10WdW35.ᦑPd=10QM=RSᨬᜧᓽᙊ☢Vᨬᜧ.ᡠPOM=10mQᙊW123Ḅ☢Vᨬᜧ.28.(1)ᙊC&(%-1)2+0+2)2=20ḄᙊXC(l,"2),78v=Y%("3—1[+(0+2[=20ᡠP(-3,0)ᙠᙊCGᡠ11PC,%k=?pPCᡠḄ=2,ᡠIḄ9:y-0=2(]+3),ᓽy=2x+6.(2)'M(x,y),ᑣQ(2x+3,2y),

9%QᙠᙊCG`ᐭᙊḄ9:b+(2x+3-I)2+(2y+2)2=20,᦮ᳮ+(]+1>+(y+l)2=5,ᦑPQqMḄst9:(%+I)2+(y+I)2=5(x*3).29.(1)xy=kx`ᐭx2+(y—4)2=4q+(1+/c2)x2-8kx+12=0.(*)ᵫ4=(-8/c)2-4(1+fc2)x12>0,+k2>3,ᡠkḄ0("8,—)u(V3,+a>).(2)%M,NᙠGb'M,NḄᙶ᪗ᑖ(#/)(x,kx),ᑣ2210Ml2=(1+fc2)xf,\ON\2=(1+k2)xj.$\OQ\2=m2+n2=(1+fc2)m2,ᵫ—.—=__I1—+™IOQI2IOM|2T|ONF'B211(1+k2>)m2(1+k2)xf(1+fc2)%^ᓽ211(%i+%2)2—2%1%2■yyj22+222'•it1212ᵫ(*)b8k12X1+X2=iTP-X1X2=iTP-ᡠ⊈2=.%Qᙠy=kxGᡠnk=——.m`ᐭ⊈2=ᑶqᓄ+5n2—3m2=36.ᵫHl?=£஽¥G2>3,b00,ᡠ<0n=mḄ¬ᦪᐵV15m2+180n=-----------,mG(-V3,0)U(0,V3).30.°1±ᵫᩩ᧕P°p,´p±ᙠµᱥy2=2pxG|Pᵨ=¹+஽=º=3,ᦑp=2,ᓽµᱥḄ9:y2=4x.°2±᧕᳛»¼ᙠ'±y=k°x+l±,4°¹½±,3஺2/2±

10\FA\=3\FB\=^+1=3(X+1)....জX12ὶ",¥'"ஹ+42(]+1)2=4%ᓽÃ2/+(242-4)x+42=0,(y=fc(x+1)ᵫ4=16-16/c2>0+1