《光学教程》姚启钧课后习题解答

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26/-50L33=x=133sn'-50114ஹᴻ®ᡂ9ᳫᐸ°᳛9R2CT«஺±²³ᙢµᐭᢚ@᳛L33Ḅ³,¶ḼḄ-/"ᳫ☢⚔8c7஻ᜐḄ³ᨵᱥ5ᑭᵨ¥¹º»¼YḄ½`ᔣᜧ᳛6ºᐝ¾»஺F¿À2s'=-18.5c/?i-18.51.33-----x2.05-8--1.515ஹᨵ}ᙽᴻↈ2ÆḄ}⊤☢ᙳᔜÉᳫ☢½Êᳫ☢ᐸ°᳛9R10cm஺ᱥᙠË-mÆ20cmᜐᱥÆᙳµᐭ³ᑖÍᵨº»¼¥¹¼YḄ஺ᴻḄᢚ@᳛1.5,³Ḅᢚ@᳛1.33஺FA4஻%Uᵫↈ2ÆḄᱥJK-^--ߟ=n—+—-ssrrt2}⊤☢ᙳÉᳫ☢Ḅↈ2Æ1.331.331.5-1.331.33-1.5----------=----------1----------s'-2010-10s'=-40.9c/??

27}⊤☢ᙳÊᳫ☢Ḅↈ2Æ:1.331.331.5-1.331.33-1.5-----------=-----------1----------s'-20-1010s'=-13.2cm16ஹÉ2ÆᙠÓḄᯖ40cm,ᙠ³Õᯖ136.8c/%=Ö2ÆḄᢚ@᳛CD³Ḅᢚ@᳛1.33w?±Ö2ÆCS2CS2Ḅᢚ@᳛1.62w,ᐸᯖÙCDE,f_(n-1.33)40}KÜ2—=----7----=---f_1.33(n-l)136.8FN஻=1.54(2)4=/I,=1.6211_1ஹ4

281J'(஻T)à11.62ᑣf=x40x(1.54-1)=-437.4C/M1.54-1.62

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2c8Ḅ9:;ᓫ=>஺ᨵ0@5A6Bᙠ1()()஺஻ᑮ30()ḄGḄᱥ4஺IJপL05MNOPNQR1S=>Ḅᯖ6UVWফY5A25cmMḄᱥ4R◤[ᡚ]᪵Ḅ1>:প`aMN4=—300cm,=2cm1ᵫ=>ᡂ:-...2__5——300ߟdf_=1.987cm_1_J_`aPN2-100b_f_=1.961cmফ`a25c?n

302__1__J_2^^25=7R'=1.852cmᵫjᐝᐹmnopq"=0mᔠ᦮4:1_11uuv111---=---1----1.852f1.961——=0.030c/n-1(P7y300°)f"3ஹ9᯿o|`}MᱥQR~ᱏ6ᱥ>18a>ᜮᨬᜧyQR~ᱏOᱥ>o620cm,Ḅᱥᙠ>ḄᨬP6Bᵫ⚪᯿o|`}MᱥQR~ᱏ6ᱥ>18c஻z,f'-18cmᵫ=>ᡂ~—=9ssf11_120-7-18S=-18067774ஹjᡠᡂḄ7Y4',ᵨM>ᱥ>᯿oRᡠjNo61R஻RJM>ᱥ>Ḅᯖ6UVW:='I,.180x603.14f'x4'=/,x4x--------=Imm180x60=859.5=85.95cm5->ᐹᨵ:ᱥ>Oj:>஺:ᱥ>Ḅᯖ6ᑖY\6rnm'4mmO1.9mm,j:>Ḅᜧ⚞ᑖY5O1()஺:ᱥ>⌼ᡂḄ¢@£ᙠ6Y160cm¤,J¥>ḄᨬᜧOᨬ¦Ḅᜧ⚞ᔜYWᵫ>Ḅᜧ⚞:

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3230cm80cms'-3020s'=60cmSdR=/dQ=/ÚÛµSY=>Ḅ☢Ü·PNḄNP'ḄÊᐝËy/'Yc3g_3()2—d஺'—D60214ஹ9Y5஻஻஻ḄÞ3ᱥ4ᙠ9᯿o|>ᜮ50c஻?ᜐRᙠ~ᱏßᡂḄY஺à~ᱏÎá1C7”RᑣḄåᦣᦿçyY1mm°I᯿o|>ᜮḄFᦪ஺ysë9ì97

33e50/=Td10ᵫÃíîR=Ód-\cmFᦪ:1=8.33a615ஹïðñᴻᙠ☠PôᐝḄõ⁐÷øÞ(ᐸùᑖY589஻஻?O589.6஻஻?)▬PḄ⁐ᦣ᳛d஻/dgZ-360cnf;ᵫLðñᴻᑴᡂḄ@ᑖüôᐝ÷øÞḄý>R~ºçyþ¦aWH1ᵫ⁐ᑖü⚞P=--AZdAA=589.3஻஻?AZ=0.6nm3°dn-27L16ஹ¿9ᙽᐝ᪕⌕প600஻஻ḄḄ30°,ᑖᐸ().02஻Ḅ(2)⁐ᦣ!ᜧ;(3)$%஺'ᐸ()ஹ(ᦪஹᐝ᪕,ᦪ-.)/஺ᵨ1ᙽᐝ᪕.ᐳ4ᑮ600/7/nḄ6ᩩ89ᵫdsin6=jA.,2x600wn_c/._d>-------------=2400஻<=2.4x1i0r3mmsin30"ᵫ$%—=3,b--d=0.8x103/n/nb3ᵫP=—=jNAA600$.r——=2N0.02N=15000ᐝ᪕Ḅ.)/9L-Nd=15000x2.4x10~3—36mm4sin90"2400Aᵫ/=-----------=-------=44600

344ᑮ0,±1,±2,ᐳ5ᩩ17ஹI⌕JKLᑖMN0.000375P஻ḄQRᵨS550஻஻?Ḅ!Uᐝ᯿W஺X9পYJKLᱥLḄᦪ[\]ফI⌕YQR_ᜧ`ḄaS2',ᑣJKLḄ_ᜧd⚞fghi8:পᵫJKLᱥLḄᑖ᩽▲mn0Ay=0.610—5—nsinu஻sin“=0610x-Oxi஺=08950.0003753.14ফ{⌼}387.725018ஹ~ᜐᩭḄQMN1.5<஺᝞Ḅ\4ᡂḄᙊ\,Xa,Ḅᙠhᜐᑖ'ᐝfgQ஺\Ḅ]S2>mm,ᐝ'ḄᐝḄS550nm஺஻L589U=——L2U=^=0.610—ᑖ'R1.5“Ie%——=0.610—LR^^0,610x550xl°'fflfflLm1.5mmL=6706/n=6.7km19ஹᵨ\]ᑖ¨S20஺஻-160cmḄQ©ªLᔲᑖ¬ᨴᳫ¯]S500mḄ±²³(ᨴᳫ-ᙢ☢ḄN·Sᙢᳫ¸]Ḅ6()º☢ᙢᳫ¸]»S6370k”஺)ᐝ'ḄᐝḄ4S55()஻஺8:U=----———=1.3x10%]60x6370x1()3?\]20c<ªL:

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36Ö×ᐝḄØÙ1ஹXÚmÛ☢QᑡᐝE[=44COS(69/-Zz)+ecoscot-kz--yI2\,71£12=4sin(a)t-kz)+esincot-kz----y2JḄØÙ᝱஺8:জ&=44cos(m_ß)+ecoscot-kz--v2E=4cos("àবvlE=4)coscot-kz--\=A^sin^cot-kz^V12ᨵ9&+&=4Ex=Acot-kz=O(AO)Eஹ=°ᑖ᪆7ᐔ[å=0cot-kz=-(0,A)2SæçèÂᙊØÙᐝ,71ঝ22=4esinீcotàkz)+esincot-kz----xyI2E=A)sin("-■¯)X2E=4sincot-kz----=-4cos(&-Zz)y2ᨵ9ê+&=4

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=73sini,z=30"22ᵫ=tan«=tan¸60—30"D0Atan
IE+ztan¸60+30"P]2sin
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