船舶结构力学课本课后习题答案解析.pdf

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1、目录第1章绪论.......................................................................................2第2章单跨梁的弯曲理论.................................................................2第３章杆件的扭转理论.................................................................15第４章力法.....................

2、................................................................17第5章位移法...................................................................................28第6章能量法...................................................................................41第7章矩阵法.....................

3、..............................................................56第9章矩形板的弯曲理论...............................................................69第10章杆和板的稳定性.................................................................751第1章绪论１．１题１）承受总纵弯曲构件：连续上甲板，船底板，甲板及船底纵骨，连续纵桁，龙骨等远离中和轴的纵向连续

4、构件（舷侧列板等）２）承受横弯曲构件：甲板强横梁，船底肋板，肋骨３）承受局部弯曲构件：甲板板，平台甲板，船底板，纵骨等４）承受局部弯曲和总纵弯曲构件：甲板，船底板，纵骨，递纵桁，龙骨等１．２题甲板板：纵横力（总纵弯曲应力沿纵向，横向货物或上浪水压力，横向作用）舷侧外板：横向水压力等骨架限制力沿中面内底板：主要承受横向力货物重量，骨架限制力沿中面为纵向力舱壁板：主要为横向力如水，货压力也有中面力第2章单跨梁的弯曲理论２.1题设坐标原点在左跨时与在跨中时的挠曲线分别为v(x)与v(x)123px(−l)3px(−l)3px(−3l)3�Mx0Nx�

5、424１）图2.1vx()=++++ll3l2EI6EI46EI26EI46EI23px(−l)3MxNx01�14原点在跨中：vx()=v+++，110l2EI6EI46EI⎧v(l)=0v'(l)=0⎪1212⎨'p⎪v(0)=0N(0)=⎩11223px(−l)3�MxNx�3２）图2.2vx()=θx+++0l2EI6EI36EI33px(−l)3�Nx�xqxdx2３）图2.3vx()=θx++−x0x∫l6EI06EI26EI２.２题33pl⎡1131⎤pl⎡1131⎤a)v=v+v=(3××−)+×(−×2)1ppp6EI⎢164

6、44⎥6EI⎢41624⎥⎣⎦⎣⎦23pl=512EIpl3⎡1⎛91⎞13⎤pl3pl3V=⎢⎜−⎟+()⎥+=26EI⎣416⎝2⎠4⎦192EI96EI2b)v'(0)=−Ml+Ml+2Pl9(1+2)3EI6EI6EI3220.1Pl5Pl73Pl2=−+=6EI327×EI1620EI2−MlMl2Pl9θ()l=+−(1+1)3EI6EI6EI322−0.1Pl−4Pl=−107Pl2=6EI327×EI1620EI22⎛⎞⎛l2l⎞pl2⎜⎟⎜⎟v(l)=⎝⎠⎝33⎠−3⎛⎜1−1⎞⎟⎡m(2−1)−m(1+1)⎤33EIl6EI

7、⎝3⎠⎣33⎦237pl=2430EI4ql473ql5ql4c)v(l)=−=2192EI768EI2304EI2qllql3pl2(16)ql3⎡111⎤ql3'v(0)=−−=−−=24EI16EI6EI8EI⎢3612⎥96EI⎣⎦���d)2.1图、2.2图和2.3图的弯矩图与剪力图如图2.1、图2.2和图2.33图2.1图2.2图2.32.3题1）32Mlql2l⎡l⎤Ml∵θ右=−−⎢(q2−q1)⎥+=06EI24EI45EI⎣2⎦3EI213ql∴M=112032Mlql17l⎡l⎤Ml2）θ=−++lq−03EI24EI18

8、0EI⎢21⎥6EI⎣⎦33ql1⎛11713⎞ql1=⎜−++−⎟=−EI⎝18243606120×⎠80EI2.4题3�Nx0图2.5∵vx()=