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时间:2020-01-11
《哈工大 数电课本 课后习题 答案.pdf》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、【2-1】解:(a)100(b)1(c)10000(d)1043210【2-2】解:(a)(10010)=1××××2+02+02+12+02×2210(b)()110=1××2+12+02×26543210(c)()1011001=1××××××2+02+12+12+02+02+12×276543210(d)(11010100)=1×+×212+02+×××××+×12+02+12+02022【2-3】解:(a)4(b)11(c)0.5625(d)45.375【2-4】解:(a)11100(b)1101
2、00110(c)0.0101001(d)0.01【2-5】解:十六进制(a)12(b)06(c)59(d)D4八进制(a)22(b)06(c)131(d)324【2-6】解:(a)(2118+=)(10101)+(10010)=(100111)10222(b)()5423−=()110110−(10111)=(11111)10222(c)(3211×=)(100000)×(1011)=(101100000)10222(d)(183÷=)(10010)×(011)=(110)10222【2-7】解:原码(a
3、)00101011(b)11111110(c)00001010(d)10100110反码(a)00101011(b)10000001(c)00001010(d)11011001补码(a)00101011(b)10000010(c)00001010(d)11011010【2-8】解:反码运算(a)[00100011]反=00100011[-00010010]反=11101101[00100011-00010010]反=[00100011]反+[-00010010]反=00010001=[00010001]反
4、00100011-00010010=00010001(b)[00001100]反=00001100[-00100000]反=11011111[00001100-00100000]反=[00001100]反+[-00100000]反=11101011=[10010100]反00001100-00100000=10010100(c)[01111100]反=01111100[-01000011]反=10111100[01111100-01000011]反=[01111100]反+[-01000011]反=001
5、11001=[00111001]反01111100-01000011=00111001(d)[00010000]反=00010000[-00100000]反=11011111[00010000-00100000]反=[00010000]反+[-00100000]反=11101111=[10010000]反00010000-00100000=10010000补码运算(a)[00100011]补=00100011[-00010010]补=11101110[00100011-00010010]补=[001000
6、11]补+[-00010010]补=00010001=[00010001]补00100011-00010010=00010001(b)[00001100]补=00001100[-00100000]补=11100000[00001100-00100000]补=[00001100]补+[-00100000]补=11101100=[10010100]补00001100-00100000=10010100(c)[01111100]补=01111100[-01000011]补=10111101[01111100-0
7、1000011]补=[01111100]补+[-01000011]补=00111001=[00111001]补01111100-01000011=00111001(d)[00010000]补=00010000[-00100000]补=11100000[00010000-00100000]补=[00010000]补+[-00100000]补=11110000=[10010000]补00010000-00100000=10010000【2-9】解:二进制数(a)00111111(b)001111001011(
8、c)000101100100(d)01010010.0111十进制数(a)63(b)971(c)356(d)82.4BCD8421码(a)01100011(b)100101110001(c)001101010110(d)10000010.0100【3-1】解:(1)逻辑代数中有三种最基本运算:与、或和非,在此基础上又派生出五种基本运算,分别为与非、或非、异或、同或、和与或非。(2)与运算的法则可概述为:有0出0,全1出1;类似
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