化工原理习题答案(上册)

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1、化工原理习题答案（上册）第一章 流体流动1        PA（绝）=1.28×105N/m2PA（表）=2.66×104N/m22        W=6.15吨3        F=1.42×104NP=7.77×104Pa4        H=0.39m5        △P=2041×105N/m26        P=1.028×105Pa   △h=0.157m7        P（绝）=18kPa     H=8.36m8        H=R  PA>PB9        略10 

2、   P=Paexp[-Mgh/RT]11    u=11.0m/s; G=266.7kg/m2sqm=2.28kg/s12    R=340mm13    qv=2284m3/h14    τ=1463s15    Hf=0.26J/N16    会汽化17    18    F=4.02×103N19    略20    u2=3.62m/s;R=0.41m21    F=151N22    v=5.5×10-6m2/s23    =0.817   a=1.0624    略25    P（

3、真）=95kPa;P（真）变大26    Z=12.4m27    P（表）=3.00×105N/m228    qv=3.39m3/h  P1变小P2变大29    qv=1.81m3/h30    H=43.8m31    τ=2104s32    He=38.1J/N33    qv=0.052m3/s=186m3/h34    qv1=9.7m3/h;qv2=4.31m3/hqv3=5.39m3/h;q,v3=5.39m3/h35    qvB/qvC=1.31;qvB/qvC=1.05

4、;能量损失36    P1（绝）=5.35×105Pa37    =13.0m/s38    qv=7.9m3/h39    qVCO2（上限）=3248l/h40    =500l/s;τ=3×104PaF=3×102N  P=150w41    he=60.3J/kg42    τy=18.84Paμ∞=4.55Pa·s43    τy=39.7Pa44    略第二章 流体输送机械1        He=15+4.5×105qV2He=45.6J/N  Pe=4.5KW2        P

5、=ρω2r2/2; Φ/ρg=u2/2g=22.4J/N3        He=34.6J/N;η=64﹪4        略5        qV=0.035m3/s;Pe=11.5KW6        串联7        qV=0.178m3/min;qV,=0.222m3/min8        会汽蚀9        安装不适宜，泵下移或设备上移10    IS80-65-160或IS100-65-31511    ηV=96.6﹪12    不适用13    P=33.6KW;T2=

6、101.0℃14    qV=87.5m3/h;选W2第三章 流体的搅拌1        略2        P=38.7w;P’=36.8w3        d/d1=4.64;n/n1=0.359;N/N1=100第四章 流体通过颗粒层的流动1        △φ=222.7N/m22        △φ/L=1084Pa/m3        V=2.42m34        K=5.26×10-4m2/s;qe=0.05m3/m25        A=15.3m2;n=2台6       

7、 略7        △V0=1.5L8        △V=13L9        q=58.4l/m2;τw=6.4min10    τ=166s;τw=124s11    K=3.05×10-5m2/sVe=5.06×10-2m3;V=0.25m312    n’=4.5rpm;L’/L=2/3第五章 颗粒的沉降和流态化1        ut=7.86×10-4m/s;ut’=0.07m/s2        dP=88.8μm3        τ=8.43×10-3s;s=6.75×10-

8、5m4        dpmax=3.6μm5        dpmin=64.7μm;ηP=60﹪6        可完全分开7        ζRe2<488        η0=0.925;x出1=0.53 x出2=0.27;x出3=0.20x出4=0;W出=59.9kg/day9        ε固=0.42;ε流=0.71;ΔФ=3.14×104N/m210    略11    D扩=2.77m12    略第六章      传热1        δ1=0.22m;δ2=0.1m2