上册化工原理习题答案

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1、化工原理习题答案（上册）第一章流体流动1PA（绝）=1.28×105N/m2PA（表）=2.66×104N/m22W=6.15吨3F=1.42×104NP=7.77×104Pa4H=0.39m5△P=2041×105N/m26P=1.028×105Pa△h=0.157m7P（绝）=18kPaH=8.36m8H=RPA>PB9略10P=Paexp[-Mgh/RT]11u=11.0m/s;G=266.7kg/m2sqm=2.28kg/s12R=340mm13qv=2284m3/h14τ=1463s15Hf=0.

2、26J/N16会汽化1718F=4.02×103N19略20u2=3.62m/s;R=0.41m21F=151N22v=5.5×10-6m2/s23=0.817a=1.0624略25P（真）=95kPa;P（真）变大26Z=12.4m27P（表）=3.00×105N/m228qv=3.39m3/hP1变小P2变大29qv=1.81m3/h30H=43.8m31τ=2104s32He=38.1J/N33qv=0.052m3/s=186m3/h34qv1=9.7m3/h;qv2=4.31m3/hqv3=5.39

3、m3/h;q,v3=5.39m3/h35qvB/qvC=1.31;qvB/qvC=1.05;能量损失36P1（绝）=5.35×105Pa37=13.0m/s38qv=7.9m3/h39qVCO2（上限）=3248l/h40=500l/s;τ=3×104PaF=3×102NP=150w41he=60.3J/kg42τy=18.84Paμ∞=4.55Pa·s43τy=39.7Pa44略第二章流体输送机械1He=15+4.5×105qV2He=45.6J/NPe=4.5KW2P=ρω2r2/2;Φ/ρg=u2/2

4、g=22.4J/N3He=34.6J/N;η=64﹪4略5qV=0.035m3/s;Pe=11.5KW6串联7qV=0.178m3/min;qV,=0.222m3/min8会汽蚀9安装不适宜，泵下移或设备上移10IS80-65-160或IS100-65-31511ηV=96.6﹪12不适用13P=33.6KW;T2=101.0℃14qV=87.5m3/h;选W2第三章流体的搅拌1略2P=38.7w;P’=36.8w3d/d1=4.64;n/n1=0.359;N/N1=100第四章流体通过颗粒层的流动1△φ=

5、222.7N/m22△φ/L=1084Pa/m3V=2.42m34K=5.26×10-4m2/s;qe=0.05m3/m25A=15.3m2;n=2台6略7△V0=1.5L8△V=13L9q=58.4l/m2;τw=6.4min10τ=166s;τw=124s11K=3.05×10-5m2/sVe=5.06×10-2m3;V=0.25m312n’=4.5rpm;L’/L=2/3第五章颗粒的沉降和流态化1ut=7.86×10-4m/s;ut’=0.07m/s2dP=88.8μm3τ=8.43×10-3s;s=

6、6.75×10-5m4dpmax=3.6μm5dpmin=64.7μm;ηP=60﹪6可完全分开7ζRe2<488η0=0.925;x出1=0.53x出2=0.27;x出3=0.20x出4=0;W出=59.9kg/day9ε固=0.42;ε流=0.71;ΔФ=3.14×104N/m210略11D扩=2.77m12略第六章传热1δ1=0.22m;δ2=0.1m2t1=800℃3t1=405℃4δ=50mm5(λ’-λ)/λ=-19.7﹪6略7Q,/Q=1.64λ小的放内层8a=330W/m2*℃9a=252.

7、5W/m2*℃10q=3.69kw/m211q1/q2=112w=3.72×10-3kg/s;w’=7.51×10-3kg/s13Tg=312℃14Tw=746K15τ=3.3hr16εA=0.48;εB=0.4017略18热阻分率0.3﹪K’=49.0W/m2·℃;K,,=82.1W/m2·℃19w=3.47×10-5kg/m·s;tw=38.7℃20δ=82mm21a1=1.29×104W/m2·℃;a,2=3.05×103W/m2·℃;R=7.58*10-5m2·℃/W22δ=10mm;Qmax=11

8、.3KW23R=6.3×10-3m2·℃/W24n=31;L=1.65m25L=9.53m26qm=4.0kg/s;A=7.14m227qm2=10.9kg/s;n=36;L=2.06m;q,m1=2.24kg/s28qm=0.048kg/s29t2=76.5℃;t2=17.9℃30t,2=98.2℃;提高水蒸气压强T’=112.1℃31qm1=1.24kg/s32T,2=78.7℃;t,2=61.3℃33T=6