2011 AMC8 problems & solutions资料

2011 AMC8 problems & solutions资料

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时间:2019-09-10

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1、Problem1Margieboughtapplesatacostofcentsperapple.Shepaidwitha5-dollarbill.HowmuchchangedidMargierecieve?SolutioncentsisequivalenttoThenthethreeapplescostThechangeMargiereceivesisProblem2Karl'srectangularvegetablegardenisfeetbyfeet,andMakenna'sisfeetbyfeet.Whosegardenisl

2、argerinarea?SolutionTheareaofarectangleisgivenbytheformulalengthtimeswidth.Karl'sgardenissquarefeetandMakenna'sgardenissquarefeet.SinceMakenna'sgardenislargerbysquarefeet.Problem3Extendthesquarepatternof8blackand17whitesquaretilesbyattachingaborderofblacktilesaroundthes

3、quare.Whatistheratioofblacktilestowhitetilesintheextendedpattern?SolutionOnewayofapproachingthisisdrawingthenextcircleofboxesaroundthecurrentsquare.Wecannowcountthenumberofblackandwhitetiles;32blacktilesand17whitetiles.Thismeanstheansweris.Problem4Hereisalistofthenumber

4、soffishthatTylercaughtinnineoutingslastsummer:Whichstatementaboutthemean,median,andmodeistrue?SolutionFirst,putthenumbersinincreasingorder.ThemeanisthemedianisandthemodeisBecause,theanswerisProblem5WhattimewasitminutesaftermidnightonJanuary1,2011?SolutionThereareminutes

5、inanhour.orhoursandminutes.Therearehoursinaday,sothetimeishoursandminutesaftermidnightonJanuary2,2011.Problem6Inatownofadults,everyadultownsacar,motorcycle,orboth.Ifadultsowncarsandadultsownmotorcycles,howmanyofthecarownersdonotownamotorcycle?Solution1ByPIE,thenumberofa

6、dultswhoownbothcarsandmotorcyclesisOutofthecarowners,ofthemownmotorcyclesandofthemdon't.Solution2Therearetotaladults,andownamotorcycle.Thenumberofadultsthatdon'townamotorcycleis.Sinceeveryoneownsacarormotorcycle,onewhodoesn'townamotorcycleownsacar,sotheansweris.Problem7

7、Eachofthefollowingfourlargecongruentsquaresissubdividedintocombinationsofcongruenttrianglesorrectanglesandispartiallybolded.Whatpercentofthetotalareaispartiallybolded?SolutionAssumethattheareaofeachsquareisone.Then,theareaoftheshaderegioninthetopleftsquareis1/4.Theareao

8、fthetoprightshadedregionis1/8.Theareaofthebottomleftshadedregionis3/8.Andtheareaofthebottomrightshadedregionis

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