架空输电线路应力弧垂计算大作业

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1、架空输电线路某500kV架空输电线路，通过典型气象区I-IX区，导线为钢芯铝绞线LGJ-630/80GB1179-1983,试利用Excel绘制架空线的应力放松曲线，并根据该曲线确定档距为600米，高差为250米时，架空线是否需要放松，如需放松请确定放松系数。解：依题意得：(1)、绘制架空线应力放松图。1)、无高差时/v=^iarcch^-Y“且C()=,则无高差吋Co=parcch—。2[0.40,计算出无高差时C。的值，接着把C。依次往下取取到

2、接近0或者等于0,求出对应的值，根据学的值对应得到c0的值v(其中：e=[aB]/[a(}]=2.5/2.25=1.11),对应值列于下表。U=1.0u=0.99n=0.98u=0.97u=0.96u=0.95u=0.94u=0.93i=0.92u=0.91u=0.900.000.46480.48260.49940.51510.52990.54390.55710.56970.58150.59280.60340.020.44480.46260.47940.49510.50990.52390.53710.54970.56150.57280.58340.040.424

3、80.44260.45940.47510.48990.50390.51710.52970.54150.55280.56340.060.40480.42260.43940.45510.46990.48390.49710.50970.52150.53280.54340.080.38480.40260.41940.43510.44990.46390.47710.48970.50150.51280.52340.100.36480.38260.39940.41510.42990.44390.45710.46970.48150.49280.50340.120.34480.362

4、60.37940.39510.40990.42390.43710.44970.46150.47280.48340.140.32480.34260.35940.37510.38990.40390.41710.42970.44150.45280.46340.160.30480.32260.33940.35510.36990.38390.39710.40970.42150.43280.44340.180.28480.30260.31940.33510.34990.36390.37710.38970.40150.41280.42340.200.26480.28260.299

5、40.31510.32990.34390.35710.36970.38150.39280.40340.220.24480.26260.27940.29510.30990.32390.33710.34970.36150.37280.38340.240.22480.24260.25940.27510.28990.30390.31710.32970.34150.35280.36340.260.20480.22260.23940.25510.26990.28390.29710.30970.32150.33280.34340.280.19480.21260.22940.245

6、10.25990.27390.28710.29970.31150.32280.33340.300.17480.19260.20940.22510.23990.25390.26710.27970.29150.30280.31340.320.15480.17260.18940.20510.21990.23390.24710.25970.27150.28280.29340.340.13480.15260.16940.18510.19990.21390.22710.23970.25150.26280.27340.360.11480.13260.14940.16510.179

7、90.19390.20710.21970.23150.24280.25340.380.09480.11260.12940.14510.15990.17390.18710.19970.21150.22280.23340.400.07480.09260.10940.12510.13990.15390.16710.17970.19150.20280.21340.420.05480.07260.08940.10510.11990.13390.14710.15970.17150.18280.19340.440.03480.05260.06940.08510.09990.1