4、,则∠2的度数为( B )A.150°B.130°C.100°D.50°2.如图,已知∠1=70°,如果CD∥BE,那么∠B的度数为( C )A.70°B.100°C.110°D.120°3.如图,AD∥BC,则一定有( A )A.∠1=∠2 B.∠3=∠4C.∠1=∠2,∠3=∠4 D.∠2=∠34.如图,若AB∥CD,∠1=130°,则∠2=___。5.已知:如图,AD∥EF,AB∥DG,说明∠1=∠2的理由。解:∵AB∥DG(已知)∴∠BAD=∠2(两直线平行,内错角相等)∵AD∥EF(已知)∴∠1=∠BAD(两直线平行,同位角相等)∴∠1=∠2(等