2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准

2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准

ID:33920625

大小:47.50 KB

页数:8页

时间:2019-03-02

2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准_第1页
2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准_第2页
2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准_第3页
2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准_第4页
2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准_第5页
资源描述:

《2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库

1、2012年福州市初中毕业班质量检查数学试卷参考答案及评分标准一、选择题 1.A  2.B  3.C  4.C  5.D  6.A  7.D  8.A  9.B  10.C二、填空题:11.    12.8     13.    14.1    15.3三、解答题:16.(1)解:      = ················································································· 4分      =.··························

2、············································································· 7分(2)解:      = ··················································································· 4分      =,···············································································

3、····················· 5分当时,原式==5.························································· 7分17.(1)证明:∵AB与CD是平行四边形ABCD的对边,∴AB∥CD,······················································································· 2分∴∠F=∠FAB.······································

4、·············································· 4分∵E是BC的中点, ∴BE=CE,····························································· 5分又∵ ∠AEB=∠FEC, ······································································· 6分∴ △ABE≌△FCE.····································

5、······································· 7分(2)解:如图,a =45°,β=60°,AD=80.在Rt△ADB中,∵, ∴.············ 2分在Rt△ADC中,∵,      ∴.······· 5分∴.答:这栋楼高约为218.6m.  ·················· 7分18.(1)=   25   %,90º .··········································································· 2

6、分    补全条形图.····································································································· 4分(2)众数是5,中位数是5.·········································································· 8分(3)该市初一学生第一学期社会实践活动时间不少于5天的人数约是:(人).························

7、······················· 12分19.(1)证法一:连接AE, ·································· 1分∵AC为⊙O的直径,∴∠AEC=90º,即AE⊥BC. ···························· 4分∵AB=AC,∴BE=CE,即点E为BC的中点.················ 6分证法二:连接OE, ····································· 1分∵OE=OC,∴∠C=∠OEC.∵AB=AC,∴∠C=∠B,∴∠B=

8、∠OEC,∴OE∥AB. ················································ 4分∴,∴EC=BE,即点E为BC的中点.·················· 6分⑵∵∠COD=80º,∴∠DAC=40º.·············

当前文档最多预览五页,下载文档查看全文

此文档下载收益归作者所有

当前文档最多预览五页,下载文档查看全文
温馨提示:
1. 部分包含数学公式或PPT动画的文件,查看预览时可能会显示错乱或异常,文件下载后无此问题,请放心下载。
2. 本文档由用户上传,版权归属用户,天天文库负责整理代发布。如果您对本文档版权有争议请及时联系客服。
3. 下载前请仔细阅读文档内容,确认文档内容符合您的需求后进行下载,若出现内容与标题不符可向本站投诉处理。
4. 下载文档时可能由于网络波动等原因无法下载或下载错误,付费完成后未能成功下载的用户请联系客服处理。