分析化学_习题参考daan

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1、1《分析化学》第四版思考题与习题参考解答王志银2第二章定性分析1、已知用生成AsH3气体的方法鉴定砷时，检出限量为1μg，每次取试液0.05mL。求此鉴定方法的最低浓度（分别以ρB和1:G表示）。【解】已知：m=1μg；V=0.05mL；根据公式：m=VG=106BBρ；ρ可得最低浓度为：20(gmL)0.05ρ==1=μ⋅−1VmB;所以：；46651020=10=10=×BGρ因此有：1:G=1:5×10-42、取一滴（0.05mL）含Hg2+的试液滴在铜片上，立即生成白色斑点（铜汞齐）。经实验发现，出现斑点的必要条件是汞的含量应不低于100μg·mL-1loa

2、nmanagement(post)review:1,approvalcriteriahavebeenimplemented;2,thecontractiscorrect;3,inlinewiththecontract,payment;4,noothermajorcasesagainstloansecurity;、Reviewedby:dateofrecordform9:qilubankborrowingbysingleyearsofmaximumamountamaximumno-loanborrowers:borrowers:...Borrowernamenumbe

3、r,lineofcreditexpirydateyearmonthdaytoyearmonthdaymaximumnumberofyearsintheloancontractarethetoplineopened,theborrowedandrequestedyourbankopenedcreditlinesabove,isherebyrequested.Borrowersignature:dateagreedtoopencreditlines.CustomerManagersignature:dateagreedtoopencreditlines.Loanrevi

4、ewsignature:datelinecancellation-Ididnotusetheloanamount,yourbankcreditlinestobecancelled.-Creditloanprincipalrepayment,yourbankcreditlinestobecancelled.Borrowersignature:date-unusedcreditlines,agreetowriteoffloans.-Creditloanprincipalrepayment,agreetowriteoffloans.CustomerManagersigna

5、ture:datecase,agreetowriteoffloans.Loanreviewsignature:dateofrecordform16:qiluselfcreditforcreditcardcancellationapplicationformnameofborrowerIDnumberandcreditlimitexpirationdateyearmonthdaytoyearmonthdayyearcontractnumberself-servicecard-Idonotusecredit,yourbankcreditlinestobecancelle

6、d.-Creditloanprincipalrepayment,yourbankcreditlinestobecancelled.Borrowersignature:date-unusedcreditlines,agreetowriteoffloans.-Creditloanprincipalrepayment,agreetowriteoffloans.CustomerManagersignature:。求此鉴定方法的检出限量。【解】已知：ρB=100μg·mL-1；V=0.05mL；根据公式：mV；B=ρ可知检出限量为：mV0.051005(g)B=ρ⋅=×=μ3

7、、洗涤银组氯化物沉淀宜用下列哪种洗涤液？为什么？(1)蒸馏水；(2)1mol·L-1HCl；(3)1mol·L-1HNO3；(4)1mol·L-1NaCl；【答】应选用（2）1mol·L-1HCl作洗涤液。这是因为HCl含有与氯化物沉淀的共同离子，可以减少洗涤时的溶解损失；同时又保持一定的酸度条件，避免某些水解盐的沉淀析出；同时HCl为强电解质可防止洗涤过程引起胶溶现象。如果用蒸馏水洗涤，则不具备上述条件，使沉淀的溶解损失增大（尤其是PbCl2）；HNO3不含共同离子、且易引起盐效应而使沉淀溶解度大；NaCl虽具有共同离子，但不具备酸性条件，易使某些水解盐沉淀析