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ID:35628862
大小:1.92 MB
页数:40页
时间:2019-04-03
《机械设计课程设计-展开式二级直齿圆柱齿轮减速器》由会员上传分享,免费在线阅读,更多相关内容在学术论文-天天文库。
1、班级:XXXXXXXXX设计:XXX学号:XXXXXXXXXX指导老师:XXX完成时间:XXXX年XX月XX日机械设计课程设计计算说明书题目:展开式二级直齿圆柱齿轮减速器安徽科技学院目录1.设计题目·················································22.传动方案简述·············································33.电动机的选择·············································34.总传动比的
2、确定及分配·····································45.运动参数和动力参数计算···································56.39带的设计计算···········································61.齿轮传动设计·············································82.轴的结构尺寸设计及强度校核·······························163.轴承的选择与计算······
3、···································264.键联接的选择和计算······································275.联轴器的选择············································30391.减速器的润滑与密封······································302.减速器箱体及其附件······································313.参考资料············
4、····································344.设计总结················································35391.设计题目题目:设计用于带式运输机的展开式二级直齿圆柱齿轮减速器原始数据:(题号H10)班级序号22232425262728293031题号H1H2H3H4H5H6H7H8H9H10运输带工作拉力F/N2100155016501750185019501500160017001800运输带工作速度v(m/s)1.351.201.251
5、.301.201.301.101.151.201.25卷筒直径D(mm)240300260250230270280290220250班级序号323334题号H11H12H13运输带工作拉力F/N190020001800运输带工作速度v(m/s)1.301.401.45卷筒直径D(mm)260280250工作条件:连续单向运转,工作时有轻微振动,使用期限10年,小批量生产,单班制工作,运输带工作速度允许误差为±5%。392.传动方案简述将传动能力较小的带传动布置在高速级,有利于整个传动系统结构紧凑,匀称。同时,将带传动布置在
6、高速级有利于发挥其传动平稳,缓冲吸振,减少噪声的特点。由于齿轮相对轴承为不对称布置,使其沿齿宽方向载荷分布不均。故齿轮布置在距扭矩输入端较远的地方,有利于减少因扭矩引起的载荷分布不均的现象,使轴能获得较大刚度。综上所述,本方案具有一定的合理性及可行性。3.电动机的选择3.1已知条件运输带工作拉力运输带工作速度卷筒直径3.2类型Y系列三相异步电动机3.3相关计算(1)工作机的有效功率(2)由电动机至工作机的总效率h带传动V带的效率——取一对滚动轴承的效率——取39一对齿轮传动的效率——取联轴器的效率——取卷筒的传动效率——取
7、故(3)电动机所需的输出功率:(4)电动机转速:卷筒轴工作转速V带传动传动比展开式二级圆柱齿轮减速器传动比:故总传动比合理范围是电动机转速的可选范围3.4确定电动机的型号查表得符合这一范围的取同步转速为的电动机。电动机的型号为4.传动装置总传动比的确定及各级传动比的分配4.1传动装置总传动比(电动机满载转速)4.2各级传动比的分配(1)V带传动的传动比:可选范围2~4初取(2)两级齿轮传动的传动比:39(3)齿轮传动中高低速级传动比的分配:查表,则5.运动参数和动力参数计算5.1各轴转速计算小带轮转速输入轴中间轴输出轴卷筒
8、轴转速5.2各轴输入功率输入轴中间轴输出轴卷筒轴5.3各轴输入转矩电动机输出转矩输入轴中间轴输出轴39卷筒轴输入转矩6.V带的设计6.1已知条件电动机功率——电动机转速——V带传动比——取6.2设计计算(1)确定计算功率根据单班制工作,每班8小时,连续,单向运转,工作时有轻微振动.载荷稳定,工作期限10
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