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1、分析酸式盐与碱反应的两种方法:???????5??????????:??????Cu・2e=Cu2+,??????2H++2e=H2?????????????N?????O?m??:Cu+2H2O?[??Cu(OH)2+H2,????????amolH2,??????????2amoJ????????????,?)????????????(C)?????e???????????????o??????,??????????,???????????????N?????O?m????2H2O?[??O2+2H2,????????amolH2,??????????amo,l????????(D
2、)????????????(??9a9?)9999?.疋???H????,?????[??????????????????,?)?,?)??,??????????????，？？？？？？？？？;??,????，？？？？,？？？？？？？？？o???????????:?????:9[91?9?9999?••」••••••••?????:???B?C????????(226200)99?9?9?e?????m???a???????????????????[?N?????????????a?????????????????,??,???????????????e???????u?????????
3、?????,???????m???a????????,???????????????????????????)??,???????????)???????a??，？？？(？？？o?????5??????????????,Ca(HCO3)2?aNaOH?????????,???)?(??????????????????????,??????????????????5?o????????????5???????????e????????????9?••?O??,?[?????????a?e?????m???a??????999999????:?????????????????e?????m
4、???a?????????????????????????5??,?(?????????????????[????????????????,????,???????????????????????m??????????,?;????????????????????,?e?????????)?(????,???????,?)?(??????????????????????9?••?)????Ca(HCO3)2?aNaOH????????Ca(HCO3)2?aNaOH????????????????99?e?99?・••••••••(03)=++0303+03NaOH=Na++0H????
5、?H??????,???a???5????????:HCO3=co2-3+H2O,CO2-3+Ca2+=CaC03??????????????,lmolCa(HCO3)2????????2molHCO3,????,??NaOH???,lmol??,2molHCO3??????????????,??NaOH??2mol??,HCO3????????????????,Ca(HCO3)2?aNaOH?????,11????,?????,1299999997999N99999Q9m9e9999.JL••••••X••••••JLJLJL•w/•••••Ca(HCO3)2+NaOH(?l??)=
6、CaCO3+NaHCO3+H2OCa(HCO3)2+2NaOH(????)=CaCO3+Na2CO3+2H2O?(?e?e??????,NaHCO3?aCa(OH)2?????,11?N21????:NaHCO3+Ca(OH)2(????)=CaCO3+NaOH+H2O2NaHCO3+Ca(OH)2(?l??)=CaCO3+Na2CO3+2H2O???e??Ca(HCO3)2?aCa(OH)2?????????2???????????????e????:(03)二++03(0)=++063••••••••tCaHC2Ca2HCHC2-CaHC2Ca22HCCaH2Ca22H,???a?
7、??5????????:HCO3+OH=C02-3+H2O,CO2-=CaC03???0,1molCa(HCO3)2????????2molHCO3,1molCa(OH)2????????????2molOH,2molHCO3?a2molOH????????????,?5?o2molCO2-3,???????+2molCa2+?5?o2molCaCO3????????,Ca(HCO3)2?aCa(OH)2???????????,11????,?
