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1、学院姓名学号任课老师考场教室__________选课号/座位号………密………封………线………以………内………答………题………无………效……电子科技大学2012-2013学年第二学期期末考试A卷课程名称：_数字逻辑设计及应用__考试形式：闭卷考试日期：2013年07月05日考试时长：_120___分钟课程成绩构成：平时30%，期中30%，实验0%，期末40%本试卷试题由___七__部分构成，共__7___页。题号一二三四五六七八九十合计得分得分I.Filloutyouranswersintheblanks(3’X10=30’)1.Ifa7
2、4x138binarydecoderhas110onitsinputsCBA,theactiveLOWoutputY5shouldbe(1orhigh).2.Ifthenextstateoftheunusedstatesaremarkedas“don’t-cares”whendesigningafinitestatemachine,thisapproachiscalledminimal(cost)approach.3.TheRCO_Lof4-bitcounter74x169is(0orlow)whencountingto0000inde
3、creasingorder.4.Todesigna"001010"serialsequencegeneratorbyshiftregisters,theshiftregistershouldneed(4)bitatleast.5.OnestatetransitionequationisQ*=JQ’+K’Q.IfweuseTflip-flopwithenabletocompletetheequation，theenableinputofTflip-flopshouldhavethefunctionEN=(JQ’+KQ).6.A4-bitB
4、inarycountercanhave(16)normalstatesatmost,4-bitJohnsoncounterwithnoself-correctioncanhave(8)normalstates,4-bitlinearfeedbackshift-register(LFSR)counterwithself-correctioncanhave(16)normalstates.7.IfweuseaROM,whosecapacityis16×4bits,toconstructa4-bitbinarycodetograycodeco
5、nverter,whentheaddressinputsare1001,(1101)willbetheoutput.8.Whentheinputis10000000ofan8bitDAC,thecorrespondingoutputvoltageis2V.Theoutputvoltageis(3.98)Vwhentheinputis11111111.第7页共7页学院姓名学号任课老师考场教室__________选课号/座位号………密………封………线………以………内………答………题………无………效……得分II.Pleaseselectthe
6、onlyonecorrectanswerinthefollowingquestions.(2’X5=10’)1.Ifa74x85magnitudecomparatorhasALTBIN=1,AGTBIN=0,AEQBIN=0,A3A2A1A0=1101,B3B2B1B0=0111onitsinputs,theoutputsare(D).A)ALTBOUT=0,AEQBOUT=0,AGTBOUT=0B)ALTBOUT=1,AEQBOUT=0,AGTBOUT=0C)ALTBOUT=1,AEQBOUT=0,AGTBOUT=1D)ALTBOUT
7、=0,AEQBOUT=0,AGTBOUT=12.AsshowninFigure1,whatwouldtheoutputsofthe4-bitadder74x283be(B)whenA3A2A1A0=0100,B3B2B1B0=1110andS/A=1.A)C4=1,S3S2S1S0=0010B)C4=0,S3S2S1S0=0110C)C4=0,S3S2S1S0=1010D)C4=0,S3S2S1S0=1110Figure13.WhichofthefollowingstatementsisINCORRECT?(A)A)ADlatchise
8、dgetriggeredanditwillfollowtheinputaslongasthecontrolinputCisactivelow.B)ADflipflopisedgetriggeredandit
