2022-2023学年安徽省合肥中考数学专项提升仿真模拟试题（一模二模）含解析

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2022-2023
ḕᔠὃᦪ⚗ᓣ⚪ஹ⌱⌱:1.᝞ᦪḄAᡠ⊤Ḅᦪk,ᓄ|k|+|l—k|Ḅo1A.1B.2k-1C.2k+1D.l-2k2.ᑡḄA.3a2—a2=3B.a2
3=a5C.a3-a6=a9D.(2a2)2=4a23.2.1=1,2?-1=3,23-1=7,2'-l=15,2-1=31,!ᔜ#Ḅ$%ᦪ&'(,*+Ḅ$%ᦪ&A.1B.3C.7D.54.ᙠ-.⁚0“ᜋᩭ45”#78⌱9:☠<=>☢@ᩭᛋBCᜋᜋᨵEᱥ⌼HḄIJ.⌱9◤⌕ᢥᜋḄ⌼H᤮PQRḄSTUVWᜋXYᔲᑣ\]ᜋ^ᐭ<=.`aᙢᨵᙽdefាhVij#k$lᨵRmnḄ“ST”ᑖpWYqk$IJᑣrdef()u415.v(ߟ----1--------)-w=1,y5|w=()a2-42-aA.a+2(ah—2)B.~U+2(tzh2)C.a-2("2)D.-a-2(ah-2)6.ᑡᔜ{#lᨵR`⚗Ḅ()C.0.2/b}-92bD.A.2$}52B.-abba}-a*7.~᜜᪥᩽᪷Ḅ᰿h⌱⚗r᪥

1ḄfᨵAᳫB᣸ᳫCᳫDᳫE¢£ᳫ.¤ὁ¦§¨©R⌱fª«¬®ᑴᡂ4k±lᨵ²᦮Ḅ®᝞ᑣi´lᨵḄA.⌱µ0EḄᨵ5EB.⌱µ0஺Ḅᡧmᙊº»72஺C.⌱µ0AḄEᦪᓰfEᦪḄ¿D.⌱µ08Ḅᡧmᙊº»Á⌱µ0DḄᡧmᙊº»ḄÂᦪÃ21.6஺8.᝞ᙠÆABC#DE/7BC,AD=6,DB=3,AE=4,yUECḄÌA1B.2C.3D.49.ᙠÎ☢Ï»ᙶ᪗Ò#ÏÓÔ=-x+2}×ÁØÙᦪy=1ḄÛᨵÜᐳvÏÓXy=—x+b}×ÁØÙᦪy=’ḄÛᨵ2$Üᐳᑣ6ḄáâäAb>2B.-22ᡈb<-2D.b<-210.ᙠ¿é10Ḅ஺OᑁᨵP,0P=6,ᙠYPḄí#ÌÂ᦮ᦪíḄᩩᦪA5ᩩB.6ᩩC.7ᩩD.8ᩩ

2ïஹðI⚪fx<3%+211.lᨵòó{ீ,ஹஹḄ᦮ᦪõ[x-l<2-2x12.ᑖõöóa2b-6ab2+9b3=.13.᝞ᙠRtaABC#ZC=90°,ZB=70°,Z\ABCḄᑁᑗᙊ஺0}øABஹBCஹCAᑖpQᑗùDஹEஹF,ᑣNDEFḄÂᦪ°.JCFA14.᝞ᙠÆ4SC#AB=2,AC=4,“BCஹCᢥ⌮ü┐þᔣ
ᑮAA'B'C,C8'஻AB,ᑖAB,C4'D,ᑣBDḄC________'BABDஹ⚪15.(-1)2016+2sin60--|-l+n°.16.x2-2x=2x+1ஹ!⚪17.᝞#$ᙠ&☢()ᙶ᪗,-,A48cᔜ⚔Ḅᙶ᪗ᑖA(4,0),B(-1,4),C(-3,1).

3(1)ᙠ#-3A4'B'C',9AA8Cᐵx=>?@(2)ᑏC8',஺'Ḅᙶ᪗@(3)FA48CḄ☢G.18.HIJKLᦪNV2-4X+5.(1)Sy=x2-4x+5ᓄᡂ᜛=a(x-h)2+kḄYZ@(2)ᢣC\JKLᦪ#]Ḅ>?=9⚔ᙶ᪗@(3)^x_`ab$ydxḄeᜧgeᜧh19.᝞#$ᙠjk$lm9lnᔠ3ᵨqr)sᩭuvw᪥yᩚ{|.HIlmḄ}~ᙢ☢Ḅ(AB)1.7m,᦮Ḅ$)sḄqᩩ()ᢝ&$yᩚ⚔Mᙠqᩩ(k$uyᩚ⚔M)45°@lnḄ}~ᙢ☢Ḅ(CD)1.5m,ᵨ᪵Ḅuyᩚ⚔MḄ)30°.28yᩚ¡(BஹNஹDᙠqᩩ(k).FCyᩚMNḄ{|.(£ὃᦪ¥VI»1.4,73«1.7.©ªᶇ᦮ᦪ.)20.᝞#$LᦪNkx+bḄ#]ᑖ®¯°Lᦪy=@Ḅ#]ᙠ]▲A(4,3),Xy=Ḅ³´=B,OA=OB.

4(1)FLᦪ¶kx+b9¶qḄ⊤¸Z@x(2)HIC(0,8),¹ᙠ\Lᦪ#]kº»qM,MB=MC,F¼bMḄᙶ᪗.21.ᨵᵬஹ¿ÀÁᨵÂmḄÃÄ$ᵬÃÄ-Åᨵ3Æᓱᱏ$ᓱᱏkᑖᑏḼ3cmஹ7cmஹ9cm@¿ÃÄ-Åᨵ4Æᓱᱏ$ᓱᱏkᑖᑏḼ2cmஹ4cmஹ6cmஹ8cm@ÃÄ᜜ᨵqÆᑏḼ5cmḄᓱᱏ.ᡠᨵᓱᱏḄYÌஹᜧlÍÎᐰ.ÐdÑÒᵬஹ¿ÀÃÄ-ᔜ_CqÆᓱᱏ$ÃÄ᜜ḄᓱᱏÓᙠqÔ$ᵨᓱᱏk᪗mḄᦪvᑖ3qᩩḄ|.(1)Õᵨ᪛Ì#ᡈᑡ⊤ḄFÙᩩÚÛᡂ)YḄᭆ᳛@(2)FÙᩩÚÛᡂ())YḄᭆ᳛.ஹᔠ⚪22.HIJKLᦪy=x?+2bx+c(bஹcÞᦪ).(I)^b=l,c=-3b$FJKLᦪᙠ-20W2kḄᨬla@(II)^c=3b$FJKLᦪᙠ0WxW4kḄᨬla@(III)^c=4b?b$àᙠávxḄaâã2bWxW2b+3Ḅäåæ$ᐸ>èḄLᦪayḄᨬla21,F¼bJKLᦪḄ᪆Z.23.(1)᝞#1,êYABCD9êYDEFG,GᙠADk$EᙠCDḄk.Fë:AE=CG,AE±CG@(2)᝞#2,àS#1-ḄêYDEFGíDîb┐
)|஺(0஺ð஺ð90஺)$¼bAE=CGñᡂòᔩhàᡂò$Õôõëm@àÁᨵᡂò$Õömᳮᵫ@(3)᝞#3,^êYDEFGíDîb┐
45஺b$CGAEH,^AD=4,DG=⊈b$FCHḄ.

52022-2023
ḕᔠὃᦪ⚗ᓣ⚪()qஹ⌱q⌱1.᝞#$ᦪ=kḄAᡠ⊤ûḄᦪk,ᓄü|k|+|l—k|Ḅ©ª()__,__01A.1B.2k-1C.2k+1D.1—2kூêº!ᫀ௃Bூ௃ᵫᦪ1,ᑣ□+"|=+1=21,ᦑ⌱B.2.ᑡḄA.3a2—a2=3B.(a2)3=a5C,a3-a6=a9D.(2a2)2=4a2ூᫀ௃Cூ௃⚪ᑖ᪆Aᫀ$2a2%B.ᫀ$a6%C.%Dᫀ$4a&

63.'221=3,23-1=7,2'-1=15,2'-1=31,()ᔜ'+,-Ḅ./ᦪ012,452ᑘ'-IḄ./ᦪ0()A.1B.3C.7D.5ூᫀ௃Cூ௃⚪᪆%21-1=1,22-1=3,23-1=7,2515,25-1=31,26-1=63,27-1=127,28-1=255...ᵫ9:45./ᦪ0:4$ᕜ<ᢥ᯿1,3,7,5Ḅ?@ABCDEF⍝2015◀:4$503I3,JK3.ᦪ0$7,ᡠ::4522015-1Ḅ./ᦪ07.ᦑ⌱ὃNOᦪᱯQ.4.ᙠTU⁚W“ᜋᩭ[\”-E^_⌱`a☠cdEe☢gᩭᛋijᜋEᜋkᨵmᱥ⌼pḄqr.⌱`◤⌕ᢥᜋkḄ⌼p᤮vwxḄyzE{|}ᜋJ~Eᔲᑣᜋᐭcd.ᙢEᨵᙽា|:-.ᨵxḄ“yz”ᑖ}~.qrEᑣ$()A-0B-@cA“೑ூᫀ௃Cூ௃⚪ᑖ᪆~FE⌕~ᙊEᑣ:ᙊஹᙊ┵ஹᳫEJ|~Ḅ|ᙊ┵E¡ᔠFᨵᙊ┵£ᔠᩩ¥.ᦑ⌱C415.¦(ߟ----1---------)-w=1,©!|w=()a2-42-aA.a+2(஺h—2)B,—a+2(aH2)c.a—2(஺஺2)D.-a-2(nh-2)ூᫀ௃D

7414a+22—u1ூ'௃.,/_42-a(a+2)(a-2)(a-2+2(a+2)(a-2)a+2'41ஹza2-4+2^aw=1,w=-a-2(a/-2).ᦑ⌱D.6.ᑡᔜ·-Eᨵx⚗Ḅ¹ºA.2,¼5?B.-abbaC.0.2a2b¼D.a*¼-aÅூᫀ௃Dூ௃A.B.C⌱⚗x⚗%D.ᡠÆ0ÇwxEÈwx0ÇḄÉᦪᨵxEᨵx⚗.ᦑ⌱D.7.$ÊËÌÍÎ᜜EÐ᪥Ò᩽ÔÕÖ×EÌÍ᪷ÙÚÛḄ᰿⌱Ý⚗EÛF᪥ÔÞḄßÖ×ᨵAàᳫEB᣸ᳫCâᳫ%DãäᳫEEåæᳫ.çὁéêÐëìxÌ⌱ÝßÖ×íîABï'Eᑴᡂ[òᨵó᦮Ḅï'¹᝞ºEᑣ:+öᨵḄ¹ºA.⌱÷WEḄᨵ5mB.⌱÷W஺Ḅᡧᙊù72஺

8C.⌱÷WAḄmᦪᓰßÖ×mᦪḄûD.⌱÷W8Ḅᡧᙊùý⌱÷WDḄᡧᙊùḄþᦪÿ21.6஺ூᫀ௃Cூ௃⚪ᑖ᪆A⌱⚗ᐜḄᦪ⌱!EḄᦪᩭᑨ%,⌱DḄ!ᦪB⌱⚗ᑭᵨ*360°ᑨ%ᓽ/,"!ᦪC⌱⚗0B,C,DḄᦪᓽ/ᑨ%,D⌱⚗ᑭᵨ⌱!BḄᦪ3⌱!D,◀56ᦪ7360஺ᓽ/ᑨ%.Ḅᦪ812+24%=50>?⌱!EḄᦪ850xl0%=5>?ᦑA⌱⚗⌱!DḄᡧDᙊFGHIஹ360஺=72஺ᦑB⌱⚗50⌱!B,C,DḄᦪ87+12+10=29,6ᦪ850ᡠ5⌱!AḄᦪᓰOPQRᦪḄST┯VᦑC⌱⚗Wᨵ⌱!BḄᡧDᙊFGY⌱!DḄᡧDᙊFGḄZᦪ[\ஹ360஺=21.6.ᦑD⌱⚗50ᦑ⌱C.ὃ^ᩩD`abcᡧD`ab.8.᝞b,ᙠaABC0DE஻BC,AD=6,DB=3,AE=4,ᑣECḄj8>A.1B.2C.3D.4ூᫀ௃BjnAp64ூ௃⚪ᑖ᪆᪷lmnoᑖopᡂYr/s——=——uᐭaw/sS=—DBEC3ECᓽ/EC=2,ᦑ⌱B.ὃ^mnoᑖopᡂYr

99.ᙠm☢yGᙶ᪗|0yo}=—x+2~YrᦪyḄbᨵᐳ^yoXy=-x+6~YrᦪyḄbᨵ2ᐳ^ᑣ6ḄH>?XA.b>2B.-20,.,.b>2,ᡈb<-2,ᦑ⌱C.10.ᙠT§810Ḅ஺0ᑁᨵS^P,0P=6,ᙠª^PḄ«0jZ8᦮ᦪ«Ḅᩩᦪ8>
A.5ᩩB.6ᩩC.7ᩩD.8ᩩூᫀ௃Dூ௃ᨬ®Ḅ«HªP¯~0PᚖyḄ«᪷lᚖ§%ᳮ²³´%ᳮaw816,ᨬjḄ«8ª0²P^Ḅ«ᓽy§820,µ¶ªP^Ḅ«ḄjZ>·8a?ᨵ᝞¸16WaW20º»ᑮ¼½Ḅᡠᨵ¾¿«j8᦮ᦪḄH16,17,18,19,20.᪷lᙊḄÀÁឋ,ᐸ0ªP¯~0PᚖyḄ«²ª஺²P^Ḅ«ÄᨵSᩩᒕ¸Ḅj817,18,19Ḅ«ᨵᩩ>5

10ªOPḄy§8ÆÇᯠs)¾¿Sᐳ8ᩩᦑ⌱D.#ஹ$%⚪fx<3x+211.Wᨵ¢ÊஹஹḄ᦮ᦪH.[x-\<2-2x--------ூᫀ௃-1,0.ூᑖ᪆௃ᐜᑖজঝWᨵḄÍWᨵ¢ḄÍ᦮ᦪᓽ/.x<3x+2®ூ௃⚪ᑖ᪆:x—1<2—2x(2)জsx>-1,ঝsx

11ூ௃⚪ᑖ᪆᝞bâãä0å஺,᪷lᑗoḄឋæ/s/஺஺=/஺5=90஺èéNC=90஺,NB=70஺᪷lêGDᑁG²%ᳮ/sNA=20஺ᙠëàDAFOD0᪷lëàDᑁG²%ᳮ/sNDOF=160஺ᵫᙊᕜG%ᳮᓽ/sNDEF=1/DOF=80஺.7ὃ^ᑗoḄឋæ%ᳮcᙊᕜG%ᳮ.14.᝞bᙠAZBC0AB=2,AC=4,AZBCí^Cᢥ⌮ð┐ᔣóôsᑮ¤Z'8'C,õC8'஻AB,ᑖöjAB,C4'÷á^D,ᑣopBDḄj8ூᫀ௃6.ூ௃⚪ᑖ᪆ø^ABCí^Cᢥ⌮ð┐ᔣóôsᑮ¤AEC,AB=2,AC=4,:.A'B'=AB=2,AC'=AC=4,NCA'B'=/A.ùCB'஻AB,.•.NA'CB'=NA¤A'CB'saDAC..CA'A'B'42ᓽ---——nAD=8.BD=6."7D~^4CAD4ὃ^1.óôḄឋæc2.mnḄឋæc3.úêGDḄᑨ%²ឋæ.êஹaw⚪:15.aw(-1)2016+2sin60"-|-⍝)|+n°.ூᫀ௃2ூᑖ᪆௃᪷lᦪḄüwýþ✌ᐜ
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12(-1)"")+2sin60°—Ḅᓽ.ூ௃(Iyo"+2sin60஺"#|+4஺=l+2x--V3+12=I+V3—+1=216.&x2-2x=2x+1ூ'()ᫀ௃+&ᓄ-X2-4X=1⎽/0X2-4X+4=1+4᦮ᳮ0(x-2)2=5•*.x—2=+^/5>BPX]=2+-^5>x=2—V5.2ூ௃ᐗ4&.᪷6ᐗ4&Ḅ789⚪;ᨵ=>?@A#;ᨵᵨCᑖ.ᐜE&᦮ᳮFGὃ⇋ᵨJᡈL.Mஹ)⚪17.᝞PᙠA☢>Sᙶ᪗VWᔜ⚔ZḄᙶ᪗ᑖ[-A(4,0),B(-1,4),C(1)ᙠPW\ATB'C',]zM'8'C'ZU8Cᐵ_x`ab;(2)ᑏZ8',஺Ḅᙶ᪗e(3)A48CḄ☢f.

13ூ'()ᫀ௃(1))᝞Pᡠi,k᪆;(2)8—CX-3,-1)e(3)AABCḄ☢f-—.2ூᑖ᪆௃(1)>?ᑭᵨᐵ_x`abZḄឋwxy0)ᫀe(2)>?ᑭᵨ(1)WᡠzP{0ᔜZᙶ᪗ᓽe(3)ᑭᵨ|S{/8Cᡠᙠ~{☢fᕜ|S{☢fxy0ᑮ)ᫀ.ூ௃(1)ᵫᐵ_x`abZḄឋwᡃG0ᑮḄP{᝞Pᡠi(2)ᵫ(1)WᡠzḄP{ᡃG0ZḄᙶ᪗ᑖ[--4)஺'(3,-1)(3)᝞Pᡠi,S&ABC-S~{EFH4—S2EC—S“HB—^ABFC]711••£EC=3(4ECE)=Q,S“HB=5"HBH)=10,S^=-(BF-CF)=3ABFCS&'EFHA=AEEF=7x4=28723^AABC=S('EFHA_S&AEC.^AHB~~^ABFC=^-10—3——=•⚪⌕ὃ`abᣚG|S{☢f'(0aZ⚪ᐵ.18./¡4¢ᦪ12-G+5.(1)Ey=x2-4x+5ᓄᡂy=a(%-/?)2+kḄ{e(2)ᢣ©4¢ᦪPªḄab`⚔Zᙶ᪗e(3)«x¬®y¯xḄ°ᜧy°ᜧ²ூ'()ᫀ௃(1)³(x-2)2+1e(2)ab`-x=2,⚔Zᙶ᪗-(2,1)e(3)x>2

14ூᑖ᪆௃´1µᑭᵨJᐜ¶4⚗Vᦪ¸¹º⚗VᦪḄ»ḄAᩭ½¾ᐰAÀÁÂᓄ-⚔Ze´2µᑭᵨ´1µḄ᪆©4¢ᦪPªḄab`⚔Zᙶ᪗e´3µ᪷64¢ᦪḄPªḄᓫÄឋ).ூ௃´1µy=x2-4x+4-4+5=´x-2µ2+1,ᓽ³´x-2µ2+1e´2µ᪷6´1µḄ¢ᦪ᪆¡ab`->Åx=2,⚔Zᙶ᪗-´2,1µe´3µ᪷6´1µÆ´2µḄÇÈz4¢ᦪḄᜧÉPª´᝞PᡠiµPªW¡«Ê2®y¯XḄ°ᜧy°ᜧ.9⚪ὃḄ4¢ᦪḄ|8{4¢ᦪḄឋwᮣÌÍᵨJÀÁᓄ-⚔Z⚪ḄᐵÎÏ4¢ᦪḄឋwḄᵨ.19.᝞PᙠѺÒÓÒÔᔠ\ᵨÖ|S×ᩭØÙÚ᪥ÜᩚÞß.à¡ÒÓḄáâãᙢ☢Ḅåæ´ABµ1.7m,êÄ᦮ë/Ḅì]0|S×Ḅᩩ>SîïᢝñAòóîãÜᩚ⚔ôMᙠöᩩ>źØ0Üᩚ⚔ôM÷S-45°eÒÔḄáâãᙢ☢Ḅåæ´CDµ1.5m,ᵨö᪵ḄØ0Üᩚ⚔ôMḄ÷S-30°.ûüå28ýò_Üᩚþ´ZBஹNஹDᙠᩩ.ᩚMNḄ.ὃᦪV2®1.4,73«1.7.$%&ᶇ᦮ᦪ.BD

15ூ*+,ᫀ௃ᩚ/0111.ூᑖ᪆௃45A6AE_LMN7E,45C6CF_LMN7F,ᑣEF=0.2m.ᵫAAEM:;Ὺ=>=?@AE=ME,AAE=ME=xm,ᑣMF=(x+0.2)m,FC=(28-x)m.ᙠRtAMFCB,ᵫMF=CF
tanNMCF,CDExḄFGHUMN=ME+EN.ᑣEF=AB—CD=1.7—1.5=0.2ᙠRtAAEMB,VZMAE=45O,I.AE=MEAAE=ME=x(KᨵAᦪMN)I.MF=x+0.2,CF=28-xᙠRtAMFCB,ZMFC=90°,NMCF=30°.,.MF=CFtanZMCFC@x*9.7,AMN=ME+EN=9.7+1.7-111.,ᩚMNḄ/0111.P⚪ὃRSC=>=?ḄT⚪.U⚪:VWXYZḄC=>=?T⚪G[\]^WX_ᓫGaC4EBbcᑮ᪷fghᦪGijkl.20.᝞nGoᦪpkx+bḄnqᑖrstWuoᦪy=@Ḅnqᙠq▲w75A(4,3),sXyxḄyzxw75B,{OA=OB.(1)oᦪy=kx+bgp⁐Ḅ⊤~fIx(2)5C(0,8),ᙠUoᦪnq+5M,@MB=MC,5MḄᙶ

16᪗.ூᑖ᪆௃(1)ᑭᵨᦪᓽNC,I(2)6MD±yxyx75D,A5MḄᙶ᪗0(x,2x-5),᪷MB=MC,@UCD=BD,ᑡDEN@xḄFG@ᑮ5MḄᙶ᪗ூC௃C(1)5A(4,3)ᐭoᦪ=3@a=3x4=12,X12/.y=—.xVA(4,3)/.0A=5,VOA=OB,


0B=5,.,.5BḄᙶ᪗0(0,-5)B(0,-5),A(4,3)ᐭkx+b@/.y=2x-5.(2)6MD_Lyx75D.••,5Mᙠoᦪy=2x-5,

17
•
A5MḄᙶ᪗0(x,2x-5)ᑣ5D(0,2x-5)VMB=MC,


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