冯恩信电磁场与电磁波课后习题答案

冯恩信电磁场与电磁波课后习题答案

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19a2জaiaজiaaজ92=cos(p)-sin8cos°()-sin(cos(p)6p~dppd(ppd(pdpiaaজ+sin஺(sin஺)pd(pd(pa?জ/.aiaஹ<.aজiaজஹ——=(sin(p—+cos^9——)(sin(p-7—+cos(p—--)dydppd(pdppd(p.a?জ.a/13o).i3.z=sin~(p——^-+sin᜛cos᜛——(-----)+cos஺-----(sin^7——)6p-dpp3(pp6(pdpia/aজ+cos(p-----(cos(P——)pZ(p4(pH2aöজ.3iaজ.i3aজVa.iaজஹi3..aজஹ2+sin~(p——-+sm*cos(p——(------)+cos°-------(sin(p——)6p-dppd(ppd(pdpi3aজ+COS஺--——(cos^7——)pd(pd(p=ø+sin20Úùksinecos9Úú+sin9coscp\ùdp-pdpp6®p*p2d(p.2ia?t+sm-p-a21aজ.19iao>21Mজ+cos(p-------+cos^sin(p------------cos^7sin(p^-----1-cos-(p—-----r-pGppc)(pdpp-G(pp-Z(p-õজiaজia?জia,ᜐஹiজdp-pdppd(p~Pdpdpp-d(p1.29ûüa)f(r)=x2zb)/(r)=pc)f(r)=r9V2ýEF

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22

232Xz2yaVxA=ddd_d_2一-2dxdz,dxdyo4&y-xA•(Vxy4)=(yx-xy)-(—2z)=0BH=A,(x,y)£+A,(x,y)y£<-23y2zxya一^£dd一n^+lVxA=国A&龙n'ᓝ4VA;~dyo.zA,(x,y)4(x,y)V--3AdA)(+1.35E=y+9+2ᦣBv஺:d-dEdE3V-E=——-H-----H------=03%dXzXddddVxE==0dx.dydxdyEEEyzxzxyxyz1.36£=£cosnEoSin஺©,VEGVxE஺0V7l8/Zjr'i1,Z3I7Xτ1ᐚজV-£=¡)+-------—(sinttE.)H-----------vr~drrsin0dOrsin஺d(p=!g(r2E஺cos6)+1%(sin6>(-Esin6))0rorrsin030_2Ecos02Ecos800—-----------------------------------=()r

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