2022届福建厦门大同中考三模数学试题含解析及点睛

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.6.᝞f&R3ABC&ZACB=90°,AB=5,AC=4,CDJ_ABD,UtanNBCDḄ()453A.D.I44

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6ᑖò᝞fᡠx&+ᛀḄᚁNABC=62஺ᚁ☢=25☢ᛀᱞᦋᛀḄᚁ☢ᚁ☢ḄᚁNA/M=50஺ᑣ!"#$%ᔣ᜜()*+,-./ᶇᑮ0.012ὃᦪ56sin62°M.88,cos62Ko.47,tan5O0M.2O22.
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7Bᧇᓫ#xᐗ/ᑣAᧇᓫ#(x-1)ᐗ/᪷>2Aᧇ3Bᧇᐳ¡>1ᐗ3¢£¤#2(x-1)+3x=l.ᦑ⌱A.ூ¨௃ᑡ£¤⚪Ḅᐵ«-¬[⚪JᙠḄt®ᐵ¯]⚪Ḅt®ᐵ¯#AJᧇḄ°+BJᧇḄ°=ᐳ¡Ḅ°1ᐗ.8ஹDூ᪆௃᪷J²ᦪ£³Ḅ´µᑖAb¶[·ᦪdᦪḄJ²ᦪ£³¸'[ᑨº.ூ»s௃•.•·ᦪḄJ²ᦪ-.=3,ᙳᦪ#.=3,/X¾)4j•••£³#X[(1-3)2+(2-3)2+(4-3)2+(5-3)2]=1542•.•dᦪḄJ²ᦪ#3,ᙳᦪ#…=3,£³#,X[(1-3)2+(2-3)2+(3-3)2+(4-3)2+(5-3)2]=2ᡠ4dᦪ·ᦪÂÃJ²ᦪaÄ£³Äᦑ⌱D.ூ¨௃Å⚪ὃÇ>J²ᦪ£³s⚪Ḅᐵ«-ÈÉJ²ᦪ£³Ḅ´µ.9ஹDூs᪆௃sODVZAOD=60o,.,.ACD=30°.VZCEB-AACEḄ᜜M:.ACEB=ZACD+ZCAO=30o+45°=75°ᦑ⌱D

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m=4,

9/•inḄlO4ᡈ1.ᦑ⌱D.ூ"#௃%⚪ὃ()©,wᦪÈIQÉÊᣚ§%⚪ḄᐵÌOÍΩ,wᦪḄ⚔"ᙶ᪗¶ᙶ᪗ÏGCÅÆ5rḄᣚ,ᐵx¼Ḅ"ϸᱥGḄᐵd.12ஹDூ᪆௃{ÐᑭᵨÒ./©,wᦪḄ⚔"Ó§ᫀ.ூa௃y=-x2-4x+5=-(x+2)2+9,ᓽ©,wᦪy=-x2-4x+5ḄᨬᜧlO9,ᦑ⌱D.ூ"#௃¦⚪Ö⌕ὃ()©,wᦪḄᨬl×Ò.O⚪ᐵÌ.©ஹØZ⚪0(%ᜧ⚪ᐳ6⚪⚪4ᑖᐳ24ᑖ.)13ஹ150°ூ᪆௃ᑭᵨᙊ┵ḄÝ☢ᕜÅÏGÅgᙊ┵Ḅß☢àᯠᑭᵨᙊ┵Ḅ☢àḄáâ./gß☢ãäᡧ|ḄᙊVuḄÆᦪᓽூa௃©,ᙊ┵ḄÝ☢ᙊḄᕜÅO45c7஻ᙊ┵Ḅß☢ᡧ|ḄæÅf5çcm,117rx6.---------=5è,180072=150ᦑ§ᫀf150'.ூ"#௃¦⚪ὃ(æÅḄáâ⚪ᐵÌᙠgᙊ┵Ḅß☢à14ஹ34ூ᪆௃

10i](]Yx-\——6,x2H--=XH——2=62—2=36—2=34,XX"\x)ᦑÌᫀ#34.15ஹ+ூ᪆௃mn(n-m)-n(m-n)=mn(n-m)+n(n-m)=n(n-m)(m+l),ᦑÌᫀ#n(n-m)(m+l).16ஹ1ூ᪆௃᪷⚪Ñ34[AḄᙶ᪗¸'4¢ᑮCBḄᙶ᪗Ò᪷AAOBḄ☢q#1,ᓽ3¢kḄ*.ூ௃sAḄᙶ᪗#(—a,0),••,CḄXyᑖA!A,B,AB=BC,AAOBḄ☢q#1,...C(a,",ÔBḄᙶ᪗#1k,—a-----=1,22as¢k=4,ᦑÌᫀ#1.ூ௃Å⚪ὃÇ>ÕÃÖ×ᦪ¯ᦪkḄØÙѵஹ^×ᦪ2ÚzḄᙶ᪗ᱯÜஹÕÃÖ×ᦪ2ÚzḄᙶ᪗ᱯÜs⚪ᐵ«-ÝÞ⚪Ѭ[ᡠß⚪◤⌕ḄᩩâᑭᵨᦪFäᔠḄæçsÌ.17ஹx

11᪷_{uvu|┦uéêgZBAC=30°,᪷_{uvu|30஺uᡠḄ{u`ì`Ḅ*íBC=gAB,2ᯠg▢ïðᑖḄ☢à=SᡧñABE-SᓭñBCD,ᑡáâᓽ.ூa௃TNCO{uZABC=60°,:.ZBAC=90°-60°=30°,ABC=—AB=—x6=3(cm),22VAABC"BfzVóS┐õᑮ4BDE,/.SABDE=SAABC,ZABE=ZCBD=180°-60°=110°,•▢ïðᑖḄ☢à=Sᡧ|ABE+SABDE-Sᡧ|BCD-SAABC=Sᡧ|ABE-Sᡧ|BCD_120/5?_120ç3?360360=11ᑍ-37r=9ø(cml).ᦑ§ᫀf9r.3ூ"#௃%⚪ὃ()õḄឋ¾ᡧ|Ḅ☢àáâ{uvu|30஺uᡠḄ{u`ì`Ḅ*íḄឋ¾g▢ïðᑖḄ☢àᡧ|Ḅ☢àḄùO⚪ḄᐵÌ.vஹ§⚪0(%ᜧ⚪ᐳ9⚪ᐳ78ᑖ§hᑏᦻüýஹþpᡈÿ
.19ஹ(1)᪆(2)2Gூ᪆௃(1)᪷ḄឋAB=CD,BC=AD,ZB=ZD,BE=DF,᪷ᐰḄᑨᓽ(2)!ABE#$%AHḄ&$'☢)ᓽ.ூ*௃(1)+,-•.,ABCD#$:.AB=CD,BC=AD,,♦,/EஹFᑖ1#BCஹADḄ2/$/.BE=-BC,DF=-AD,223BE=DF,

12ᙠAABE5ACDF2AB^CD⚪ὃABḄឋ5ᑨ$ᐰḄᑨ$Ḅឋ5ᑨCD/$EFᔠHᵨᳮJᳮ#K⚪ḄᐵM.20ஹV2-1-ூ᪆௃N⚪ᑖ᪆:

13ߟߟx2x+2x-1N⚪᪆:OP=——TTX-----------------ST+2
"xx+2xx-1x+2x+21x+2V*=XY][$OP=\Y=>/2-1.ὃ/-ᑖPḄᓄ^_.21ஹ6.58`ூ᪆௃N⚪ᑖ᪆-aA/bAE_LCDcE.ᙠRtAABE2$᪷dᦪAE,BE,ᙠR3ADE2$᪷dᦪDE,'᪷DB=DE-BEᓽ.N⚪᪆-aA/bAE_LCDcE.ᙠR3ABE2$ZABE=62°..•.AE=ABsin62<5=25x0.88=22`$AR1BE=ABcos62o=25x0.47=U.75`$ᙠRtAADE2$NADB=50°,.\DE=--------^=18-`$tan50°3ADB=DE-BEX6.58`.ᦑK[hijkᔣ᜜noᜧq6.58`.ὃ/-rḄhᵨ-ᚁtᚁu⚪.22ஹ(1)/M(1,2)\ᙠrvy=-x+4w$ᳮᵫ᪆(2)xḄyz{1ᡈ2(1)20—n+2Vok=---------.᪷y=kx+bxḄᜧᜧ$ᑮk>0,ᓽ------>0,জᡈঝdeᑖ72-3n-3[«-3>0[«-3<01\PᓽnḄ_.ூ*௃

14(1)Maᙠy=-x+4zᳮᵫ᝞ð,x=ly=-1+4=1^2,...M(1,2)aᙠy=-x+4z(2)y=-x+4ySḄs᪆u#y=-x+4+b.জM(L2)ᐵxḄ#Mi(1,-2),,Mi(1,-2)ᙠy=-x+4+bz:.-2=-l+4+b,.,.b=-1,ᓽḄ#1ঝM(1,2)ᐵyḄ#M(-1,2),2VNL(-1,2)ᙠy=-x+4+bz.♦.2=l+4+b,.♦.b=-2,ᓽḄ#2.ñzᡠòḄ#1ᡈ2(1),y=kx+bM(1,2),.2=lk+b,b=2-Ik.•y=kx+by=-x+4!Ḅ"ᙶ᪗#n,.y=kn+b=-n+4,kn+2-lk=-n+4,-n+2k=---------஻3•y=kx+b$xḄ%ᜧ'%ᜧ,ߟn+2.k>0,ᓽ------>0,஻3—n+2)0-n+2<0•জ஻3>0'ᡈঝ஻3VoatuvজõsatuvঝḄsx#2VnVl..nḄ)*,-2Vn^×ᦪ2ÚØÙÄᣚ^×ᦪ2ÚzḄᙶ᪗ᱯÜ^×ᦪḄឋøsᐗ^atuvù-

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