电气仪表工试题

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104+ᱏ-.஺027.DDZ-II/0〈ᘤ34567ὶḄ9:;᩽=Ḅ>ᵨ@ABCDE■G5ᐭIJ⊤ḄLMNOPQRSTUVW⁚YZ⌼ᡂ]⌕Ḅ_᡾஺028.bcde☢gᵨᩭhij☢dkl800mm,mhe$noᑖql1.2g/cin^D0.8g/cm3,st᪥vḄwtxo஺y0%ஹ50%ஹ100%DEᨬxj☢y34l100%ᡠV}ḄᨬᜧwtxolELt=1.2/1.0X800=960mmᨬj☢y34l0%ᡠV}Ḅᨬ#wtxolE1t=0.8/1.0X800=640mmᵫᵨt᪥vj☢Ḅ0ᓄlELtTt=960-640=320mmᯠᙠᨬxj☢vᵨt᪥vᑮ800-320=480mmᜐᩭ᪥஺ᐸwtxo34ḄV}ᐵYlEwtxo,mme%480064050800100029.ᵨᵯᏔhi¡ovlAB⌕¢£⊡¥?

105DEᵯᏔᵯ§Ḅᜧ#)ᐸ9£Ḅ¡oᨵᐵᐸ¡o-ᵯ§ᐵYª«@ᙠ¢£¡ol0࠷vᑖoḄ஺ᙠ®▭}ᵨ°ᵫ±ᵯᏔ¢£²☄ᙠ´M'ᑮᕜ¶᛻¡oḄ¸¹ᡠUh¡°Ḅ¢£¡oºᢝᙠ0C0%&ᙠ½¾¡o0¿Ꮤᵯ§ÀÁ&)£¡oÁ&)¢£¡o஺ᡠU᝞¢£¡oÃᵫ0ᓄ]ᯠÄÅhi஺lÆÇ◀É]Ê¢£¡o⊡¥஺aE1=6VRE2=3VbI=-3Aᓝ;.ÌẠgÎ⚪1.ÑPÌẠgÎ⚪(YCJJIA001-014)001.;ᑴ10111Úᣚᡂᓝᑴᦪ(ᑏ4ᣚÎÞß)àE10111=l*24+l*22+l*21+l*20=23D

106002.200ºCᣚÎᡂíî@ïðoC(ᑏ4ᣚÎñò)àEtF=(9/5t0+32)ºF=9/5*200+32=392ºF003.Ikgf/cm2ᣚÎᡂüýᓱPa
“lkgf/cm2=9.8N/(l/10000m2)=9.8*1(MPa004.1Ḅᵯ#R%&'(Uab=-15V:R=-9-3/-3=4Q005.ᙠRLC23ᵯ4&R=10Q,L=500uH,f=1000KHZ,ᦋ

107Yᙠ50KpaᜐZ⊤[%Ḅ\]^_.[%`]^_a[%bᵨ^_?Z⊤[%Ḅ\]^_=50-49.5=0.5KpaZ⊤[%`]^_=0.5/50*100%=1%Z⊤[%bᵨ^_=0.5/100*100%=0.5%007.MfgV<〈ᘤḄVj@40Kpa,ᨬᜧ%@20t/h,op⌕Yᨬᜧ%ᦋ@25t/h,ᑣ<〈ᘤḄVjsᦋ@GᵫuQ=K*AP&ᑣ(25/20)2=AP/40wP=62.5Kpaᡠy&<〈ᘤḄVjsᦋ@62.5Kpao008,ᵨf{|}ᐲ_N<〈ᘤV&R@1m,@0.9,@0.7,᝞ᵨ᪥&ḄR%aVjR%GR%Hl=1000*0.7=700mm

108VjR%H2=1000*0.9=900mm009.᝞ᡠ[&ᜧᘤḄᜧᦪK?+U03RRaUiᵫuᐭᜧᘤḄᵯg@&a`?u“ᙢ”&ᑣUi/R+U0/3R=0U0/Ui=-3ᓽ1=U0/Ui=3

109ᡠyᜧᘤḄᜧᦪ@3o010.ᨵfᙽ£R@2.53.V¥0-100KpaḄNO⊤&ḄQR᪗§ᨬ¨ᑖ@ªG«⊤Ḅᨬᜧ\]^_@Amax=2.5*(100-0)=2.5KpaZ⊤ḄQR᪗§Ḅᑖª%®s¨u¯ᐸᐕ²^_ᡠ]sḄ\]^_%&ᦑᐸQR᪗§ᨬ´ᑖ@(100-0)+2.5=40ªᡠy«ᙽNO⊤ḄQR᪗§ᨬsᑖ@40ª஺011.ᨵf{ᵯm_N<〈ᘤ&Vj@25Kpa,]sḄᨬᜧgV@50t/h,op⌕Y40t/hBµ¶&·᝞⊤¸¹º»¼Bµ¶½¾¿XᙠGᵫu⊤¸¹º»¼&ᑣwP1=K*APwPl=40/50*25=20Kpa

110]su40t/hḄᵯgÀÁ%@11=20/25*16+4=16.8mAᡠyµ¶%s¿Xᙠ16.8mAᜐ஺012.ÂÃ⁚▀ᐰ¹B&▀ÇNN_@4*100Kpa,ȨBÉÊḄËgV@100m3,·▀ḄgVÌᦪC@GCv%G'(Q=100m3/h,wP=4*100Kpa,r=lgf/cm3ᑣC=Q/AP/Y=100/4/1=50Cv=l.17C=1.17*50=58.5
:C@50,Cv%@58.5஺013.ÂÃ⁚▀ḄgVÌᦪC@50,?▀ÇÏN_@16*100Kpa,gÐR@0.81gf/cm3B-&ᡠ¼ÉÊḄᨬᜧgV
G:ÐÑgV:Q=C*AP/Y=50*16/0.81=222(m3/h)VgV:G=C*AP*y=50*16*0.81=180(t/h)

111014,ᨵÔÕÃ⁚▀&ᐸ´ÃRl=R2=30,ÖfÕ▀ᨬᜧgVQlmax=100m3/h,Ö×ÕᨬᜧgVQ2max=4m3/h,ØᵨᑖjÃ⁚B&´Ã´ÙGÖfÕ▀ᨬ¨gV@=Qlmin=100/30=3.3(m3/h)Ö×Õ▀ᨬ¨gV@=Q2min=4/30=0.134(m3/h)ᡠyR=Qlmax/Q2max=100/0.134=740ᓽ´Ã´Ù740oᓝÜ.ÝÞ⚪1.à3ÝÞ⚪(YCZJIA001-010)001.äᵨ½¾CDᘤåDCSèéêëìíᜐ]fEïðRñ[ò4᪥&'(êëìíᜐðR@25࠷,·⌕᪥100࠷Bs〈ᵯô½¾G(t(25,0࠷)=1.495mV,t(100,0࠷=6.319mV)
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:ᵫU⊤KLMNOᑣAQ=KAPWPl=(40/50)2X25=16KPaU40t/hḄᵯX*11=20/25X16+4=16.8mAoᡠYFGXRSᙠ16.8mAᜐ஺007.[\⁚▀ᐰL▀`a4X100KPa,bcdeḄf!100m3,H▀Ḅ!gᦪC&'(CVX&'(i*jkQ=100m3/h,AP=4X100Kpa,r=lgf/cm3ᑣC=Q/VAP/r=100/4/1=50CV=1.17C=1.17X50=58.5008.[\⁚▀Ḅ!gᦪC50,$▀`a16X100KPa,0.81gf/cm3,ᡠOdeḄᨬᜧ!@&'()*l!*Q=C/JWP/r=50X

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