资源描述:
《简单交互效应和简单简单效应分析》由会员上传分享,免费在线阅读,更多相关内容在行业资料-天天文库。
1、between-subjectdesignifthree-wayinteractionissignifcant,computethesimpleinteractioneffect.**********simpleinteractioneffect********************manovatotalbygender(1,2)depart(1,2)grade(1,3)/design=gender*gradewithindepart(1)gender*gradewithindepart(2).ifthesimpleinteraction
2、effectisnotsignifcant,computethesimpleeffect.如果简单交互效应不显著,那么就计算***************simpleeffect***********************manovatotalbygender(1,2)depart(1,2)grade(1,3)/design=gradewithindepart(1)genderwithindepart(1).**************multiplecomparisons*****************manovatotalbygen
3、der(1,2)depart(1,2)grade(1,3)/contrast(grade)=special(1111-1010-1)/design=gradewithindepart(1).manovatotalbygender(1,2)depart(1,2)grade(1,3)/contrast(grade)=special(1111-1001-1)/design=gradewithindepart(1).ifthesimpleinteractionissignificant,computethesimplesimpleeffect.简单
4、交互效应显著,计算简单简单效应。***********simplesimpleeffect**********************manovatotalbygender(1,2)depart(1,2)grade(1,3)/design=gradewithingender(1)withindepart(2)gradewithingender(2)withindepart(2).******************multiplecomparisons*******************manovatotalbygender(1,2)de
5、part(1,2)grade(1,3)/contrast(grade)=special(1111-1010-1)/design=gradewithingender(2)withindepart(2).manovatotalbygender(1,2)depart(1,2)grade(1,3)/contrast(grade)=special(1111-1001-1)/design=gradewithingender(2)withindepart(2).Thewithin-subjectdesign(组内设计)issimilartothebetw
6、een-subjectdesign.Youcanchangethe“design”into“wsdesign(组内)”.Andthecommandcontrastisnotadaptomultiplecomparisonsinwithin–subjectdesign.mixed-designifthree-wayinterationeffectissignificant,computethesimpleinterationeffect.(如果三项交互效应显著,计算简单交互效应)*************simpleinteractionef
7、fect*************manovaa1b1a1b2a1b3a2b1a2b2a2b3byfreq(1,3)/wsfactors=a(2)b(3)/wsdesign=a*b/design=mwithin(混合设计)freq(1)mwithinfreq(2)mwithinfreq(3).ifsimpleinteractioneffectissignificant,computethesimplesimpleeffect.************simplesimpleeffect******************manovaa1b1
8、a1b2a1b3a2b1a2b2a2b3byfreq(1,3)/wsfactors=a(2)b(3)/wsdesign=awithinb(1)awithinb(2)awithin