Statistics for Managers Using Microsoft Excel 7E - Levine - SM levine_smume7_ism_07

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1、SolutionstoEnd-of-SectionandChapterReviewProblems281CHAPTER77.1PHstatoutput:CommonDataMean100StandardDeviation2ProbabilityforaRangeProbabilityforX<=FromXValue95XValue95ToXValue97.5ZValue-2.5ZValuefor95-2.5P(X<=95)0.0062097ZValuefor97.5-1.25P(X<=95)0.0062ProbabilityforX>P(X

2、<=97.5)0.1056XValue102.2P(95<=X<=97.5)0.0994ZValue1.1P(X>102.2)0.1357FindXandZGivenCum.Pctage.CumulativePercentage35.00%ProbabilityforX<95orX>102.2ZValue-0.38532P(X<95orX>102.2)0.1419XValue99.22936(a)P(<95)=P(Z<–2.50)=0.0062(b)P(95<<97.5)=P(–2.50

3、994(c)P(>102.2)=P(Z>1.10)=1.0–0.8643=0.1357(d)P(>A)=P(Z>–0.39)=0.65=100–0.39()=99.227.2PHStatoutput:CommonDataMean50StandardDeviation0.5ProbabilityforaRangeProbabilityforX<=FromXValue47XValue47ToXValue49.5ZValue-6ZValuefor47-6P(X<=47)9.866E-10ZValuefor49.5-1P(X<=47)0.0000P

4、robabilityforX>P(X<=49.5)0.1587XValue51.5P(47<=X<=49.5)0.1587ZValue3P(X>51.5)0.0013FindXandZGivenCum.Pctage.CumulativePercentage65.00%ProbabilityforX<47orX>51.5ZValue0.38532P(X<47orX>51.5)0.0013XValue50.19266ProbabilityforX>XValue51.1ZValue2.2P(X>51.1)0.0139(a)P(<47)=P(Z<–

5、6.00)=virtuallyzero(b)P(47<<49.5)=P(–6.0051.1)=P(Z>2.20)=1.0–0.9861=0.0139(d)P(>A)=P(Z>0.39)=0.35=50+0.39(0.5)=50.195Copyright©2014PearsonEducation,Inc.SolutionstoEnd-of-SectionandChapterReviewProblems2817.3(a)Forsamplesof25travelexpensevo

6、uchersforauniversityinanacademicyear,thesamplingdistributionofsamplemeansisthedistributionofmeansfromallpossiblesamplesof25vouchersthatcouldoccur.(b)Forsamplesof25absenteerecordsin2012foremployeesofalargemanufacturingcompany,thesamplingdistributionofsamplemeansisthedistrib

7、utionofmeansfromallpossiblesamplesof25recordsthatcouldoccur.(c)Forsamplesof25salesofunleadedgasolineatservicestationslocatedinaparticularstate,thesamplingdistributionofsamplemeansisthedistributionofmeansfromallpossiblesamplesof25salesthatcouldoccur.7.4(a)SamplingDistributi

8、onoftheMeanforn=2(withoutreplacement)SampleNumberOutcomesSampleMeans11,3=221,6=3.531,7=44