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时间:2021-12-30
《Statistics for Managers Using Microsoft Excel 7E - Levine - SM levine_smume7_ism_06》由会员上传分享,免费在线阅读,更多相关内容在学术论文-天天文库。
1、SolutionstoEnd-of-SectionandChapterReviewProblems261CHAPTER66.1PHStatoutput:NormalProbabilitiesCommonDataMean0StandardDeviation1ProbabilityforaRangeProbabilityforX<=FromXValue1.57XValue1.57ToXValue1.84ZValue1.57ZValuefor1.571.57P(X<=1.57)0.9417924ZValuefor1.841.84P(X<
2、=1.57)0.9418ProbabilityforX>P(X<=1.84)0.9671XValue1.84P(1.57<=X<=1.84)0.0253ZValue1.84P(X>1.84)0.0329FindXandZGivenCum.Pctage.CumulativePercentage95.00%ProbabilityforX<1.57orX>1.84ZValue1.644854P(X<1.57orX>1.84)0.9747XValue1.644854(a)P(Z<1.57)=0.9418(b)P(Z>1.84)=1–0.9
3、671=0.0329(c)P(1.571.84)=0.9418+(1–0.9671)=0.97476.2PHStatoutput:NormalProbabilitiesCommonDataMean0StandardDeviation1ProbabilityforaRangeProbabilityforX<=FromXValue1.57XValue-1.57ToXValue1.84ZValue-1.57ZValuefor1.571.57P(X
4、<=-1.57)0.0582076ZValuefor1.841.84P(X<=1.57)0.9418ProbabilityforX>P(X<=1.84)0.9671XValue1.84P(1.57<=X<=1.84)0.0253ZValue1.84P(X>1.84)0.0329FindXandZGivenCum.Pctage.CumulativePercentage84.13%ProbabilityforX<-1.57orX>1.84ZValue0.999815P(X<-1.57orX>1.84)0.0911XValue0.999
5、815(a)P(–1.571.84)=0.0582+0.0329=0.0911Copyright©2014PearsonEducation,Inc.SolutionstoEnd-of-SectionandChapterReviewProblems261cont.(c)IfP(Z>A)=0.025,P(Z6、eareaiscapturedbetween–A=–1.00andA=+1.00.6.3(a)PartialPHStatoutput:NormalProbabilitiesCommonDataMean0StandardDeviation1ProbabilityforaRangeProbabilityforX<=FromXValue1.57XValue1.08ToXValue1.84ZValue1.08ZValuefor1.571.57P(X<=1.08)0.8599289ZValuefor1.841.84P(X<=1.57)0.97、418ProbabilityforX>P(X<=1.84)0.9671XValue-0.21P(1.57<=X<=1.84)0.0253ZValue-0.21P(X>-0.21)0.5832FindXandZGivenCum.Pctage.CumulativePercentage84.13%ProbabilityforX<1.08orX>-0.21ZValue0.999815P(X<1.08orX>-0.21)1.4431XValue0.999815P(Z<1.08)=0.8599(b)P(Z>–0.21)=1.0–0.4168=8、0.5832(c)PartialPHStatoutput:ProbabilityforX<-0.21orX>0P(X<-0.21orX>0)0.9168P(Z<–0.21)+P(Z>0)=0.4168+0.5=0.9168(d)PartialPHS
6、eareaiscapturedbetween–A=–1.00andA=+1.00.6.3(a)PartialPHStatoutput:NormalProbabilitiesCommonDataMean0StandardDeviation1ProbabilityforaRangeProbabilityforX<=FromXValue1.57XValue1.08ToXValue1.84ZValue1.08ZValuefor1.571.57P(X<=1.08)0.8599289ZValuefor1.841.84P(X<=1.57)0.9
7、418ProbabilityforX>P(X<=1.84)0.9671XValue-0.21P(1.57<=X<=1.84)0.0253ZValue-0.21P(X>-0.21)0.5832FindXandZGivenCum.Pctage.CumulativePercentage84.13%ProbabilityforX<1.08orX>-0.21ZValue0.999815P(X<1.08orX>-0.21)1.4431XValue0.999815P(Z<1.08)=0.8599(b)P(Z>–0.21)=1.0–0.4168=
8、0.5832(c)PartialPHStatoutput:ProbabilityforX<-0.21orX>0P(X<-0.21orX>0)0.9168P(Z<–0.21)+P(Z>0)=0.4168+0.5=0.9168(d)PartialPHS
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