信号与系统（第二版）英文版 (Simon Haykin 著) 电子工业出版社 课后答案

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1、课后答案网：www.hackshp.cn若侵犯了您的版权利益，敬请来信告知！课后答案网您最真诚的朋友www.hackshp.cn网团队竭诚为学生服务，免费提供各门课后答案，不用积分，甚至不用注册，旨在为广大学生提供自主学习的平台！课后答案网：www.hackshp.cn视频教程网：www.efanjy.comPPT课件网：www.ppthouse.comCHAPTER11.1to1.41-partoftext1.42(a)Periodic:Fundamentalperiod=0.5s(b)Nonperiodic(c)P

2、eriodicFundamentalperiod=3s(d)PeriodicFundamentalperiod=2samples(e)Nonperiodic(f)Periodic:Fundamentalperiod=10samples(g)Nonperiodic(h)Nonperiodic(i)Periodic:Fundamentalperiod=1sample课后答案网2æöæöpl.43yt()=3cos200t+---èøèø62www.hackshp.cnp=9cosæö200t+---èø69æöp=---c

3、os400t+---12èø39(a)DCcomponent=---29æöp(b)Sinusoidalcomponent=---cos400t+---2èø39Amplitude=---21200Fundamentalfrequency=---------Hzp1.44TheRMSvalueofsinusoidalx(t)isA¤2.Hence,theaveragepowerofx(t)ina1-ohm22resistoris()A¤2=A/2.1.45LetNdenotethefundamentalperiodof

4、x[N].whichisdefinedby2pN=------WTheaveragepowerofx[n]isthereforeN-112P=----åx[]nNn=0N-1122æö2pn=----åAcos----------+fNèøNn=02N-1A2æö2pn=------åcos----------+fNèøNn=01.46Theenergyoftheraisedcosinepulseis课后答案网pw¤12E=ò---()cos()wt+1td–pw¤41pw¤2www.hackshp.cn=---ò()c

5、os()wt+2cos()wt+1td201pw¤æö11=---òèø---cos()2wt++---2cos()wt+1td20221---æö3---æö---p-==3p¤4w2èø2èøw1.47Thesignalx(t)iseven;itstotalenergyistherefore52E=2òx()ttd024252=21ò()dt+25ò()–ttd041543=2[]t+2–---()5–tt=03t=4226==8+---------331.48(a)Thedifferentiatoroutputi

6、sì1for–5<

7、02025t31.51x(10t-5)1.0t00.10.50.91.01.52(a)x(t)1t-1123-1y(t-1)t-1123-1x(t)y(t-1)11t课后答案网-123-1www.hackshp.cn41.52(b)x(t+1)x(t-1)11t-11234-1y(-t)y(-t)1t-2-11234-1x(t-1)y(-t)1t-2-11234-11.52(c)-2t课后答案网-1123www.hackshp.cn-1-2-1t1234x(t+1)y(t-2)-2-11234t51.52(d)x(t)

8、1t-3-2-1123-1y(1/2t+1)6-5-4-3-2-1t1246-1.0x(t-1)y(-t)1t-3-2-1123-11.52(e)x(t)1-4-3-2-1t123课后答案网-1y(2-t)www.hackshp.cn123t-4-3-2-1x(t)y(2-t)-1t123-161.52(f)x(t)1t-2-11