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时间:2018-01-15
《第二章 轴向拉压应力与材料的力学性能》由会员上传分享,免费在线阅读,更多相关内容在应用文档-天天文库。
1、第二章轴向拉压应力与材料的力学性能题号页码2-3.........................................................................................................................................................12-5............................................................................
2、.............................................................................22-7.........................................................................................................................................................22-9...................
3、......................................................................................................................................32-10......................................................................................................................
4、.................................32-15.......................................................................................................................................................42-16...............................................................
5、........................................................................................52-18.......................................................................................................................................................62-19........
6、...............................................................................................................................................72-21.............................................................................................................
7、..........................................72-22.......................................................................................................................................................8(也可通过左侧题号书签直接查找题目与解)2-3图示轴向受拉等截面杆,横截面面积A=500mm2,载荷F=50kN。试
8、求图示斜截面m-m上的正应力与切应力,以及杆内的最大正应力与最大切应力。9解:该拉杆横截面上的正应力为题2-3图99σ=F=50×103N=1.00×108Pa=100MPa9A500×10-6m2斜截面m-m的方位角α=−50o,故有ασ=σcos2α=100MPa⋅cos2(−50o)=41.3MPaτ=σsin2α=50MPa⋅sin(−100o)=−49.2MPaα2杆内的最大正应力与
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