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大小:1.87 MB
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时间:2021-04-16
《最新人教版高中化学选修五(课件)4.1-油脂-(共52张PPT)教学讲义PPT.ppt》由会员上传分享,免费在线阅读,更多相关内容在教育资源-天天文库。
1、人教版高中化学选修五(课件)4.1-油脂-(共52张PPT)油脂第一节一.油脂的组成和结构是由多种高级脂肪酸和甘油反应生成的酯,属于酯类。(俗称:甘油三酯)C、H、O油——常温呈液态脂肪——常温呈固态1.定义:3.组成:2.分类:脂肪(动物油脂固态)油(植物油脂液态)二、油脂的物理性质1.密度比水的密度小,为0.9~0.95g/cm3;2.有明显的油腻感;3.不溶于水,易溶于有机溶剂,是一种良好的有机溶剂;4.当高级脂肪酸中烯烃基多时大多为液态的油;当高级脂肪酸中烷烃基多时,大多为固态的脂肪。家里做汤放的油为什么浮在水面?衣服上的油渍为什么用水洗不掉,而用汽油可洗干净?讨论:三
2、.油脂的化学性质思考:1.油脂属于酯类,应具有什么性质?2.当分子中含有不饱和键时,油脂还应当具有什么性质?如何检验?3.若想将油变为脂肪仍作食物,应与什么物质通过什么反应得到?1、油脂的水解酸性条件下:C17H35COOCH+3H2O3C17H35COOH+CHOHCH2OHCH2OHC17H35COOCH2C17H35COOCH2H2SO4(硬脂酸甘油酯)(硬脂酸)(甘油)硬脂酸甘油酯+水硬脂酸+甘油可逆!C17H35COOCH+3NaOH3C17H35COONa+CHOHCH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35C
3、OOCH2C17H35COOCH2碱性条件下:皂化反应油脂在碱性条件下的水解反应肥皂的主要成分钠肥皂(硬肥皂)与钾肥皂(软肥皂)CH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHCH2OHC17H35COOCH+3N
4、aOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHCH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35CO
5、OCH2CH2OHC17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2CH2OHC17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOH
6、C17H35COOCH2CH2OHC17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2CH2OHC17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH+3N
7、aOH3C17H35COONa+CHOHC17H35COOCH2CH2OHC17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHCH2OHC17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3C17H35COONa+CHOHC17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH2C17H35COOCH+3NaOH3
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