数值分析c++高斯赛德尔迭代.docx

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1、[2]高斯赛德尔迭代题目:3*x1-2*x3=12*x2+x3=0-2*x1+x2+3*x3=2[3]程序源代码:#include"stdio.h"#include"math.h"floata[3][3],b[3],x0[3],x[3];voidinput(){inti,j;printf("~~~~~~~~~~~~~~~~~~welcometocomein~~~~~~~~~~~~~~~~~~~");printf("inthesameline,pleaseinputmatrixa[3][3]:");for(i=0;i<3;i++)for(j=0;j<3

2、;j++)scanf("%f",&a[i][j]);printf("inthesameline,pleaseinputmatrixb[3]");for(i=0;i<3;i++)scanf("%f",&b[i]);printf("inthesamelinepleaseinputprimitivevaluex0[3]");for(i=0;i<3;i++)scanf("%f",&x0[i]);}main(){floate0=0.0001;intn=20,k=1,i,j;floatpre[3];floatmax=pre[0];input();printf("

3、theresultareasfollows:");do{for(i=0;i<3;i++){floatt=0;for(j=0;j<3;j++)if(j!=i)t+=a[i][j]*x0[j];x[i]=(b[i]-t)/a[i][i];pre[i]=fabs(x[i]-x0[i]);x0[i]=x[i];}printf("executetime:%d",k);for(i=0;i<3;i++)printf("%f",x[i]);printf("");for(j=1;j<3;j++)if(max

4、(max>e0&&kn)printf("failure!pleasecheckyourworkorsetandtryagain");}[4]对应题目运行结果：[1]高斯赛德尔流程图：开始输入x0[3],a[3][3],b[3],e0,nfailurei结束k0->maxK=1,20,1i,j=1,3,1Bi-(j=1i-1aijxj-j=i+1naijxj)/aii->xixi->txi-t<=maxYxi-t->maxmax=