周忍华层次分析作业.doc

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1、R=[95.329.4331.147.2;96.326.9332.941.&95.924.7329.450.5;97.328.4356.667.7;98.128.8365.740•&97.025.4332.441.2;97.225.5333.541.9]95.300029.40()0331.100047.200096.300026.9000332.900041.800095.900024.7000329.400050.500097.300028.40()0356.600067.700098.100028.8000365.700040

2、.800097.000025.4000332.400041.200097.200025.5000333.500041.9000R=[95.329.4331.147.2;96.326.9332.941.8;95.924.7329.450.5;97.328.4356.667.7;98.128.8365.740.8;97.025.4332.441.2;97.225.5333.541.9];Rlmax=max(R);Rlmin=min(R);Rl=ones(7r4);forj=l:4Rl(:zj)=R(:,j)/Rlmax(l,j);end

3、R1(:z4)=Rlmin(lz4)./R(4)R1=0.97151.00000.90540.86440.98170.91500.91030.97610.97760.84010.90070.80790.99180.96600.97510.60271.00000.97961.00001.00000.98880.86390.90890.99030.99080.86730.91190.9737Rlmax=max(Rl);Rlmin=min(Rl);r=Rlmax-Rlmin;w=r./sum(r)0.04170.23340.14490.5

4、801四、模型的建立4.1构造评价矩阵95.329.4331.147.296.326.9332.941.895.924.7329.450.597.328.4356.667.798.128.8365.740.897.025.4332.441.297.225.5333.541.94.2标准化处理利用矩阵线性比例变换法得出:R=0.97151.00000.90540.86440.98170.91500.91030.97610.97760.84010.90070.80790.99180.96600.97510.60271.00000.979

5、61.00001.00000.98880.86390.90890.99030.99080.86730.91190.97374・・3指标权重的求解利用matlab软件编程得岀标准差无量纲化的均方差权重为:w二[0.04170.23340.14490.5801]4.31综合指标权重的求解根据公式：（冋2・・・，m）令k、=0.4,k2=0.6